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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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Showing 151-180 of 384 questions

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151 Medium
151 of 384
Application +4 | -1
Given X=(Gh/c3)1/2X = {\left( {Gh/{c^3}} \right)^{1/2}} , where G,h and c are gravitational constant, Planck’s constant and the velocity of light respectively. Dimensions of X are the same as those of
View answer and explanation
Correct option: C
Length
Option C (Length) is correct because dimensional analysis of the given expression results in the dimensions of length.
152 Medium
152 of 384
Remembering +4 | -1
Dimensional formula for force is
View answer and explanation
Correct option: B
[MLT−2]\left[ {\mathrm{ML}{\mathrm{T}^{ - 2}}} \right]
Option B ([MLT−2][\mathrm{ML}{\mathrm{T}^{ - 2}}]) is correct because force is mass times acceleration, and the dimensional formula for acceleration is [LT-2].
153 Medium
153 of 384
Understanding +4 | -1
The unit of self-inductance is
View answer and explanation
Correct option: C
Ohm second
Option C (Ohm second) is correct because self-inductance (L) is related to voltage (V) and rate of change of current (dI/dt) by V = L(dI/dt), so L = V/(dI/dt).
154 Medium
154 of 384
Remembering +4 | -1
What is the dimension of Luminous flux?
View answer and explanation
Correct option: A
[cd1][\mathrm{cd^1}]
Option A ([cd1][\mathrm{cd^1}]) is correct because Luminous flux is measured in lumens, and lumens are defined in terms of candela (cd), the SI unit of luminous intensity.
155 Medium
155 of 384
Remembering +4 | -1
The dimensions of torque are
View answer and explanation
Correct option: B
[ML2 T−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]
Option B ([ML²T⁻²]) is correct because torque is the product of force and distance, so its dimensions are [MLT⁻²][L] = [ML²T⁻²].
156 Hard
156 of 384
Application +4 | -1
In finding out refractive index of glass slab the following observations were made through travelling microscope 50 vernier scale division = 49 MSD; 20 divisions on main scale in each cm\mathrm{cm}
For mark on paper
MSR=8.45 cm,VC=26\mathrm{MSR}=8.45 \mathrm{~cm}, \mathrm{VC}=26
For mark on paper seen through slab
MSR=7.12 cm,VC=41\mathrm{MSR}=7.12 \mathrm{~cm}, \mathrm{VC}=41
For powder particle on the top surface of the glass slab
MSR⁡=4.05 cm,VC=1\operatorname{MSR}=4.05 \mathrm{~cm}, \mathrm{VC}=1
(MSR=(\mathrm{MSR}= Main Scale Reading, VC=\mathrm{VC}= Vernier Coincidence)
Refractive index of the glass slab is:
View answer and explanation
Correct option: A
1.42
Option A (1.42) is correct because the refractive index is calculated by dividing the real depth by the apparent depth.
157 Medium
157 of 384
Analyzing +4 | -1
In the context of accuracy of measurement and significant figures in expressing results of experiment, which of the following is/are correct
(1) Out of the two measurements 50.14 cm and 0.00025 ampere, the first one has greater accuracy
(2) If one travels 478 km by rail and 397 m by road, the total distance travelled is 478 km
View answer and explanation
Correct option: C
Both are correct
Option C (Both are correct) is correct because both statements regarding accuracy and significant figures are valid.
158 Medium
158 of 384
Understanding +4 | -1
The number of significant figures in all the given numbers 25.12, 2009, 4.156 and 1.217×10−41.217 \times {10^{ - 4}} is
View answer and explanation
Correct option: D
4
Option D (4) is correct because each of the given numbers has four significant figures.
159 Medium
159 of 384
Understanding +4 | -1
Which of the following is/are the units of strength of magnetic field at a point?
View answer and explanation
Correct option: C
NA−1  m−1\mathrm{N}{\mathrm{A}^{ - 1}}\mathrm{\;}{\mathrm{m}^{ - 1}}
Option C (NA−1  m−1\mathrm{N}{\mathrm{A}^{ - 1}}\mathrm{\;}{\mathrm{m}^{ - 1}}) is correct because the magnetic force on a current-carrying wire is F = BIL, so B = F/(IL), and the units are N/(A*m).
