JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

Let

S

denote the set of all values of

S

for which the equation

2{x^2} - 2\left( {2a + 1} \right)x + a\left( {a + 1} \right) = 0

has one root less than

a

and other root greater than

a

, then

S

equals

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the correct range for 'a' is a < -1 or a > 0, which is not represented by any of the given options.

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

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