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NEET • PHYSICS • NUCLEI

Nuclei practice · Mixed difficulty

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Showing 151-180 of 210 questions

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151 Medium
151 of 210
Remembering +4 | -1
What is used as a moderator in a nuclear reactor?
View answer and explanation
Correct option: B
Graphite
Option B (Graphite) is correct because graphite is commonly used as a moderator in nuclear reactors to slow down neutrons, increasing the probability of nuclear fission.
152 Medium
152 of 210
Understanding +4 | -1
The nuclei of which of the following pairs of nuclei are isotones
View answer and explanation
Correct option: A
34Se74,  31Ca71_{34}S{e^{74}},\,{\,_{31}}C{a^{71}}
Option A (34Se74,  31Ca71_{34}S{e^{74}},\,{\,_{31}}C{a^{71}}) is correct because both nuclei have the same number of neutrons (40).
153 Medium
153 of 210
Understanding +4 | -1
During the β−decay\mathrm{\beta } - \mathrm{decay}
View answer and explanation
Correct option: D
A neutron in the nucleus decays emitting an electron
Option D is correct because during beta decay, a neutron within the nucleus transforms into a proton, emitting an electron and an antineutrino.
154 Medium
154 of 210
Application +4 | -1
How much energy must a gamma ray photon have, if it is to materialize into a pair of electron and positron with each particle having a K.E of 1MeV?
View answer and explanation
Correct option: B
3.02 MeV
Option B is correct because the gamma ray photon must have enough energy to create the mass of the electron and positron, plus provide their kinetic energies. The rest mass energy of an electron or positron is 0.51 MeV.
155 Easy
155 of 210
Application +4 | -1
A nucleus of mass number 189 splits into two nuclei having mass number 125 and 64. The ratio of radius of two daughter nuclei respectively is
View answer and explanation
Correct option: D
0.211111111
Option A (1.052777778) is incorrect. The correct ratio is 5/4 = 1.25. The student likely made a calculation error or used an incorrect formula.
156 Medium
156 of 210
Remembering +4 | -1
Neutrino emission in β−decay\mathrm{\beta } - \mathrm{decay} was predicted theoretically by
View answer and explanation
Correct option: D
Pauli
Option D is correct because Wolfgang Pauli proposed the existence of the neutrino to explain the continuous energy spectrum of beta particles in beta decay.
157 Medium
157 of 210
Understanding +4 | -1
During a nuclear fusion reaction
View answer and explanation
Correct option: D
Two light nuceli combine to give a heavier nucleus and possible other products
Option D is correct because nuclear fusion involves the combination of two light nuclei to form a heavier nucleus, releasing energy in the process, as seen in the sun's core.
158 Medium
158 of 210
Understanding +4 | -1
The correct order of ionizing capacity of α,β\alpha ,\beta and γ−\gamma - rays is
View answer and explanation
Correct option: B
α>β>γ\alpha > \beta > \gamma
Option B (α>β>γ\alpha > \beta > \gamma) is correct because alpha particles have the highest ionizing capacity due to their large charge and mass, followed by beta particles, and then gamma rays.
159 Medium
159 of 210
Remembering +4 | -1
The approximate nuclear radius is proportional to (AA is the mass number and ZZ the atomic number)
View answer and explanation
Correct option: B
A1/3{A^{1/3}}
Option B (A1/3{A^{1/3}}) is correct because the nuclear radius is directly proportional to the cube root of the mass number (A).
160 Easy
160 of 210
Application +4 | -1
A radioactive substance 84218X{ }_{84}^{218} {X} undergoes following decay:

84218X⟶α-Decay A⟶β−-Decay B⟶α-Decay C⟶β+−Decay D⟶γ-Decay Y{ }_{84}^{218} {X} \stackrel{\alpha \text {-Decay }}{\longrightarrow} {A} \stackrel{\beta^{-} \text {-Decay }}{\longrightarrow} {B} \stackrel{\alpha \text {-Decay }}{\longrightarrow} {C} \stackrel{\beta^{+}-\text {Decay }}{\longrightarrow} {D} \stackrel{\gamma \text {-Decay }}{\longrightarrow} {Y}

