JEE CHEMISTRY MCQ: SOLID STATE

1 Hard

1 of 1

Analyzing +4 | -1

A compound of formula

{A_2}{B_3}

has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms?

View answer and explanation

Correct option: C

hcp lattice-

B

\frac{1}{3}

tetrahedral voids-

A

The correct answer is C (hcp lattice-

B

\frac{1}{3}

tetrahedral voids-

A

) because in an hcp lattice, the number of tetrahedral voids is twice the number of atoms, and the formula

{A_2}{B_3}

implies that A occupies 1/3 of the tetrahedral voids.

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