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NEET • PHYSICS • NUCLEI

Nuclei practice · Mixed difficulty

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91 Medium
91 of 210
Application +4 | -1
A radioactive element 92238U{}_{92}^{238}U undergoes successive radioactive decay and decays into 82206Pb{}_{82}^{206}Pb.The number of α  and  β\alpha\,\, \mathrm{ }and\mathrm{ }\,\,\beta particles emitted respectively are:
View answer and explanation
Correct option: C
8 and 6
Option C (8 and 6) is correct because the number of alpha and beta particles emitted can be determined by balancing the mass number and atomic number in the nuclear decay equation.
92 Medium
92 of 210
Analyzing +4 | -1
A radioactive decay chain starts from 92Np237_{92}N{p^{237}} produces 90Th229_{90}T{h^{229}} by successive emissions. The emitted particles can be
View answer and explanation
Correct option: A
Two α\alpha -particles and one β\beta -particle
Option A (Two α\alpha -particles and one β\beta -particle) is correct because it accounts for the change in atomic mass and atomic number from 92Np237_{92}N{p^{237}} to 90Th229_{90}T{h^{229}}.
93 Easy
93 of 210
Application +4 | -1
By how much fraction energy will be decreased in a given atomic explosion, if the speed of light were become 1/31 / 3 of the present value?
View answer and explanation
Correct option: A
8/98 / 9
Option A (8/98 / 9) is correct because the energy is proportional to the square of the speed of light, so reducing the speed of light to 1/3 reduces the energy to 1/9, resulting in a decrease of 8/9.
94 Easy
94 of 210
Application +4 | -1
r1   and   r2{r_1}\,\,\,{\text{and}}\,\,\,{r_2} are the radii of atomic nuclei of mass number 125 and 216 respectively. The ratio of r1r2\frac{{{r_1}}}{{{r_2}}} is
View answer and explanation
Correct option: B
56\frac{5}{6}
Option B (5/6) is correct because the ratio of the radii is proportional to the cube root of the ratio of the mass numbers.
95 Medium
95 of 210
Analyzing +4 | -1
An element AA decays into element CC by a two step process
A→B+2He4A \to B{ + _2}\mathrm{H}{\mathrm{e}^4}
B→C+2−1  e0B \to C + {2_{ - 1}}\,\,{e^0}
Then
View answer and explanation
Correct option: A
AA and CC are isotopes
Option A (AA and CC are isotopes) is correct because in the process, the mass number changes by 4-0 = 4 and the atomic number changes by 2-2 = 0. Therefore, A and C have the same atomic number but different mass numbers, making them isotopes.
96 Hard
96 of 210
Application +4 | -1
For l131{l^{131}}, half life is 8 days, the activity of an 8 μg8\,\mu g sample of l is
View answer and explanation
Correct option: B
3.18×1015 days−13.18 \times {10^{15}}\,day{s^{ - 1}}
Option B (3.18×1015 days−13.18 \times {10^{15}}\,day{s^{ - 1}}) is correct because it is calculated using the decay constant and the number of atoms in the sample.
97 Medium
97 of 210
Understanding +4 | -1
A free neutron decays spontaneously into
View answer and explanation
Correct option: A
A proton ,an electron and antineutrino
A free neutron decays into a proton, an electron, and an antineutrino to conserve charge, baryon number, and lepton number.
98 Easy
98 of 210
Application +4 | -1
The mass number of nucleus having radius equal
to half of the radius of nucleus with mass number
192 is
View answer and explanation
Correct option: D
24
Option D (24) is correct because the radius of a nucleus is proportional to the cube root of its mass number, and halving the radius reduces the mass number to one-eighth.
99 Medium
99 of 210
Application +4 | -1
In the nuclear reaction: X(n,α)3Li7X{\left( {n,\alpha } \right)_3}L{i^7} the term XX will be
View answer and explanation
Correct option: A
5B10_5{B^{10}}
Option A (5B10_5{B^{10}}) is correct because it balances the nuclear reaction equation, ensuring that the atomic numbers and mass numbers are conserved on both sides.
100 Medium
100 of 210
Remembering +4 | -1
The rest energy of an electron is
View answer and explanation
Correct option: A
510  KeV510\,\,KeV
Option A (510 KeV510 \,KeV) is correct because the rest energy of an electron is calculated using Einstein's mass-energy equivalence formula, E=mc².
101 Medium
101 of 210
Remembering +4 | -1
The subatomic particles proton and neutron fall under the group of
View answer and explanation
Correct option: D
Baryons
Protons and neutrons are classified as baryons because they are heavy particles made up of three quarks.
