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NEET • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Mixed difficulty

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61 Easy
61 of 183
Understanding +4 | -1
A thermodynamical system is changed from state(p1V1)to(p2,V2)\left( {{p_1}{V_1}} \right)\mathrm{to}\left( {{p_2},{V_2}} \right) by two different processes, the quantity which will remain same will be
View answer and explanation
Correct option: D
ΔQ−ΔW\mathrm{\Delta }Q - \mathrm{\Delta }W
Option D (ΔQ−ΔW\mathrm{\Delta }Q - \mathrm{\Delta }W) is correct because the change in internal energy, which is a state function, is equal to ΔQ−ΔW\mathrm{\Delta }Q - \mathrm{\Delta }W according to the first law of thermodynamics.
62 Hard
62 of 183
Understanding +4 | -1
Identify the characteristics of an adiabatic process in a monoatomic gas.

(A) Internal energy is constant.

(B) Work done in the process is equal to the charge in internal energy.

(C) The product of temperature and volume is a constant.

(D) The product of pressure and volume is a constant.

(E) The work done to change the temperature from T1\mathrm{T}_1 to T2\mathrm{T}_2 is proportional to (T2−T1)\left(\mathrm{T}_2-\mathrm{T}_1\right)

Choose the correct answer from the options given below:
View answer and explanation
Correct option: C
(B), (E) only
Option C ((B), (E) only) is correct because in an adiabatic process, work done equals the negative change in internal energy, and work done is proportional to the temperature difference.
63 Easy
63 of 183
Analyzing +4 | -1
A monoatomic ideal gas expanded adiabatically to η\eta times of its initial volume. If the ratio of final rate of collisions of molecules with unit area of container's walls to the initial rate is 1ηx\frac{1}{\eta^x}. Find the value of xx.
View answer and explanation
Correct option: A
1.33
Option A (1.33) is correct because it is derived from the relationship between collision rate, volume, and adiabatic expansion.
64 Medium
64 of 183
Application +4 | -1
In an isobaric process, the absolute temperature is doubled. The mean free path (λ)\left( \lambda \right) and the relaxation time (τ)\left( \tau \right) will become respectively
View answer and explanation
Correct option: B
times and 2\sqrt 2 times
Option B ( times and 2\sqrt 2 times) is correct because the mean free path is proportional to temperature and relaxation time is proportional to the square root of temperature.
65 Medium
65 of 183
Application +4 | -1
A lead ball moving with a velocity V strikes a wall and stops. If 50% of its energy is converted into heat, then what will be the increase in temperature (Specific heat of lead is S )
View answer and explanation
Correct option: B
V24JS\frac{{{V^2}}}{{4JS}}
Option B (V24JS\frac{{{V^2}}}{{4JS}}) is correct because it correctly relates the increase in temperature to the initial kinetic energy and specific heat, considering the energy conversion efficiency.
66 Easy
66 of 183
Application +4 | -1
In a thermodynamic process, pressure of fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas. If initial internal energy of the gas was 40 J, what will be final internal energy ?
View answer and explanation
Correct option: B
28 J
Option B (28 J) is correct because the final internal energy is calculated using the first law of thermodynamics, accounting for heat released and work done on the gas.
67 Medium
67 of 183
Application +4 | -1
The specific heat of a metal at low temperature varies according to S=3t2+4tS=3 t^2+4 t where tt is absolute temperature. The heat energy needed to raise the temperature of unit mass of metal from 1 K1 \mathrm{~K} to 2 K2 \mathrm{~K} is
View answer and explanation
Correct option: A
13
Option A (13) is correct because it is the result of integrating the specific heat function over the given temperature range.
68 Medium
68 of 183
Analyzing +4 | -1
(A): In isobaric process, during an expansion of a gas both volume and temperature of the gas increase.
(R): Heat added to a gas partly gets converted into internal energy and remaining to do external work.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because in an isobaric process, as heat is added, the temperature increases, leading to an increase in volume, and this is because the heat is used for both internal energy increase and work done.
69 Medium