160 Easy
160 of 384
Application +4 | -1
The dimensional formula of coefficient of viscosity is (F=ηAΔVΔx)\left( {F = \eta A\frac{{\Delta V}}{{\Delta x}}} \right)
View answer and explanation
Correct option: D
ML−1T−1M{L^{ - 1}}{T^{ - 1}}
Option D (ML−1T−1M{L^{ - 1}}{T^{ - 1}}) is correct because the coefficient of viscosity relates force to area and velocity gradient, and its dimensions can be derived from the given formula.
161 Easy
161 of 384
Application +4 | -1
Dimensional formula for the universal gravitational constant G is
View answer and explanation
Correct option: C
[M−1L3T−2]\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^3}{\mathrm{T}^{ - 2}}} \right]
Option C ([M⁻¹L³T⁻²]) is correct because it is derived from Newton's law of gravitation, F = G(m1m2/r²).
162 Hard
162 of 384
Application +4 | -1
In the relation p=αβ  e−αzkθ,  pp = \frac{\mathrm{\alpha }}{\mathrm{\beta }}\mathrm{\;}{\mathrm{e}^{ - \frac{{\alpha z}}{{k\mathrm{\theta }}}}},\mathrm{\;}p , is the pressure, z the distance, k is Boltzmann constant and θ\theta is the temperature, the dimensional formula of β\beta will be
View answer and explanation
Correct option: A
[M0L2T0]\left[ {{\mathrm{M}^0}{\mathrm{L}^2}{\mathrm{T}^0}} \right]
Option A ([M⁰L²T⁰]) is correct because the exponent in the exponential term must be dimensionless, allowing us to determine the dimensions of β.
163 Easy
163 of 384
Understanding +4 | -1
Statement-I: The number of significant figures in 0.0010.001 is 1 while in 0.1000.100 it is 3.
Statement-II: Zeros before a non-zero significant digit are not counted while zeros after a non-zero significant digit are counted.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because the number of significant figures in 0.001 is 1, and in 0.100 it is 3, and the rule about zeros is correctly stated.
164 Easy
164 of 384
Remembering +4 | -1
In which of the following systems of units, a Weber is the unit of magnetic flux?
View answer and explanation
Correct option: C
SI
Option C (SI) is correct because the Weber is defined as the SI unit of magnetic flux.
165 Medium
165 of 384
Analyzing +4 | -1
Which of the following physical quantities have the
same dimensions?
View answer and explanation
Correct option: A
Electric displacement (D→)(\overrightarrow D )
and surface charge
density
Electric displacement (D→\overrightarrow D) and surface charge density have the same dimensions because electric displacement is defined as charge per unit area.
166 Medium
166 of 384
Application +4 | -1
Dimensions of permeability are
View answer and explanation
Correct option: A
A−2M1L1T−2{A^{ - 2}}{M^1}{L^1}{T^{ - 2}}
Option A (A−2M1L1T−2{A^{ - 2}}{M^1}{L^1}{T^{ - 2}}) is correct because it matches the dimensional formula for permeability derived from the force between two current-carrying wires.
167 Medium
167 of 384
Understanding +4 | -1
A student measured the diameter of a wire using a screw gauge with the least count 0.001 cm0.001 \mathrm{~cm} and listed the measurements. The measured value should be recorded as
View answer and explanation
Correct option: D
5.320 cm5.320 \mathrm{~cm}
Option D is correct because the measured value should be recorded with the same number of decimal places as the least count of the instrument.
168 Medium
168 of 384
Analyzing +4 | -1
Which of the following is dimensionless?
View answer and explanation
Correct option: A
v2rg\frac{{{v^2}}}{{r\mathrm{g}}}
Option A (8) is correct because the time taken for collision is directly proportional to the side length when masses are scaled proportionally.
169 Easy
169 of 384
Application +4 | -1
The density of a material in CGS system is 8 g/cm3g/cm^3. In a system of a unit in which unit of length is 5 cm and unit of mass is 20 g. The density of material is
View answer and explanation
Correct option: C
50
Option D (50) is correct because it is calculated by converting the density from the CGS system to the new system of units.