102 Hard
102 of 210
Analyzing +4 | -1
Let An{A}_{{n}} be the area enclosed by the n{n}th orbit in a hydrogen atom. The graph of ln⁡(AnA1)\ln \left(\frac{{A_n}}{{A_1}}\right) against ln⁡(n)\ln {(n})
View answer and explanation
Correct option: A
Will pass through the origin
Option A (Will pass through the origin) is correct because the area enclosed by the nth orbit is proportional to n², and when n=1, the logarithm of the ratio is zero.
103 Hard
103 of 210
Application +4 | -1
A sample of radioactive material can decay by two processes AA and BB with half-lives 12\frac{1}{2} hour and 14\frac{1}{4} bour respectively. Now, the radioactive sample decays for 7 hour in such a way that for 1 hour it decays according to process A{A} and for next hour decays according to B{B} and this decaying with different processes in alternate hours continues upto 6 hour and then, in 7th7^{\text {th}} hour, it decays simultaneously with both the processes. If N0{N}_0 nuclei of sample are present at t=0t=0, then number of radioactive nuclei after 7 hour would be
View answer and explanation
Correct option: B
N0224\frac{{N}_0}{2^{24}}
Option B (N0224\frac{{N}_0}{2^{24}}) is correct because it accounts for the decay during alternating hours with different half-lives and the final hour with both processes.
104 Medium
104 of 210
Application +4 | -1
The number of revolutions per second made by an electron in the first Bohr orbit of hydrogen atom is of the order of
View answer and explanation
Correct option: D
1015{10^{15}}
Option D (1015{10^{15}}) is correct because the frequency is proportional to the electron's velocity and inversely proportional to the orbital radius.
105 Medium
105 of 210
Understanding +4 | -1
For uranium nucleus how does its mass vary with volume?
View answer and explanation
Correct option: A
m∝Vm \propto V
Option A (m∝Vm \propto V) is correct because the mass of a nucleus is directly proportional to its volume, assuming constant density.
106 Easy
106 of 210
Understanding +4 | -1
From the statements given below:
(A) The angular momentum of an electron in nthn^{\text {th}} orbit is an integral multiple of hh.
(B) Nuclear forces do not obey inverse square law.
(C) Nuclear forces are spin dependent.
(D) Nuclear forces are central and charge independent.
(E) Stability of nucleus is inversely proportional to the value of packing fraction.
Choose the correct answer from the options given below:
View answer and explanation
Correct option: D
(A), (B), (C), (E) only
Option D ((A), (B), (C), (E) only) is correct because angular momentum is quantized, nuclear forces don't obey the inverse square law, they are spin-dependent, and stability is inversely proportional to packing fraction.
107 Medium
107 of 210
Application +4 | -1
A freshly prepared radioactive sample having half life 4 hours, emits radiation of intensity which is 64 times the permissible level. The minimum time in hours after which it is safe to work with the source will be
View answer and explanation
Correct option: B
24 hours
Option B (24 hours) is correct because it represents the time required for the radiation intensity to reduce to the permissible level, calculated using the concept of half-life.
108 Medium
108 of 210
Application +4 | -1
The end product of the decay of 90Th232  is  82Pb208_{90}\mathrm{T}{\mathrm{h}^{232}}\,\,\mathrm{is}\,{\,_{82}}\mathrm{P}{\mathrm{b}^{208}}. The number of α  and  β\alpha \,\,\mathrm{and}\,\,\beta-particles emitted are respectively
View answer and explanation
Correct option: A
6,4\mathrm{6,4}
Option A (6,4\mathrm{6,4}) is correct because each alpha particle emission reduces the mass number by 4 and the atomic number by 2, while each beta-minus particle emission increases the atomic number by 1.
109 Medium
109 of 210
Application +4 | -1
A nucleus zXA_z{X^A} emits an α\mathrm{\alpha }-particle. The resultant nucleus emits a β+{\mathrm{\beta }^ + } particle. The respective atomic and mass numbers of the final nucleus will be
View answer and explanation
Correct option: A
Z−3,A−4Z - 3,A - 4
Option A (Z−3,A−4Z - 3,A - 4) is correct because alpha emission reduces the atomic number by 2 and the mass number by 4, while beta-plus emission reduces the atomic number by 1 and leaves the mass number unchanged.
110 Medium
110 of 210
Remembering +4 | -1
If MM is the atomic mass and AA is the mass number, packing fraction is given by
View answer and explanation
Correct option: B
M−AA\frac{{M - A}}{A}
Option B is correct because the packing fraction is defined as the difference between the atomic mass (M) and the mass number (A), divided by the mass number (A).
