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JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
An ideal gas is made to go through a cyclic thermodynamical process in four steps. The amount of heat involved are Q1=600J,Q2=−400J,Q3=−300J{Q_1} = 600J,{Q_2} = - 400J,{Q_3} = - 300J and Q4{Q_4}=200 J respectively. The corresponding work involved are W1=300J,W2=−200J,W3=−150J{W_1} = 300J,{W_2} = - 200J,{W_3} = - 150J and W4{W_4}. What is the value of W4{W_4}
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Correct option: C
150J150J
Option C (150 J) is correct because it applies the first law of thermodynamics for a cyclic process, where the net heat equals the net work done.

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