Then product Y{Y} is :
View answer and explanation
Correct option: B
80210Y{ }_{80}^{210} {Y}
Option B (80210Y{ }_{80}^{210} {Y}) is correct because after the series of decays, the atomic number decreases by 4 (2 from each alpha decay, +1 from beta-minus, -1 from beta-plus), and the mass number decreases by 8 (4 from each alpha decay).
161 Medium
161 of 210
Analyzing +4 | -1
A π0{\pi ^0} at rest decays into 2γ2\gamma rays, π0→γ+γ{\pi ^0} \to \gamma + \gamma. Then which of the following can happen
View answer and explanation
Correct option: B
The two γ′s\gamma 's move in opposite direction
Option B (The two γ′s\gamma 's move in opposite direction) is correct because momentum must be conserved, and since the pion was at rest, the photons must move in opposite directions with equal momentum.
162 Medium
162 of 210
Understanding +4 | -1
Some radioactive nucleus may emit
View answer and explanation
Correct option: A
Only one α,β\alpha ,\beta or γ\gamma at a time
Option A (Only one α,β\alpha ,\beta or γ\gamma at a time) is correct because a radioactive nucleus typically emits only one type of particle (α\alpha, β\beta, or γ\gamma) during a single decay event.
163 Medium
163 of 210
Remembering +4 | -1
Half life of radioactive element depends upon
View answer and explanation
Correct option: D
Nature of element
Option D is correct because the half-life of a radioactive element is an intrinsic property determined by the structure of its nucleus, which is independent of external factors like amount, temperature, or pressure.
164 Medium
164 of 210
Remembering +4 | -1
The functions of moderators in nuclear reactor is to
View answer and explanation
Correct option: A
Decrease the speed of neutrons
The function of moderators in a nuclear reactor is to decrease the speed of neutrons, making them more likely to be captured by the fuel nuclei.
165 Medium
165 of 210
Remembering +4 | -1
Which of the following isotopes is normally fissionable
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Correct option: C
92U235_{92}{U^{235}}
Option A (Controlled chain reaction) is correct because atomic reactors rely on a controlled chain reaction to generate energy safely and sustainably.
166 Easy
166 of 210
Remembering +4 | -1
The penetrating power of α\alpha-rays is
View answer and explanation
Correct option: B
Maximum
Option A is correct because alpha particles are heavy and doubly charged, leading to significant ionization and energy loss, thus having minimum penetrating power.
167 Medium
167 of 210
Remembering +4 | -1
One Becquerel is defined as
View answer and explanation
Correct option: A
1\mathrm{1} disintegration per sec
Option A (1 disintegration per sec) is correct because one Becquerel (Bq) is defined as one disintegration per second.
168 Medium
168 of 210
Application +4 | -1
In the following reaction
12Mg24+2He4→14SiX+0n1,X_{12}M{g^{24}}{ + _2}H{e^4}{ \to _{14}}S{i^X}{ + _0}{n^1},X is
View answer and explanation
Correct option: B
27\mathrm{27}
Balancing the mass numbers in the nuclear reaction gives X = 27.
169 Medium
169 of 210
Understanding +4 | -1
Two lithium nuclei in a lithium vapour at room temperature do not combine to form a carbon nucleus because
View answer and explanation
Correct option: B
It is not energetically favourable
Option B (It is not energetically favourable) is correct because the fusion of lithium nuclei requires overcoming a significant energy barrier, which is not readily available at room temperature.
170 Medium
170 of 210
Analyzing +4 | -1
If the total binding energies of 12H,24He,2656Fe&92235U{ }_1^2 \mathrm{H},{ }_2^4 \mathrm{He},{ }_{26}^{56} \mathrm{Fe} \&{ }_{92}^{235} \mathrm{U} nuclei are 2.22,28.3,4922.22,28.3,492 and 1786 MeV1786 \mathrm{~MeV} respectively, identify the most stable nucleus of the following.
View answer and explanation
Correct option: A
2656Fe{ }_{26}^{56} \mathrm{Fe}
Option A is correct because the most stable nucleus has the highest binding energy per nucleon, and Fe-56 has the highest value among the given options.
171 Medium
171 of 210
Remembering +4 | -1
Isotopes are atoms having
View answer and explanation
Correct option: A
Same number of protons but different number of neutrons
Option A (Same number of protons but different number of neutrons) is correct because isotopes of an element have the same atomic number (number of protons) but different mass numbers (different number of neutrons).
172 Medium
172 of 210
Understanding +4 | -1
92U235_{92}{\mathrm{U}^{235}} and 92U238_{92}{\mathrm{U}^{238}} differ as
View answer and explanation
Correct option: C
92U238_{92}{\mathrm{U}^{238}} has 3\mathrm{3} neutrons more
Option C (92U238_{92}{\mathrm{U}^{238}} has 3\mathrm{3} neutrons more) is correct because isotopes of an element have the same number of protons but different numbers of neutrons. 238U^{238}U has 3 more neutrons than 235U^{235}U (238-92 = 146 vs 235-92 = 143, difference is 3).
173 Medium
173 of 210
Understanding +4 | -1
Which of these is a fusion reaction
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Correct option: A
13H+12H=24He+01n_1^3H + _1^2H = _2^4He + _0^1n
Option A is the correct fusion reaction because it shows the combination of two light nuclei (Hydrogen isotopes) to form a heavier nucleus (Helium) and a neutron.
174 Hard
174 of 210
Application +4 | -1
Find out the mass of Uranium required per day to operate 0.95 MW nuclear power plant using 92U235_{92}{U^{235}} fission.
View answer and explanation
Correct option: A
1 gm
Option A (1 gm) is correct because the mass of Uranium required is calculated based on the power plant's energy output and the energy released per fission.
175 Easy
175 of 210
Understanding +4 | -1
Statement-I: The BE per nucleon of the fused heavier nuclei is more than the B.E per nucleon of the lighter nuclei.

