JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Analyzing +4 | -1

For the equation

{\cos ^{ - 1}}x + {\cos ^{ - 1}}2x + \pi = 0

, then the number of real solutions is

View answer and explanation

Correct option: C

Option C (0) is correct because the equation has no real solutions, as the value of x obtained does not satisfy the original equation.

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x

{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)