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NEET • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Mixed difficulty

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121 Hard
121 of 183
Application +4 | -1
One mole of an ideal monatomic gas is taken from state A\mathrm{A} to state B through the process P=(3/2)T1/2P=(3 / 2) T^{1 / 2}. It is found that its temperature increases by 100 K100 \mathrm{~K} in this process. Now it is taken from state B to C through a process for which internal energy is related to volume as Uint =(1/2)V1/2U_{\text {int }}=(1 / 2) V^{1 / 2}. Find the total work performed by the gas (in joule), if it is given that volume at B\mathrm{B} is 100 m3100 \mathrm{~m}^3 and at C it is 1600 m31600 \mathrm{~m}^3. (Use R=8.3 J/molKR=8.3 \mathrm{~J} / \mathrm{mol} \mathrm{K}.)
View answer and explanation
Correct option: A
435
The total work performed by the gas is 435 J. The work done in process A to B is calculated using the given relation P = (3/2)T(1/2) and the ideal gas law. The work done in process B to C is calculated using the relation between internal energy and volume.
122 Medium
122 of 183
Remembering +4 | -1
The thermodynamic process in which no work is done on or by the gas is
View answer and explanation
Correct option: D
Isochoric process
Option D (Isochoric process) is correct because in an isochoric process, the volume is constant, so no work is done.
123 Medium
123 of 183
Application +4 | -1
If amount of heat given to a system be 50 J and work done on the system be 15 J, then change in internal energy of the system is
View answer and explanation
Correct option: C
65 J
Option C (65 J) is correct because the change in internal energy is calculated by adding the heat given to the system and the work done on the system according to the first law of thermodynamics.
124 Easy
124 of 183
Understanding +4 | -1
Heat added to a system is equal to
View answer and explanation
Correct option: D
Sum of above all the three factors
Option D (Sum of above all the three factors) is correct because the heat added to a system can increase its internal kinetic energy, increase its internal potential energy, and/or be used to do work by the system, as described by the first law of thermodynamics.
125 Hard
125 of 183
Application +4 | -1
A man of 60 Kg gains 1000 Cal of heat by eating 5 mangoes. His efficiency is 56%. The height to which he can Jump by using this energy is
View answer and explanation
Correct option: A
4 m
Option A (4 m) is correct because it is the height calculated using the man's efficiency and the energy gained from eating mangoes.
126 Medium
126 of 183
Understanding +4 | -1
The theory of refrigerator is based on
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because the theory of a refrigerator is based on the reversed Carnot cycle, which involves the transfer of heat from a cold reservoir to a hot reservoir by doing work on the system.
127 Hard
127 of 183
Application +4 | -1
A monoatomic gas (γ=5/3)(\gamma = 5/3) is suddenly compressed to 1/8 of its original volume adiabatically, then the pressure of the gas, will change to
View answer and explanation
Correct option: D
32 times its initial pressure
Option D (32 times its initial pressure) is correct because the pressure changes by a factor of 32 when the volume is adiabatically compressed to 1/8 of its original volume with γ = 5/3.
128 Easy
128 of 183
Application +4 | -1
A monoatomic gas at pressure PP and volume VV is suddenly compressed to one eighth of its original volume. The final pressure at constant entropy will be :
View answer and explanation
Correct option: C
32P32 P
Option C (32P32 P) is correct because for a monoatomic gas undergoing adiabatic compression, the final pressure is 32 times the initial pressure when the volume is reduced to one-eighth.
129 Easy
129 of 183
Understanding +4 | -1
If CP{C_P} and CV{C_V} denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then CP−CV={C_P} - {C_V} =
View answer and explanation
Correct option: A
R28\frac{R}{{28}}
Option A (R28\frac{R}{{28}}) is correct because it represents the difference between specific heats of nitrogen per unit mass, considering its molar mass.
130 Medium
130 of 183
Remembering +4 | -1
In which thermodynamic process, volume remains same?
View answer and explanation
Correct option: D
Isochoric
Option D (Isochoric) is correct because an isochoric process is defined as a thermodynamic process where the volume remains constant.
131 Medium
131 of 183
Remembering +4 | -1
First law of thermodynamics states that
View answer and explanation
Correct option: D
Heat is a form of energy
Option D (Heat is a form of energy) is correct because the first law of thermodynamics is essentially a statement of energy conservation, recognizing heat as a form of energy.