69 of 183
Understanding +4 | -1
Which of the following is not thermodynamic coordinate?
View answer and explanation
Correct option: A
Gas constant ( R )
Option A (Gas constant (R)) is correct because the gas constant is a fixed value, not a thermodynamic coordinate which can vary.
70 Medium
70 of 183
Understanding +4 | -1
Choose the correct statement
View answer and explanation
Correct option: B
Heat is a path function, while internal energy is not
Option B (Heat is a path function, while internal energy is not) is correct because heat transfer depends on the process, while internal energy depends only on the state of the system.
71 Medium
71 of 183
Application +4 | -1
If earth suddenly stops rotating about its own axis, the increase in it’s temperature will be
View answer and explanation
Correct option: A
R2ω25Js\frac{{{R^2}{\omega ^2}}}{{5Js}}
Option A is correct because it represents the increase in temperature due to the rotational kinetic energy being converted into heat energy when the Earth stops rotating.
72 Medium
72 of 183
Analyzing +4 | -1
Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increases as Vq,{V^q}, where V is the volume of the gas. The value of q is (γ=CPCV)\left( {\gamma = \frac{{{C_P}}}{{{C_V}}}} \right)
View answer and explanation
Correct option: C
γ+12\frac{{\gamma + 1}}{2}
Option C (γ+12\frac{{\gamma + 1}}{2} ) is correct because the average time of collision increases with volume as V(γ+1)/2V^{(\gamma+1)/2} in an adiabatic expansion.
73 Medium
73 of 183
Application +4 | -1
In the above question, if γ=1.5\mathrm{\gamma } = 1.5,the gas may
View answer and explanation
Correct option: C
A mixture of monoatomic and diatomic gases
Option C (A mixture of monoatomic and diatomic gases) is correct because a gamma value of 1.5 lies between the gamma values of monoatomic (1.67) and diatomic (1.4) gases, implying a mixture.
74 Medium
74 of 183
Application +4 | -1
Calculate change in internal energy of a system which has absorbed 2 kcal of heat and done 500 J of work
View answer and explanation
Correct option: A
7900 J
Option B (8900 J) is correct because it is the change in internal energy calculated using the first law of thermodynamics: ΔU=Q−W\Delta U = Q - W.
75 Medium
75 of 183
Analyzing +4 | -1
For a gas Cp−Cv=R{C_p} - {C_v} = R in a state PP and Cp−Cv=1.10 R{C_p} - {C_v} = 1.10\,R in a state Q .  TpQ\,.\,\,{T_p} and  TQ\,{T_Q} are the temperatures in two
different states PP and QQ respectively. Then,
View answer and explanation
Correct option: D
Tp>TQ{T_p} > {T_Q}
Option D (Tp>TQ{T_p} > {T_Q}) is correct because for a real gas, the difference between Cp and Cv decreases as temperature decreases.
76 Medium
76 of 183
Understanding +4 | -1
Water is used to cool the radiators of engines in cars because
View answer and explanation
Correct option: B
Of its high specific heat
Option B (Of its high specific heat) is correct because water's high specific heat capacity allows it to absorb a large amount of heat without a significant temperature increase, making it an effective coolant.
77 Easy
77 of 183
Understanding +4 | -1
Statement-1: When an ideal gas is taken from a given thermodynamic state AA to another given thermodynamic state BB by any polytrophic process, the change in the interval energy of the system will be the same in all processes.
Statement-2: Internal energy of the gas depends only upon its absolute temperature.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A is correct because the change in internal energy of an ideal gas depends only on its initial and final temperatures, and the internal energy itself is a function of absolute temperature only. Therefore, the change in internal energy will be the same regardless of the path taken.
78 Medium
78 of 183
Understanding +4 | -1
When a body A is in thermal equilibrium with a body B, and also separately with a body C, then B and C will be in thermal equilibrium with each other.
View answer and explanation
Correct option: A
TRUE
This statement describes the zeroth law of thermodynamics, which states that if two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other. Therefore, the statement is true.
79 Medium
79 of 183
Analyzing +4 | -1
Assertion(A): If volume of a gas is increasing but temperature of the gas is decreasing, then heat given to the gas may be positive, negative or zero.