170 Easy
170 of 384
Remembering +4 | -1
The value of Planck's constant in SI unit is
View answer and explanation
Correct option: D
6.63×10−34 J−s6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}
Option D (6.63×10−34 J−s6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}) is correct because it is the experimentally determined value of Planck's constant in SI units.
171 Medium
171 of 384
Analyzing +4 | -1
Assertion : The error in the measurement of radius of the
sphere is 0.3%.The permissible error in its surface area is
0.6%.
Reason : The permissible error is calculated by the formula ΔAA=4Δrr\frac{{\Delta A}}{A} = \frac{{4\Delta r}}{r}
View answer and explanation
Correct option: C
Assertion is correct, reason is incorrect
Assertion is correct, reason is incorrect. The assertion is correct, but the reason is incorrect. The correct formula for the permissible error is ΔAA=2Δrr\frac{{\Delta A}}{A} = 2\frac{{\Delta r}}{r}
172 Medium
172 of 384
Remembering +4 | -1
The quantity having the same units in all systems of units is
View answer and explanation
Correct option: B
time
Option B (time) is correct because the concept and measurement of time are fundamental and consistent across all systems of units.
173 Easy
173 of 384
Application +4 | -1
The dimensional formula for Boltzmann’s constant is
View answer and explanation
Correct option: A
[ML2T−2θ−1]\left[ {M{L^2}{T^{ - 2}}{\theta ^{ - 1}}} \right]
Option A ([ML²T⁻²θ⁻¹]) is correct because Boltzmann's constant relates energy to temperature, and its dimensional formula reflects this relationship.
174 Medium
174 of 384
Remembering +4 | -1
Universal time is based on
View answer and explanation
Correct option: C
Vibrations of cesium atom
Option C (Vibrations of cesium atom) is correct because Universal Time (UTC) is based on the atomic time standard provided by cesium atomic clocks.
175 Easy
175 of 384
Application +4 | -1
Error in measurement of radius of sphere is 4% then maximum % error in volume is
View answer and explanation
Correct option: D
0.12
Option D (0.12) is correct because the percentage error in volume is three times the percentage error in the radius.
176 Easy
176 of 384
Remembering +4 | -1
Dimensional formula for force is
View answer and explanation
Correct option: B
[M1L1T−2]\left[ {{M^1}{L^1}{T^{ - 2}}} \right]
Option B ([M1L1T−2]\left[ {{M^1}{L^1}{T^{ - 2}}} \right]) is correct because force is mass times acceleration, and the dimensions of acceleration are length/time2.
177 Medium
177 of 384
Application +4 | -1
The velocity of a freely falling body changes as gphq{g^p}{h^q} , where g is acceleration due to gravity and h is the height. The values of p and q are
View answer and explanation
Correct option: B
12,12\frac{1}{2},\frac{1}{2}
Option B (12,12\frac{1}{2},\frac{1}{2}) is correct because dimensional analysis confirms that the velocity is proportional to the square root of both g and h.
178 Medium
178 of 384
Understanding +4 | -1
The dimensions of couple are
View answer and explanation
Correct option: A
ML2T−2M{L^2}{T^{ - 2}}
Option A (ML2T−2M{L^2}{T^{ - 2}}) is correct because couple is defined as force times distance, and the dimensions of force are MLT−2MLT^{-2} and distance is L.
179 Easy
179 of 384
Understanding +4 | -1
If the absolute errors in two physical quantities AA and BB are aa and bb respectively, then the absolute error in the value of A−BA-B are
View answer and explanation
Correct option: C
a+ba+b
Option C (a+ba+b) is correct because the absolute error in the difference of two quantities is the sum of their absolute errors.
180 Medium
180 of 384
Application +4 | -1
Consider a new system of units in which c(speed of light in vacuum), h(Planck’s constant) and G(gravitational constant) are taken as fundamental units. Which of the following would correctly represent mass in this new system?
View answer and explanation
Correct option: A
hcG\sqrt {\frac{{hc}}{G}}
Option A (hcG\sqrt {\frac{{hc}}{G}}) is correct because it gives the correct dimensional analysis for mass in terms of c, h, and G.
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