JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

If the roots of

\left( {{a^2} + {b^2}} \right){x^2} - 2\left( {bc + ad} \right)x + {c^2} + {d^2} = 0

are equal, then

View answer and explanation

Correct option: A

\frac{a}{b} = \frac{c}{d}

Option A (

\frac{a}{b} = \frac{c}{d}

) is correct because for the roots to be equal, the discriminant must be zero, which simplifies to ad = bc, hence a/b = c/d.

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