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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
Let f(x)=log⁡sin⁡x2,0<x<π/2f(x)=\log \sin x^2, 0 < x < \pi / 2 then f′′(π/2)f^{\prime \prime}(\sqrt{\pi} / 2) is equal to
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Correct option: C
2(1−π)2(1-\pi)
Option C (2(1−π)2(1-\pi)) is correct because it is the value of the second derivative of the given function evaluated at x=π/2x = \sqrt{\pi}/2.

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