The quadratic equation whose roots are ${\sec ^2}\,\,\theta $ and ${\rm{cose}}{{\rm{c}}^2}\,\,\;\theta $ can be

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The quadratic equation whose roots are

{\sec ^2}\,\,\theta

and

\mathrm{cose}{\mathrm{c}^2}\,\,\;\theta

can be

View answer and explanation

Correct option: C

{x^2} - 4x + 4 = 0

Option C (

{x^2} - 4x + 4 = 0

) is correct because it is a quadratic equation with roots

{\sec ^2}\,{\theta }

and

\mathrm{cose}{\mathrm{c}^2}\,\;{\theta }

and has a discriminant that is greater than or equal to 4.

Practice All Chapter MCQs →

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\alpha ,\beta

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\alpha ,\;\beta

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{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

\;a \ne 0,

9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)