111 Medium
111 of 210
Understanding +4 | -1
The fussion process is possible at high temperatures, because at higher temperatures
View answer and explanation
Correct option: D
The nucleus get sufficient energy to overcome the strong forces of repulsion
The correct answer is D because at high temperatures, nuclei gain sufficient kinetic energy to overcome the electrostatic repulsion and allow fusion to occur.
112 Medium
112 of 210
Understanding +4 | -1
Pick out the correct statement from the following.
View answer and explanation
Correct option: B
Packing fraction may be positive or may be negative
Option B (Packing fraction may be positive or may be negative) is correct because the packing fraction can be either positive or negative depending on whether the actual mass is greater or less than the mass number.
113 Easy
113 of 210
Application +4 | -1
Binding energy of a certain nucleus is 18×108 J18 \times 10^8 \mathrm{~J}. How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:
View answer and explanation
Correct option: B
20 μg20\,\mu \mathrm{g}
Option B (20 μg20 \,\mu \mathrm{g}) is correct because it represents the mass equivalent of the given binding energy, calculated using E=mc2E=mc^2.
114 Easy
114 of 210
Application +4 | -1
The velocity of alpha particles from polonium (atomic weight 210) is 1.6×107 m/sec1.6 \times 10^7 \mathrm{~m} / \mathrm{sec}. What is the velocity of recoil atoms?
View answer and explanation
Correct option: B
3.1×105 m/sec3.1 \times 10^5 \mathrm{~m} / \mathrm{sec}
Option B (3.1×105 m/sec3.1 \times 10^5 \mathrm{~m} / \mathrm{sec}) is correct because the recoil velocity can be calculated using the conservation of momentum. The momentum of the alpha particle equals the momentum of the recoil atom.
115 Medium
115 of 210
Remembering +4 | -1
Atomic number of a nucleus is ZZ and atomic mass is MM. The number of neutron is
View answer and explanation
Correct option: A
M−ZM - Z
Option A (M−ZM - Z) is correct because the number of neutrons is the difference between the mass number (M) and the atomic number (Z).
116 Hard
116 of 210
Application +4 | -1
In the nuclear reaction
1H2+1H2⟶2He3+0n1{ }_1 {H}^2+{ }_1 {H}^2 \longrightarrow{ }_2 {He}^3+{ }_0 n^1

Mass of deuterium atom =2.014741 amu=2.014741 \,\mathrm{amu}, Mass of 2He3{ }_2 {He}^3 atom =3.016977 amu=3.016977 \mathrm{~amu}, and Mass of neutron =1.008987 amu.=1.008987 \mathrm{~amu}.
The QQ-value of the reaction will be:
View answer and explanation
Correct option: B
3.27 MeV3.27 \mathrm{~MeV}
Option B (3.27 MeV3.27 \mathrm{~MeV}) is correct because the Q-value is calculated from the mass difference between reactants and products.
117 Medium
117 of 210
Application +4 | -1
The ratio of the energies of the hydrogen atom in its first to second excited state is
View answer and explanation
Correct option: C
9/4\mathrm{9/4}
Option C (9/4\mathrm{9/4}) is correct because the energy of a hydrogen atom is inversely proportional to the square of the principal quantum number.
118 Medium
118 of 210
Analyzing +4 | -1
Assertion: Mass defect in nuclear reactions is less than 1%1 \%.

Reason: In nuclear reaction, change in BE/N is generally less than 1%1\%.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
Option A is correct because the mass defect is related to the binding energy per nucleon, and changes in binding energy per nucleon are typically less than 1% in nuclear reactions.
119 Medium
119 of 210
Application +4 | -1
The radius of a nucleus with atomic mass number 7\mathrm{7} is 2  fermi\mathrm{2}\,\,\mathrm{fermi}. Find the radius of nucleus with atomic number 189\mathrm{189}.
View answer and explanation
Correct option: D
6  fermi\mathrm{6}\,\,\mathrm{fermi}
Option D (6 fermi\mathrm{6}\,\mathrm{fermi}) is correct because the nuclear radius is proportional to the cube root of the mass number.
120 Easy
120 of 210
Understanding +4 | -1
Fpp,FnnF_{p p}, F_{n n} and FnpF_{n p} are the nuclear forces between proton -proton, neuron-neuron and neuron- proton respectively. Then relation between them is
View answer and explanation
Correct option: C
Fpp=Fnn=FnpF_{p p}=F_{n n}=F_{n p}
Option C (Fpp=Fnn=FnpF_{p p}=F_{n n}=F_{n p}) is correct because the nuclear force is charge-independent, meaning it acts equally between proton-proton, neutron-neutron, and neutron-proton pairs.
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