JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The solution set of the inequation

0 < \left| {3x + 1} \right| < \frac{1}{3}\;,

View answer and explanation

Correct option: C

\left( { - 4/9\;, - 2/9} \right) - \left\{ { - 1/3} \right\}

The correct answer is C (

\left( { - 4/9\;, - 2/9} \right) - \left\{ { - 1/3} \right\}

) because it represents the interval where the absolute value of

3x+1

is greater than 0 but less than 1/3, excluding the point where

3x+1 = 0

More Questions from QUADRATIC EQUATIONS

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{x^2} + 4ax + 2 > 0

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a

f\left( x \right) = a{x^2} + bx + c\;

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