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NEET • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Mixed difficulty

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Showing 151-180 of 183 questions

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151 Easy
151 of 183
Understanding +4 | -1
Assertion: First law of thermodynamics is a restatement of the principle of conservation.
Reason: Energy is fundamental quantity.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C (If assertion is true, but reason is false) is correct because the first law of thermodynamics is indeed a restatement of the principle of conservation of energy, but energy being a fundamental quantity is not the correct explanation for this.
152 Easy
152 of 183
Application +4 | -1
An electric heater supplies heat to a system at a rate of 100 W100 \mathrm{~W}. If the system does work at a rate of 75 J75 \mathrm{~J} per second, at what rate (in joules) is the internal energy increasing?
View answer and explanation
Correct option: A
25
Option A (25) is correct because the rate of increase in internal energy is the difference between the power supplied and the rate of work done by the system.
153 Medium
153 of 183
Remembering +4 | -1
The mechanical equivalent of heat JJ is
View answer and explanation
Correct option: C
A conversion factor
Option C (A conversion factor) is correct because the mechanical equivalent of heat (J) is a factor that converts between units of energy (mechanical) and units of heat.
154 Easy
154 of 183
Application +4 | -1
A gas at NTP is suddenly compressed to one fourth of its original volume. If γ\gamma is supposed to be 3/23 / 2, then the final pressure is :-
View answer and explanation
Correct option: C
8 atmosphere
Option C (8 atmosphere) is correct because using the adiabatic process equation with γ = 3/2, the final pressure is calculated to be 8 times the initial pressure.
155 Medium
155 of 183
Application +4 | -1
500 J of heat energy is removed from 4 moles of a monoatomic ideal gas at constant volume. The temperature drops by
View answer and explanation
Correct option: C
10∘C{10^ \circ }C
Option C (10∘C{10^ \circ }C) is correct because the temperature drop is calculated using the heat removed, number of moles, and molar specific heat at constant volume.
156 Easy
156 of 183
Application +4 | -1
A gas expand 0.25  m30.25\,\,{m^3} at constant pressure 103N/m2,{10^3}N/{m^2}, the work done is
View answer and explanation
Correct option: B
250 J
Option B (250 J) is correct because work done at constant pressure is calculated as the product of pressure and change in volume.
157 Medium
157 of 183
Understanding +4 | -1
Assertion: Heat is not a state thermodynamic function.
Reason: Heat given in a system depends on process.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Heat is a path function, meaning its value depends on the process taken, not just the initial and final states. Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.
158 Medium
158 of 183
Application +4 | -1
A Carnot’s engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is
View answer and explanation
Correct option: A
420 J
Option A (420 J) is correct because it is the work done calculated from the Carnot refrigerator's coefficient of performance.
159 Easy
159 of 183
Application +4 | -1
A water falls is 84 metres high. If half of the potential energy of the falling water get converted to heat, the rise in temperature of water will be
View answer and explanation
Correct option: A
0.098∘C0.098^{\circ} \mathrm{C}
Option A (0.098∘C0.098^{\circ} \mathrm{C}) is correct because it is the temperature rise calculated from the conversion of potential energy to heat.
160 Medium
160 of 183
Understanding +4 | -1
Entropy of a system is related with
View answer and explanation
Correct option: A
Disorder of molecular motion of the system
Entropy is a measure of the disorder or randomness of a system, which is directly related to the disorder of molecular motion. Therefore, option A is correct.
161 Medium
161 of 183
Remembering +4 | -1
The ratio of the specific heats CpCV=γ\frac{C_p}{C_V}=\gamma in terms of degrees of freedom (n)(n) is given by
View answer and explanation
Correct option: C
(1+2n)\left(1+\frac{2}{n}\right)
Option C is correct because the relationship between the ratio of specific heats (γ\gamma) and the degrees of freedom (nn) is given by the formula γ=1+2n\gamma = 1 + \frac{2}{n}.
162 Medium
162 of 183
Understanding +4 | -1
The factor not needed to calculate heat lost or gained when there is no change of state is
View answer and explanation
Correct option: C
Relative density
