JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

\left[\tan ^{-1} x\right]^2-2\left[\tan ^{-1} x\right]+1 \leq 0

, where

[x]

denotes greatest interger

\leq x

, iff

x \in[\tan k, \tan 2)

then evaluate

k

View answer and explanation

Correct option: A

Option A (1) is correct because solving the inequality leads to the condition that x belongs to the interval [tan 1, tan 2), thus k = 1.

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