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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Application +4 | -1
26 If α=0.98\alpha=0.98 and current though emitter ie=20 mA\mathrm{i}_{\mathrm{e}}=20 \mathrm{~mA}, the value of β\beta is -
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Correct option: B
49
Option B (49) is correct because it is the value of β calculated using the given value of α and the relation between α and β.

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