Option C (Relative density) is correct because relative density is not directly used in the formula for calculating heat lost or gained without a change of state, which involves mass, specific heat, and temperature change.
163 Medium
163 of 183
Application +4 | -1
Calculate the time required to heat 20 kg20 \mathrm{~kg} of water from 10∘C10^{\circ} \mathrm{C} to 35∘C35^{\circ} \mathrm{C} using an immersion heater rated 1000 W1000 \mathrm{~W}. Assume that 80%80 \% of the power input is used to heat the water. Specific heat capacity of water =4200 J kg−1 K−1=4200 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}.
View answer and explanation
Correct option: B
44 min
Option B (44 min) is correct because it accurately calculates the time required based on the power, efficiency, mass, specific heat, and temperature change.
164 Medium
164 of 183
Understanding +4 | -1
Pressure – Temperature relationship for an ideal gas undergoing adiabatic change is (γ=CPCV)\left( {\gamma = \frac{{{C_P}}}{{{C_V}}}} \right)
View answer and explanation
Correct option: D
P1−γ  Tγ{P^{1 - \gamma }}\,\,{T^\gamma } = Constant
Option D (P1−γTγ{P^{1 - \gamma }}\\ {T^{\gamma }} = Constant) is correct because it represents the correct relationship between pressure and temperature in an adiabatic process.
165 Medium
165 of 183
Application +4 | -1
A gas under constant pressure of 4.5×1054.5 \times {10^5} Pa when subjected to 800 kJ of heat changes the volume from0.5m30.5{\mathrm{m}^3} to 2.0m32.0{\mathrm{m}^3}. The change in the internal energy of the gas is
View answer and explanation
Correct option: D
1.25×105J1.25 \times {10^5}\mathrm{J}
Option D (1.25×105J1.25 \times {10^5}\mathrm{J}) is correct because the change in internal energy is calculated using the first law of thermodynamics, accounting for the work done at constant pressure.
166 Medium
166 of 183
Understanding +4 | -1
The energy supply being cut-off, an electric heater element cools down to the temperature of its surroundings, but it will not cool further because
View answer and explanation
Correct option: D
Element & surroundings have same temp.
Option D (Element & surroundings have same temp.) is correct because heat transfer stops when thermal equilibrium is reached, meaning the element and surroundings are at the same temperature.
167 Hard
167 of 183
Application +4 | -1
The specific heat at constant pressure of a real gas obeying PV2=RT\mathrm{PV}^2=\mathrm{RT} equation is :
View answer and explanation
Correct option: D
CV+R2V\mathrm{C}_{\mathrm{V}}+\frac{\mathrm{R}}{2 \mathrm{V}}
Option D (CV+R2V\mathrm{C}_{\mathrm{V}}+\frac{\mathrm{R}}{2 \mathrm{V}}) is correct because it accounts for the additional term arising from the equation of state PV2=RT\mathrm{PV}^2=\mathrm{RT} when calculating CpC_p.
168 Hard
168 of 183
Application +4 | -1
Two heat engines are operating in such a way that the heat rejected by the first engine is used as the heat input of the second. If both the engines are 40%40 \% efficient, then the overall efficiency of the system is
View answer and explanation
Correct option: A
0.640.64
Option A (0.64) is correct because the overall efficiency is the product of the individual efficiencies when engines are operating in series.
169 Medium
169 of 183
Analyzing +4 | -1
100 mol100 \mathrm{~mol} of an ideal gas is heated from 10∘10^{\circ} to 20∘C20^{\circ} \mathrm{C} keeping its (i) volume constant (ii) pressure constant. Let ΔUa\Delta U_a and ΔUb\Delta U_b denote the change in the internal energy of the gas due to process (i) and (ii), respectively. Then, which of the following shall be true?
View answer and explanation
Correct option: B
ΔUa>ΔUb\Delta U_a > \Delta U_b
Option A is correct because the internal energy change depends only on the temperature change for an ideal gas, and the temperature change is the same in both processes, but work done is different.
170 Easy
170 of 183
Remembering +4 | -1
Which of the following has maximum specific heat
View answer and explanation
Correct option: A
Water
Option A (Water) is correct because water has a higher specific heat capacity than alcohol, glycerine, and oil.
171 Medium
171 of 183
Remembering +4 | -1
The first operation involved in a carnot cycle is
View answer and explanation
Correct option: A
Isothermal Expansion
Option A (Isothermal Expansion) is correct because the Carnot cycle starts with isothermal expansion.
172 Medium
172 of 183
Analyzing +4 | -1
Heat energy of 184 kJ184 \mathrm{~kJ} is given to ice of mass 600 g600 \mathrm{~g} at −12∘C-12^{\circ} \mathrm{C}. Specific heat of ice is 2222.3 J kg−2222.3 \mathrm{~J} \mathrm{~kg}^{-} 10C−1{ }^{10} \mathrm{C}^{-1} and latent heat of ice in 336 kJ/kg−1336 \mathrm{~kJ} / \mathrm{kg}^{-1}

