Question

If $y=f\left(\frac{2 x-1}{x^2+1}\right)$ and $f^{\prime}(x)=\sin x^2$, then $\frac{d y}{d x}=$

Accepted Answer

$\frac{-2 x^2+2 x+2}{\left(x^2+1\right)^2} \sin \left(\frac{2 x-1}{x^2+1}\right)^2$

Answer

$\frac{6 x^2-2 x+2}{\left(x^2+1\right)^2} \sin \left(\frac{2 x-1}{x^2+1}\right)^2$

Answer

$\frac{6 \mathrm{x}^2-2 \mathrm{x}+2}{\left(\mathrm{x}^2+1\right)^2} \sin ^2\left(\frac{2 \mathrm{x}-1}{\mathrm{x}^2+1}\right)$

Answer

$\frac{-2 x^2+2 x+2}{\left(x^2+1\right)^2} \sin ^2\left(\frac{2 x-1}{x^2+1}\right)$

JEE MATHEMATICS MCQ: DIFFERENTIATION

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