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NEET • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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Showing 31-60 of 239 questions
31 Medium
31 of 239
Understanding +4 | -1
In uniform circular motion
View answer and explanation
Correct option: C
Both the angular velocity and the angular momentum stay constant
Option C (Both the angular velocity and the angular momentum stay constant) is correct because in uniform circular motion, both the magnitude and direction of angular velocity and angular momentum are constant.
32 Medium
32 of 239
Understanding +4 | -1
A body moves with constant angular velocity on a circle. Magnitude of angular acceleration
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because constant angular velocity implies no change in angular velocity, hence zero angular acceleration.
33 Medium
33 of 239
Remembering +4 | -1
A spherical shell has mass MM and radius RR. Moment of inertia about its diameter will be
View answer and explanation
Correct option: B
23MR2\frac{2}{3}M{R^2}
Option B (2/3 MR²) is correct because the moment of inertia of a spherical shell about its diameter is 2/3 MR².
34 Medium
34 of 239
Understanding +4 | -1
A circular turn table has a block of ice placed at its centre. The system rotates with an angular speed ω\omega about an axis passing through the centre of the table. If the ice melts on its own without any evaporation, the speed of rotation of the system
View answer and explanation
Correct option: D
Decreases to a value less than ω\omega
Option D (Decreases to a value less than ω\omega) is correct because the moment of inertia increases when the ice melts, and angular momentum is conserved.
35 Medium
35 of 239
Understanding +4 | -1
If a hollow cylinder and a solid cylinder are allowed to roll down an inclined plane, which will take more time to reach the bottom
View answer and explanation
Correct option: A
Hollow cylinder
Option A (Hollow cylinder) is correct because the hollow cylinder has a higher moment of inertia, resulting in a slower acceleration down the incline.
36 Easy
36 of 239
Analyzing +4 | -1
A solid sphere and hollow sphere of same mass and radius rotate about their diameter with same rotational kinetic energy. If torques of equal magnitude are applied on them, ratio of their angular displacement before they are bought to rest.
View answer and explanation
Correct option: A
0.042361111
Option A (0.042361111) is correct as it represents the ratio of angular displacements calculated using the moments of inertia of a solid sphere and a hollow sphere and the work-energy theorem.
37 Medium
37 of 239
Analyzing +4 | -1
The moment of inertia of a uniform cylinder of length ll and radius RR about its perpendicular bisector is II. What is the ratio l/Rl/R such that the moment of inertia is minimum?
View answer and explanation
Correct option: D
32\sqrt {\frac{3}{2}}
Option D (32\sqrt {\frac{3}{2}}) is correct because it represents the ratio l/R that minimizes the moment of inertia of a cylinder about its perpendicular bisector.
38 Medium
38 of 239
Understanding +4 | -1
The ratio of angular speeds of minute hand and hour hand of a watch is
View answer and explanation
Correct option: C
12:112:1
Option C (12:112:1) is correct because the minute hand completes one rotation in 60 minutes, while the hour hand completes one rotation in 12 hours.
39 Hard
39 of 239
Application +4 | -1
Two discs of same moment of inertia rotating about
their regular axis passing through centre and
perpendicular to the plane of disc with angular
velocity 2 rad/s and 4 rad/s. They are brought into
contact face to face coinciding the axis of rotation.
The expression for loss of energy during this procss
is:
View answer and explanation
Correct option: A
II
Option D (All of the above) is correct because pulling the weights inwards decreases the moment of inertia, increasing angular velocity and kinetic energy while conserving angular momentum.
40 Hard
40 of 239
Application +4 | -1
The surface density of a circular disc of radius a depends on the distance as ρ(r)=A+Br\rho(r)=A+B r. The moment of inertia about the line perpendicular to the plane of the disc is
View answer and explanation
Correct option: A
πa4(A2+2a5B)\pi a^4\left(\frac{A}{2}+\frac{2 a}{5} B\right)
Option A (πa4(A2+2a5B)\pi a^4(\frac{A}{2}+\frac{2 a}{5} B)) is correct because it is the result of integrating the moment of inertia over the area of the disc with the given density function.
41 Medium
41 of 239
Analyzing +4 | -1
STATEMENT-1 : Two cylinders, one hollow (metal) and the other solid (wood) with the same mass and identical dimensions are simultaneously allowed to roll without slipping down an inclined plane from the same height. The hollow cylinder will reach the bottom of the inclined plane first.