A. Final temperature of system will be 0∘C0^{\circ} \mathrm{C}.

B. Final temperature of the system will be greater than 0∘C0^{\circ} \mathrm{C}.

C. The final system will have a mixture of ice and water in the ratio of 5:15: 1.

D. The final system will have a mixture of ice and water in the ratio of 1:51: 5.

E. The final system will have water only.

Choose the correct answer from the options given below:
View answer and explanation
Correct option: B
A and D only
Options A and D are correct because the heat energy is sufficient to raise the ice to 0°C and partially melt it, resulting in a mixture of ice and water in a 5:1 ratio.
173 Medium
173 of 183
Remembering +4 | -1
The ideal gas equation for an adiabatic process is:
View answer and explanation
Correct option: A
PVγ=P V^\gamma= constant
Option A (PVγ=P V^{\gamma}= constant) is correct because it represents the relationship between pressure and volume in an adiabatic process.
174 Medium
174 of 183
Analyzing +4 | -1
CvandCp{C_v}and{C_p} denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then
View answer and explanation
Correct option: B
Cp+Cv{C_p} + {C_v} is larger for a diatomic ideal gas than for a monoatomic ideal gas
Option B (Cp+Cv{C_p} + {C_v} is larger for a diatomic ideal gas than for a monoatomic ideal gas) is correct because both CpC_p and CvC_v are larger for diatomic gases due to their additional degrees of freedom.
175 Medium
175 of 183
Application +4 | -1
How much work to be done in decreasing the volume of an ideal gas by an amount of 2.4×10−4m32.4 \times {10^{ - 4}}{m^3} at normal temperature and constant normal pressure of 1×105N/m21 \times {10^5}N/{m^2}
View answer and explanation
Correct option: D
24J24J
Option D (24J24J) is correct because it is the work done calculated as W=PΔVW = P \Delta V at constant pressure.
176 Medium
176 of 183
Analyzing +4 | -1
Two Carnot engines A and B are operated in series. The engine AA receives heat from the source at temperature T1T_1 and rejects the heat to the sink at temperature T\mathrm{T}. The second engine BB receives the heat at temperature TT and rejects to its sink at temperature T2T_2. For what value of TT the efficiencies of the two engines are equal?
View answer and explanation
Correct option: D
T1T2\sqrt{T_1 T_2}
Option D is correct because for the efficiencies of the two Carnot engines to be equal, the intermediate temperature T must be the geometric mean of the source and sink temperatures.
177 Medium
177 of 183
Analyzing +4 | -1
An ideal monoatomic gas undergoes process PV1.25=P V^{1.25}= Constant . Then
View answer and explanation
Correct option: D
Heat is absorbed by gas if volume increases
Option D (Heat is absorbed by gas if volume increases) is correct because for the process PV1.25=ConstantPV^{1.25} = \text{Constant}, if volume increases, temperature decreases, but the work done is greater than the decrease in internal energy, leading to heat absorption.
178 Medium
178 of 183
Understanding +4 | -1
Efficiency of Carnot engine is 100% if
View answer and explanation
Correct option: B
T2=0K{T_2} = 0K
Option B (T2=0K{T_2} = 0K) is correct because the efficiency of a Carnot engine is given by η=1−T2T1\eta = 1 - \frac{T_2}{T_1}, where T2T_2 is the temperature of the cold reservoir and T1T_1 is the temperature of the hot reservoir. For η\eta to be 100%, T2T_2 must be 0K.
179 Medium
179 of 183
Understanding +4 | -1
When heat is given to a gas in an isothermal change, the result will be
View answer and explanation
Correct option: A
External work done
Option A (External work done) is correct because in an isothermal process, the temperature remains constant, so the internal energy does not change, and all the heat added is converted into work.
180 Medium
180 of 183
Understanding +4 | -1
Which of the following parameters does not characterise the thermodynamic state of matter?
View answer and explanation
Correct option: C
Work
Option C (Work) is correct because work is a process-dependent quantity, not a state variable. Temperature, pressure, and volume are state variables that describe the condition of the matter.
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