JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

Let

f\left( x \right) = {\left( {x - 7} \right)^2}{\left( {x - 2} \right)^7},x \in \left[ {2,7} \right].

The value of

\theta \in \left( {2,7} \right)

such that

f'\left( \theta \right) = 0

is equal to

View answer and explanation

Correct option: B

\frac{{53}}{9}

Option B (

\frac{{53}}{9}

) is correct because it is the value of theta that makes the derivative of the function equal to zero within the given interval.

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