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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1
(a2−3a+2)x2+(a2−5a+6)x+a−2=r\left( {{a^2} - 3a + 2} \right){x^2} + \left( {{a^2} - 5a + 6} \right)x + a - 2 = r for three distinct values of xx for some r∈R,   ifr \in R,\;\,\mathrm{if} a+ra + r is equal to
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Correct option: B
2
Option B (2) is correct because when a = 2, the equation holds true for three distinct values of x, and r = 0, thus a + r = 2.

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