STATEMENT-2 : By the principle of conservation of energy, the total kinetic energies of both the cylinders are identical when they reach the bottom of the incline.
View answer and explanation
Correct option: D
Statement - 1 is False, Statement-2 is True
Statement-1 is False, and Statement-2 is True. The solid cylinder reaches the bottom first because it has a lower moment of inertia. The total kinetic energies are the same due to conservation of energy.
42 Medium
42 of 239
Application +4 | -1
Two homogeneous spheres A and B of masses m and 2m having radii 2a and a respectively are placed in touch. The distance of centre of mass from first sphere is
View answer and explanation
Correct option: B
2a
Option B (2a) is correct because it correctly calculates the distance from the center of mass to the first sphere, considering the masses and radii of both spheres.
43 Medium
43 of 239
Analyzing +4 | -1
Assertion: At the centre of earth, a body has centre of mass, but no centre of gravity.
Reason: Acceleration due to gravity is zero at the centre of earth.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because at the center of the Earth, the net gravitational force is zero, leading to no center of gravity, and this is because the acceleration due to gravity is zero.
44 Easy
44 of 239
Application +4 | -1
A force F = 10 N is acting on a point is at 4 m distance then torque is [N-m]
View answer and explanation
Correct option: C
40
Option C (40 N-m) is correct because torque is the product of force and the perpendicular distance from the axis of rotation.
45 Hard
45 of 239
Application +4 | -1
A thin rod of mass 6 m and length 6l6l is bent into regular hexagon. The moment of inertia of the hexagon about an axis normal to its plane and through the centre of mass of the system
View answer and explanation
Correct option: C
5 ml25\,m{l^2}
Option C (5 ml25\,m{l^2}) is correct because it is the moment of inertia calculated by summing the moments of inertia of each rod segment about the center.
46 Medium
46 of 239
Understanding +4 | -1
Two racing cars of masses m1 and m2{m_1}\,and\,{m_2} are moving in circles of radii r1 and r2{r_1}\,and\,{r_2} respectively. Their speeds are such that each makes a complete circle in the same duration of time t.The ratio of the angular speed of the first to the second car is
View answer and explanation
Correct option: C
1:11:1
Option C (1:11:1) is correct because angular speed is defined as the angle covered per unit time, and both cars complete a circle in the same time.
47 Easy
47 of 239
Analyzing +4 | -1
When a sphere rolls down an inclined plane, then identity the correct statement related to the work done by friction force
View answer and explanation
Correct option: C
The net work done by friction is zero
Option C (The net work done by friction is zero) is correct because while friction does negative work in the translational sense, it does positive work in the rotational sense, resulting in zero net work.
48 Medium
48 of 239
Understanding +4 | -1
A uniform heavy disc is rotating at constant angular velocity ω\omega about a vertical axis through its centre and perpendicular to the plane of the disc. Let L be its angular momentum. A lump of plasticine is dropped vertically on the disc and sticks to it. Which will be constant
View answer and explanation
Correct option: C
L only
Option C (L only) is correct because in the absence of external torques, the angular momentum of the system is conserved.
49 Medium
49 of 239
Understanding +4 | -1
Where will be the centre of mass on combining two masses m and (M > m)
View answer and explanation
Correct option: B
Towards M
Option B is correct. The center of mass is always closer to the heavier mass. Since M > m, the center of mass will be towards M.
50 Medium
50 of 239
Application +4 | -1
If the equation for the displacement of a particle moving on a circular path is given by (θ)=2t3+0.5\left( \theta \right) = 2{t^3} + 0.5, where θ\theta is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start is
View answer and explanation
Correct option: C
24 rad/sec
Option C (24 rad/sec) is correct because angular velocity is the derivative of angular displacement with respect to time.
51 Medium
51 of 239
Analyzing +4 | -1
If we hollow the ball of pendulum and fill it with sand, what would be the effect of change on the center of mass?
View answer and explanation
Correct option: D
Its value will first decrease and then increase
Option D is correct. Initially, the center of mass decreases as sand is added to the hollow ball. After it is completely filled, further addition of sand increases the center of mass.