132 Easy
132 of 183
Understanding +4 | -1
Assertion: The internal energy of a real gas is function of both, temperature and volume.
Reason: At constant pressure, some heat is spent in expansion of the gas.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the internal energy of a real gas depends on both temperature and volume due to intermolecular forces, and at constant pressure, some heat is used for expansion, indicating volume dependence.
133 Easy
133 of 183
Application +4 | -1
The temperature of food material in a refrigerator is 4∘C4^{\circ} \mathrm{C} and temperature of environment is 15∘C15^{\circ} \mathrm{C}. If carnot cycle is used in its working gas, then find its carnot efficiency.
View answer and explanation
Correct option: A
0.0380.038
Option A (0.038) is correct because the Carnot efficiency is calculated using the temperatures of the cold and hot reservoirs in Kelvin.
134 Medium
134 of 183
Remembering +4 | -1
In thermodynamics, heat and work are:
View answer and explanation
Correct option: C
Path functions
Option C is correct because heat and work are path functions, meaning their values depend on the path taken during a thermodynamic process, not just the initial and final states.
135 Medium
135 of 183
Understanding +4 | -1
Compressed air in the tube of a wheel of a cycle at normal temperature suddenly starts coming out from a puncture. The air inside
View answer and explanation
Correct option: C
Starts becoming cooler
Option C (Starts becoming cooler) is correct because the sudden expansion of air is an adiabatic process, where the air does work on the surroundings, causing its internal energy and temperature to decrease.
136 Hard
136 of 183
Application +4 | -1
One mole of an ideal gas with γ=1.4,\gamma = 1.4, is adiabatically compressed so that its temperature rises from 27∘C27^\circ C to 35∘C,35^\circ C,. The change in the internal energy of the gas is (R=8.3J/mol. k)\left( {R = 8.3J/mol.\,k} \right)
View answer and explanation
Correct option: B
166 J
Option B (166 J) is correct because it is the change in internal energy calculated using the given temperature change and the number of moles.
137 Medium
137 of 183
Application +4 | -1
During an adiabatic expansion of 2 moles of a gas, the change in internal energy was found −50J- 50J.The work done during the process is
View answer and explanation
Correct option: D
50J50J
Option D (50J50J) is correct because in an adiabatic process, the work done is equal to the negative of the change in internal energy.
138 Medium
138 of 183
Analyzing +4 | -1
An engineer claims to have made an engine delivering 10kW10kW power with fuel consumption of 1g/s1g/s. The calorific value of the fuel is 2kcal/g2kcal/g. Is the claim of the engineer
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Correct option: B
Invalid
Option B (Invalid) is correct because the claimed efficiency exceeds the maximum possible efficiency based on the fuel's calorific value.
139 Medium
139 of 183
Analyzing +4 | -1
Statement-1: When you touch two bodies, the body which is felt warmer must be of higher temperature than the other one.
Statement-2: The heat flows from higher temperature to lower temperature.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B (Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1) is correct because while both statements are true, the perceived warmth is also influenced by the rate of heat transfer, not just the temperature difference.
140 Hard
140 of 183
Application +4 | -1
A bullet of mass m kgm \mathrm{~kg} is moving with velocity K2 m/sK^2 \, \mathrm{m} / \mathrm{s} collides against a vertical wall, consequently half of its kinetic energy is converted into heat. If whole heat is acquired by the bullet, the rise in temperature (in ∘C)\text{(in }{ }^{\circ} \mathrm{C}) of bullet is (specific heat for bullet =s J/kg∘C)\text{(specific heat for bullet }=s \mathrm{~J} / \mathrm{kg}^{\circ} \mathrm{C})
View answer and explanation
Correct option: B
K44s\frac{K^4}{4 s}
Option B (K44s\frac{K^4}{4 s}) is correct because it is the rise in temperature calculated from the kinetic energy converted to heat.
141 Medium
141 of 183
Remembering +4 | -1
In an isothermal change, an ideal gas obeys
View answer and explanation
Correct option: A
Boyle’s law
Option A (Boyle’s law) is correct because Boyle's law states that for a fixed amount of gas at constant temperature, pressure and volume are inversely proportional (PV = constant), which is the condition for an isothermal change.
