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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
Suppose for a differentiable function h,h(0)=0h, h(0)=0, h(1)=1h(1)=1 and h′(0)=h′(1)=2h^{\prime}(0)=h^{\prime}(1)=2. If g(x)=h(ex)eh(x)g(x)=h\left(e^x\right) e^{h(x)}, then g′(0)g^{\prime}(0) is equal to:
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Correct option: D
4
Option D (4) is correct because it is the value of the derivative of g(x) evaluated at x=0, calculated using the chain rule and product rule.

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