JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

The derivative of

{\tan ^{ - 1}}\left( {\frac{{2x}}{{1 - {x^2}}}} \right)

with respect to

{\cos ^{ - 1}}\sqrt {1 - {x^2}}

View answer and explanation

Correct option: D

\frac{{2\sqrt {1 - {x^2}} }}{{1 + {x^2}}}

Option D (

\frac{{2\sqrt {1 - {x^2}} }}{{1 + {x^2}}}

) is correct because it results from correctly differentiating both functions and then dividing the derivatives.

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