JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y = {\log _a}x + {\log _x}a + {\log _x}x + {\log _a}a

, then

\frac{{dy}}{{dx}}

is equal to

View answer and explanation

Correct option: D

\frac{1}{{x\log a}} - \frac{{\log a}}{{x{{\left( {\log x} \right)}^2}}}

Option D is correct because the derivative is found using logarithm properties and the chain rule.

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