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NEET UG PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1
A body of mass 1 kg is rotating in a vertical circle of radius 1m. What will be the difference in its kinetic energy at the top and bottom of the circle? (Take g=10  ms−2\mathrm{g} = 10\mathrm{\;m}{\mathrm{s}^{ - 2}})
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Correct option: B
20 J
Option B (20 J) is correct because the difference in kinetic energy between the top and bottom of the circle is equal to the change in potential energy, which is 2mgR2mgR.

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