Reason(R): Heat given to a gas is a state function. It is not path function.
View answer and explanation
Correct option: C
If Assertion is correct but Reason is incorrect.
The Assertion is correct because the heat given to the gas depends on the path taken (first law of thermodynamics). The Reason is incorrect because heat is a path function, not a state function.
80 Medium
80 of 183
Understanding +4 | -1
When water is converted into ice, its entropy
View answer and explanation
Correct option: B
Decreases
Option B (Decreases) is correct because when water converts to ice, it becomes more ordered, leading to a decrease in entropy.
81 Easy
81 of 183
Application +4 | -1
An iron ball of mass 0.2 kg0.2 \mathrm{~kg} is heated to 100∘C100^{\circ} \mathrm{C} and put into a block at ice at 0∘C 25 g0^{\circ} \mathrm{C} \,25 \mathrm{~g} of ice melts. If the latent heat of fusion of ice is 80 cal g−180 \mathrm{~cal} \mathrm{~g}^{-1}, then the specific heat of iron in cal g−1 ∘C\mathrm{cal} \mathrm{~g}^{-1} \,{}^\circ\mathrm{C} is
View answer and explanation
Correct option: B
0.10.1
Option B (0.1) is correct because the specific heat of iron is calculated by equating the heat lost by the iron ball to the heat gained by the ice during melting.
82 Medium
82 of 183
Analyzing +4 | -1
An ideal gas in a piston cylinder arrangement is to be taken from a temperature of 500 K500 {~K} to a temperature of 600 K600 {~K}. Which of the thermodynamic process given in options should be used so that the final state of 600 K600 {~K} is achieved using a minimum energy input from outside?
View answer and explanation
Correct option: C
Isochoric
Option C (Isochoric) is correct because at constant volume, all the heat added goes into increasing the internal energy and thus the temperature, requiring the least energy input.
83 Medium
83 of 183
Application +4 | -1
A mono atomic gas is supplied the heatQQ very slowly keeping the pressure constant. The work done by the gas will be
View answer and explanation
Correct option: C
25Q\frac{2}{5}Q
Option C (25Q\frac{2}{5}Q) is correct because for a monoatomic gas at constant pressure, the work done is 25\frac{2}{5} of the heat supplied.
84 Hard
84 of 183
Application +4 | -1
In an adiabatic process where pressure is increased by 23%ifCpCv=32,\frac{2}{3}\% \mathrm{if}\frac{{{C_p}}}{{{C_v}}} = \frac{3}{2}, then the volume decreases by about
View answer and explanation
Correct option: A
49%\frac{4}{9}\%
Option A (49%\frac{4}{9}\%) is correct because it is derived from the adiabatic process equation relating pressure and volume changes.
85 Easy
85 of 183
Application +4 | -1
A girl weighing 42 kg eats bananas whose energy is 980 calories. If this energy is used to go to height hh, the value of hh is
View answer and explanation
Correct option: A
10 m
Option A (10 m) is correct because the potential energy gained by the girl equals the energy from the bananas, so mgh=energymgh = energy, and solving for h gives 10m.
86 Easy
86 of 183
Understanding +4 | -1
The increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?
View answer and explanation
Correct option: B
Adiabatic
Option B is correct because if the increase in internal energy of a system is equal to the work done on the system (ΔU = W), and from the first law of thermodynamics ΔU = Q - W, then Q = 0, which defines an adiabatic process.
87 Hard
87 of 183
Analyzing +4 | -1
Consider the efficiency of carnot's engine is given by η=αβsin⁡θlog⁡eβxkT\eta=\frac{\alpha \beta}{\sin \theta} \log e \frac{\beta x}{k T}, where α\alpha and β\beta are constants. If TT is temperature, kk is Boltzmann constant, θ\theta is angular displacement and xx has the dimensions of length. Then, choose the incorrect option
View answer and explanation
Correct option: D
Dimensions of α\alpha is same as that of β\beta.
Option D is the incorrect option because, based on dimensional analysis of the given equation, the dimensions of α\alpha and β\beta are not the same.
88 Easy
88 of 183
Understanding +4 | -1
In a cyclic process, work done by the system is
View answer and explanation
Correct option: B
Equal to heat given to the system
The correct answer is B (Equal to heat given to the system) because in a cyclic process, the change in internal energy is zero, so the work done equals the heat added.
89 Hard
89 of 183
Application +4 | -1
A litre of dry air STP expands adiabatically to a volume of 3 L. If γ=1.40,\mathrm{\gamma } = 1.40, the work done by air is (31.4=4.6555)\mathrm{(}{\mathrm{3}^{\mathrm{1}\mathrm{.4}}}\mathrm{ = 4}\mathrm{.6555)} [Take, air to be an ideal gas]
View answer and explanation
Correct option: B
90.5 J
Option B (90.5 J) is correct because the work done by the air is calculated using the adiabatic process equation and the ideal gas law.
90 Easy
90 of 183
Application +4 | -1
At constant volume the specific heat of a gas is 3R2,\frac{{3R}}{2}, then the value of 'γ\gamma' will be
View answer and explanation
Correct option: C
53\frac{5}{3}
Option C (5/3) is correct because γ = Cp/Cv, and Cp can be found using the relation Cp = Cv + R.
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