142 Medium
142 of 183
Application +4 | -1
For a gas, the difference between the two principle specific heats is 4150 Jkg−1K−1\mathrm{Jk}{\mathrm{g}^{ - 1}}{\mathrm{K}^{ - 1}}.What is the specific heat of the gas at constant volume if the ratio of specific heat is 1.4?
View answer and explanation
Correct option: B
10375Jkg−1K−110375\mathrm{Jk}{\mathrm{g}^{ - 1}}{\mathrm{K}^{ - 1}}
Option A (5186Jkg−1K−15186\mathrm{Jk}{\mathrm{g}^{ - 1}}{\mathrm{K}^{ - 1}}) is incorrect. Option B (10375Jkg−1K−110375\mathrm{Jk}{\mathrm{g}^{ - 1}}{\mathrm{K}^{ - 1}}) is the correct answer because it is derived from the given difference between specific heats and their ratio.
143 Medium
143 of 183
Understanding +4 | -1
Which of the following is not a thermodynamical function
View answer and explanation
Correct option: B
Work done
Option B (Work done) is correct because work done is a path function, not a state function like enthalpy, Gibb's energy, and internal energy.
144 Easy
144 of 183
Understanding +4 | -1
Which of the following is not a state function?
View answer and explanation
Correct option: B
Work done in isothermal process
Option B (Work done in isothermal process) is correct because work done is a path function, not a state function, and depends on the process (isothermal in this case).
145 Medium
145 of 183
Analyzing +4 | -1
An ideal monoatomic gas A\mathrm{A} is supplied heat so as to expand without changing its temperature. In another process, starting with same state, it is supplied heat at constant pressure. In both cases a graph of work done by gas is plotted versus heat added (Q) to the gas. The ratio of slope of graphs obtained in first & second process in η1\eta_1. The same ratio obtained for ideal diatomic gas is η2\eta_2. If the ratio η1η2=ab\frac{\eta_1}{\eta_2}=\frac{a}{b}. Then find a+ba+b.
View answer and explanation
Correct option: D
12
Option D (12) is correct. The ratio η1η2\frac{{\eta_1}}{{\eta_2}} is calculated based on the work done and heat added in isothermal and isobaric processes for monoatomic and diatomic gases.
146 Medium
146 of 183
Understanding +4 | -1
Assertion: The zeroth law said that, when two systems XX and YY are in thermal equilibrium, there must be a physical quantity that has the same value for both.
Reason: The physical quantity, which is same for both the systems, is temperature.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
The zeroth law of thermodynamics defines thermal equilibrium, and temperature is the physical quantity that is the same for systems in thermal equilibrium. Therefore, both the assertion and reason are true, and the reason is the correct explanation.
147 Medium
147 of 183
Remembering +4 | -1
The specific heat relation for ideal gas is
View answer and explanation
Correct option: B
CP−CV=R{C_P} - {C_V} = R
Option B (CP−CV=R{C_P} - {C_V} = R) is correct because it is the correct specific heat relation for an ideal gas, where R is the gas constant.
148 Easy
148 of 183
Understanding +4 | -1
For an isothermal expansion of a perfect gas, the value of ΔPP\frac{{\Delta P}}{P} is equal
View answer and explanation
Correct option: B
−ΔVV- \frac{{\Delta V}}{V}
Option B (−ΔVV- \frac{{\Delta V}}{V}) is correct because for an isothermal process, PV=constantPV = constant, and differentiating this gives the relationship between changes in pressure and volume.
149 Medium
149 of 183
Analyzing +4 | -1
Assertion: The ratio CPCV\frac{C_P}{C_V} is more for helium gas than for hydrogen gas.
Reason: Atomic mass of helium is more than that of hydrogen.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct. The ratio CPCV\frac{C_P}{C_V} is indeed higher for helium than for hydrogen because helium is monoatomic (γ=5/3\gamma = 5/3) and hydrogen is diatomic (γ=7/5\gamma = 7/5). However, the reason given (atomic mass) is not the correct explanation; the correct reason is the difference in degrees of freedom.
150 Easy
150 of 183
Application +4 | -1
Heat energy of 1500 J is supplied to a gas the external work done by the gas is 525 J. The increase in internal energy is
View answer and explanation
Correct option: B
975 J
Option B (975 J) is correct because the increase in internal energy is the difference between the heat supplied and the work done by the gas, according to the first law of thermodynamics.
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