52 Hard
52 of 239
Application +4 | -1
A solid sphere of mass 2 kg2 \mathrm{~kg} is rolling on a frictional horizontal surface with velocity 6 m/s6 \mathrm{~m} / \mathrm{s}. It collides on the free end of an ideal spring whose other end in fixed. The maximum compression produced in the spring will be x m\sqrt{x} \mathrm{~m}. Find the value of xx (Force constant of the spring is 36 N/m36 \mathrm{~N} / \mathrm{m} ).
View answer and explanation
Correct option: A
2.8
Option A (2.8) is correct because the maximum compression is found by equating the total kinetic energy (translational and rotational) to the potential energy stored in the spring.
53 Hard
53 of 239
Application +4 | -1
A solid cylinder of mass M{M} and radius R{R} rolls down an inclined plane of height h{h}. The angular velocity of the cylinder when it reaches the bottom of the plane is :
View answer and explanation
Correct option: B
2Rgh3\frac{2}{R} \sqrt{\frac{g h}{3}}
Option B (2Rgh3\frac{2}{R} \sqrt{\frac{g h}{3}}) is correct because it is the correct angular velocity when the cylinder reaches the bottom.
54 Medium
54 of 239
Understanding +4 | -1
The motion of centre of mass depends on
View answer and explanation
Correct option: A
Total external force
Option A (Total external force) is correct because the motion of the center of mass is determined solely by the net external force acting on the system.
55 Medium
55 of 239
Application +4 | -1
Two particles of masses 1 kg and 2 kg are located at x1=0,  y1=0 and x2=1,  y2=0{x_1} = 0,\;{y_1} = 0\,and\,{x_2} = 1,\;{y_2} = 0 respectively. The centre of mass of the system is at
View answer and explanation
Correct option: D
x=23,  y=0x = \frac{2}{3},\;y = 0
Option D (x=23,  y=0x = \frac{2}{3},\;y = 0) is correct because the center of mass coordinates are calculated using the formulas xcm=(m1x1+m2x2)/(m1+m2)x_{cm} = (m_1x_1 + m_2x_2) / (m_1 + m_2) and ycm=(m1y1+m2y2)/(m1+m2)y_{cm} = (m_1y_1 + m_2y_2) / (m_1 + m_2).
56 Medium
56 of 239
Understanding +4 | -1
In the absence of external torque for a body revolving about any axis, the quantity that remains constant is
View answer and explanation
Correct option: D
Angular momentum
The correct answer is D (Angular momentum) because in the absence of external torque, the angular momentum of a body remains constant.
57 Hard
57 of 239
Application +4 | -1
 A{~A} wheel has mass of the rim 1 kg1 {~kg}, having 50 spokes each of mass 5 g5 {~g}. The radius of the wheel is 40 cm40 {~cm}. The moment of inertia
View answer and explanation
Correct option: C
0.173 kg−m20.173 {~kg}-{m}^2
Option C (0.173 kg−m2{kg}-{m}^2) is correct because the moment of inertia is calculated by summing the moment of inertia of the rim and the spokes.
58 Medium
58 of 239
Application +4 | -1
Four particles of masses m,2m,3m and 4m are arranged at the corners of a parallelogram with each inside equal to a and one of the angle between two adjacent sides is 600{60^0}. The parallelogram lies in the x-y plane with mass m at the origin and 4m on the x-axis. The centre of mass of the arrangement will be located at
View answer and explanation
Correct option: B
(0.95a,34a)\left( {0.95a,\frac{{\sqrt 3 }}{4}a} \right)
Option B (0.95a,34a)\left( {0.95a,\frac{{\sqrt 3 }}{4}a} \right) is correct because it is the calculated center of mass based on the given mass distribution and geometry.
59 Easy
59 of 239
Understanding +4 | -1
What are the coordinates of centre of mass of a point mass of 2 kg2 {~kg} with coordinates (2,3)(2,3) ?
View answer and explanation
Correct option: D
(2,3)(2,3)
Option D ((2,3)) is correct because the coordinates of the center of mass of a single point mass are the same as the coordinates of the point mass itself.
60 Medium
60 of 239
Understanding +4 | -1
The principle of conservation of angular momentum, states that angular momentum
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the principle of conservation of angular momentum states that angular momentum remains constant when the net torque acting on the system is zero.
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