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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Application +4 | -1
Let f(⋅)f(\cdot) and g(⋅)g(\cdot) be differentiable functions on (−∞(-\infty, ∞)\infty) and let f′(⋅)f^{\prime}(\cdot) and g′(⋅)g^{\prime}(\cdot) denote derivatives of f(⋅)f(\cdot) and g(⋅)g(\cdot) respectively. If f(0)=12,g(0)=13,f′(0)=1f(0)=\frac{1}{2}, g(0)=\frac{1}{3}, f^{\prime}(0)=1 and g′(0)=2g^{\prime}(0)=2, then the value of lim⁡x→02f(2x2+3x)−13g(x)−1\lim \limits_{{x \rightarrow 0}} \frac{2 f\left(2 x^2+3 x\right)-1}{3 g(x)-1} is
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Correct option: A
1
Option A (1) is correct because the limit is evaluated using L'Hopital's rule and the given derivative values.

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