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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Let ff be any function defined on RR and let it satisfy the condition ∣f(x)−f(y)∣ ≤ ∣(x−y)2∣,  ∀  x,y∈R\left| {f(x) - f(y)\left| {{\mkern 1mu} \le {\mkern 1mu} } \right|{{\left( {x - y} \right)}^2}} \right|,{\mkern 1mu} {\mkern 1mu} \forall \;x,y \in R
If f(0)=1f(0) = 1, then
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Correct option: D
f(x)>0,  ∀x∈Rf(x) > 0,\,\,\forall x \in R
Option D is correct. Given the condition on f(x)f(x), it can be shown that f(x)f(x) is a constant function, and since f(0)=1f(0) = 1, f(x)=1f(x) = 1 for all xx, thus f(x)>0f(x) > 0 for all x∈Rx \in R.

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