JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

Let

f(x)=2 \tan ^{-1} x+\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)

. Then,

View answer and explanation

Correct option: D

All the above

Option D (All the above) is correct because the polynomial

f(x) = x^3 - 5x^2 + 2x + 6

satisfies all the given conditions:

f(0)+f(2)=f(1)

f(0)+f(3)=0

, and

f(1)+f(3)=f(2)

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