JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

f\left( x \right) = {\log _{{x^2}}}\left( {lo{g_e}x} \right),

then

f'\left( x \right)

x = e

View answer and explanation

Correct option: C

\frac{1}{{2e}}

Option C (

\frac{1}{{2e}}

) is correct because after differentiating and substituting x=e, the result is

\frac{1}{{2e}}

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