Statement-II: The final system is more tightly bound to the initial system.
View answer and explanation
Correct option: A
Statement-I and Statement-II are true
Option A (Statement-I and Statement-II are true) is correct because fusion results in heavier nuclei with higher binding energy per nucleon, making the final system more tightly bound.
176 Medium
176 of 210
Remembering +4 | -1
Age of a tree is determined using radio-isotope of
View answer and explanation
Correct option: A
Carbon
Option A (Carbon) is correct because radiocarbon dating uses the radioactive isotope Carbon-14 to determine the age of organic materials, including trees.
177 Medium
177 of 210
Analyzing +4 | -1
A fission reaction is given by 92236U→54140Xe+3894Sr+x+y,{ }_{92}^{236} {U} \rightarrow{ }_{54}^{140}{Xe}+{ }_{38}^{94} {Sr}+x+y, where x{x} and y{y} are two particles. Considering 92236U{ }_{92}^{236} U being at rest, the kinetic energies of the products are denoted by KXe,KSr,Kx(2 MeV){K}_{X e}, K_{S r}, K_x(2 \mathrm{~MeV}) and Ky(2 MeV),K_y(2 \mathrm{~MeV}), respectively. Let the binding energies per nucleon of 92236U,54140Xe,3894Sr{ }_{92}^{236} {U},{ }_{54}^{140} {Xe},{ }_{38}^{94} {Sr} be 7.5 MeV,8.5 MeV7.5 \mathrm{~MeV}, 8.5 \mathrm{~MeV} and 8.5 MeV8.5 \mathrm{~MeV} respectively. Considering different conservation laws, the correct option is
View answer and explanation
Correct option: A
x=n,y=n,KSr=129 MeV,KXe=86 MeVx=n, y=n, K_{S r}=129 \mathrm{~MeV}, K_{X e}=86 \mathrm{~MeV}
Option A is correct because it satisfies both charge and baryon number conservation, and the kinetic energies are consistent with the energy released in the fission process.
178 Easy
178 of 210
Analyzing +4 | -1
Which of the following sequence for the emission of radioactive radiations are followed for a given reaction?

zXA⟶z+1YA⟶z−1 KA−4⟶z−1 KA−4{ }_{\mathrm{z}} \mathrm{X}^{\mathrm{A}} \longrightarrow{ }_{\mathrm{z}+1} \mathrm{Y}^{\mathrm{A}} \longrightarrow { }_{\mathrm{z}-1} \mathrm{~K}^{\mathrm{A}-4} \longrightarrow { }_{\mathrm{z}-1} \mathrm{~K}^{\mathrm{A}-4}
View answer and explanation
Correct option: B
β,α,γ\beta, \alpha, \gamma
Option B (β,α,γ\beta, \alpha, \gamma) is correct because the first decay increases the atomic number by 1 (beta decay), the second reduces the mass number by 4 and atomic number by 2 (alpha decay), and the third does not change either (gamma decay).
179 Easy
179 of 210
Understanding +4 | -1
After one α\alpha-decay and two consecutive β\beta-decays, the daughter nucleus is an isotope of the
View answer and explanation
Correct option: A
same element
Option A is correct because an alpha decay reduces the atomic number by 2, and each beta decay increases it by 1. Thus, after one alpha and two beta decays, the atomic number is the same as the original element, making it an isotope.
180 Easy
180 of 210
Application +4 | -1
If the mass defect during the formation of lithium from hydrogen is 0.5%0.5 \%, what will be the energy obtained in forming lithium from 1 kg1 \mathrm{~kg} of hydrogen?
View answer and explanation
Correct option: C
1.25×1081.25 \times 10^8
Option C (1.25×1081.25 \times 10^8) is correct because the energy is calculated using the mass defect and Einstein's mass-energy equivalence.
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