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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Application +4 | -1
If x=f(t)x=f(t) and y=g(t)y=g(t), then d2ydx2\frac{d^2 y}{d x^2} is equal to
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Correct option: B
g′′(t)f′(t)−g′(t)f′′(t)(f′(t))3\frac{g^{\prime \prime}(t) f^{\prime}(t)-g^{\prime}(t) f^{\prime \prime}(t)}{\left(f^{\prime}(t)\right)^3}
Option B (g′′(t)f′(t)−g′(t)f′′(t)(f′(t))3\frac{g^{\prime \prime}(t) f^{\prime}(t)-g^{\prime}(t) f^{\prime \prime}(t)}{\left(f^{\prime}(t)\right)^3}) is correct because it is derived by applying the chain rule and quotient rule to find the second derivative of y with respect to x.

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