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NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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Showing 181-210 of 303 questions

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181 Medium
181 of 303
Understanding +4 | -1
Assertion: The magnitude of the resultant of two vectors P⃗\vec{P} and Q⃗\vec{Q} is maximum (P+Q)(P+Q), when the two vectors act in the same direction and minimum (P−Q)(P-Q), when they act in opposite directions.

Reason: The resultant of two vectors can be found by using the relation

R=P2+Q2+2PQcos⁡θR=\sqrt{P^2+Q^2+2 P Q \cos \theta}
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not
correct explanation of the assertion.
Option B (If both assertion and reason are true but reason is not correct explanation of the assertion) is correct because both the assertion about maximum and minimum resultant magnitudes and the reason stating the formula for resultant magnitude are true, but the formula doesn't directly explain the assertion.
182 Medium
182 of 303
Application +4 | -1
A boat can travel at a speed of 8 kmph in still water on a lake. In the flowing water of a stream, it can move at 8kmph relative to the water in the stream. If the stream speed is 3kmph, how fast can the boat move past a tree on the shore in travelling (i) upstream (ii) downstream?
View answer and explanation
Correct option: A
5 kmph and 11 kmph
Option A (5 kmph and 11 kmph) is correct because it accurately calculates the boat's speed relative to the shore both upstream and downstream by considering the stream's effect.
183 Medium
183 of 303
Understanding +4 | -1
Assertion: The time taken by a boat to cover a certain distance upstream is more than the time taken to cover the same distance downstream.

Reason: The speed of the boat is lesser while moving upstream as compared to downstream due to the speed of the stream.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A is correct because the effective speed is lower upstream and higher downstream, leading to longer travel time upstream.
184 Easy
184 of 303
Application +4 | -1
What is the angle between (i+j) \left( {i + j} \right)\, and (kˉ+jˉ)\left( {\bar k + \bar j} \right)?
View answer and explanation
Correct option: B
60∘60^\circ
Option B is correct because the angle between the two vectors is 60 degrees, which can be found using the dot product formula.
185 Medium
185 of 303
Analyzing +4 | -1
Of the vectors given below, the parallel vectors are,

A⃗=6i^+8j^B⃗=210i^+280k^C⃗=5.1i^+6.8j^D⃗=3.6i^+6j^+48k^\begin{aligned} & \vec{A}=6 \hat{i}+8 \hat{j} \\ & \vec{B}=210 \hat{i}+280 \hat{k} \\ & \vec{C}=5.1 \hat{i}+6.8 \hat{j} \\ & \vec{D}=3.6 \hat{i}+6 \hat{j}+48 \hat{k} \end{aligned}
View answer and explanation
Correct option: B
A→\overrightarrow{\mathrm{A}} and C→\overrightarrow{\mathrm{C}}
Option B (A→\overrightarrow{\mathrm{A}} and C→\overrightarrow{\mathrm{C}}) is correct because parallel vectors have proportional components, and the ratio of the components of A and C are equal.
186 Medium
186 of 303
Application +4 | -1
GivenP⃗.Q⃗=0 then ∣P⃗×Q⃗∣ is\mathrm{\vec P}\mathrm{.\vec Q} = 0\,then\,\left| {\mathrm{\vec P} \times \mathrm{\vec Q}} \right|\,is
View answer and explanation
Correct option: A
∣P⃗∣∣Q⃗∣\left| {\mathrm{\vec P}} \right|\left| {\mathrm{\vec Q}} \right|
Option A (∣P⃗∣∣Q⃗∣\left| \mathrm{\vec P} \right|\left| \mathrm{\vec Q} \right|) is correct because if the dot product of two vectors is zero, they are perpendicular, and the magnitude of their cross product is the product of their magnitudes.
187 Medium
187 of 303
Application +4 | -1
The resultant of two vector of equal magnitude is twice of magnitude of either of the vectors the angle between them is
View answer and explanation
Correct option: C
00{0^0}
Option C (00{0^0}) is correct because if the resultant of two vectors of equal magnitude is twice the magnitude of either vector, the vectors must be in the same direction, hence the angle is 0 degrees.
188 Medium
188 of 303
Application +4 | -1
The adjacent sides of a parallelogram are represented by co-initial vectors 2i^+3j^ and i^+4j^2\hat i + 3\hat j\,and\,\hat i + 4\hat j. The area of the parallelogram is
View answer and explanation
Correct option: A
5 units along z- axis
Option A (5 units along z- axis) is correct because the area of the parallelogram is the magnitude of the cross product of the vectors, which results in a vector along the z-axis.
189 Hard
189 of 303
Analyzing +4 | -1
The xx and yy-coordinates of a particle moving in a plane are given by x(t)=acos⁡(pt)x(t)=a \cos (p t) and y(t)=bsin⁡(pt)y(t)=b \sin (p t), where a,b(<a)a, b( < a) and pp are positive constants of appropriate dimensions and tt is time. Then, which of the following is not true?
View answer and explanation
Correct option: D
Distance travelled by the particle in time interval between t=0t=0 and t=π2pt=\frac{\pi}{2 p} is aa.
Option D is correct. The distance traveled by the particle in the given time interval is not simply 'a' because the motion is elliptical, not linear.
190 Medium
190 of 303
Application +4 | -1
If the vector A⃗=2i^+4j^  and  B⃗=5i^+pj^\mathrm{\vec A} = 2\hat i + 4\hat j\,\,and\,\,\mathrm{\vec B} = 5\hat i + \mathrm{p\hat j} are parallel to each other, the magnitude of B⃗\mathrm{\vec B} is
View answer and explanation
Correct option: A
555\sqrt 5
Option A (555\sqrt 5) is correct because parallel vectors have proportional components, allowing us to determine 'p' and then the magnitude of B.
191 Hard
191 of 303
Application +4 | -1
The retardation experienced by a moving motor boat, after its engine is cut off, is given by dudt=−kv3,\frac{{du}}{{dt}} = - k{v^3},, where k is a constant. If v0{v_0} is the magnitude of the velocity at cut-off, the magnitude of the velocity at time t after the cut-off is
View answer and explanation
Correct option: D
v02v02kt+1\frac{{{v_0}}}{{\sqrt {2v_0^2kt + 1} }}
Option D is correct because it's derived by integrating the given retardation equation and applying the initial condition.
192 Easy
192 of 303
Understanding +4 | -1
Magnitude of component of vector 2i^+6k^2 \hat{i}+6 \hat{k} along yy-axis is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the component of a vector along an axis is zero if the vector has no projection onto that axis. The given vector has no y-component.
193 Medium
193 of 303
Application +4 | -1
If A→=2i^+3j^+4k^  and  B⃗=4i^+3j^+2k^\overrightarrow A = 2\hat i + 3\hat j + 4\hat k\,\,and\,\,\mathrm{\vec B} = 4\hat i + 3\hat j + 2\hat k, then angle between A→\overrightarrow A and B⃗\mathrm{\vec B} is
View answer and explanation
Correct option: C
cos⁡−1(25/29){\cos ^{ - 1}}\left( {25/29} \right)
Option C (cos⁡−1(25/29){\cos ^{ - 1}}\left( {25/29} \right)) is correct because it is the angle between the two vectors calculated using the dot product formula.
194 Easy
194 of 303
Analyzing +4 | -1
Two stones are projected so as to reach the same distance from the point of projection on a horizontal surface. The maximum height reached by one exceeds the other by an amount equal to half the sum of the height attained by them. Then, angle of projection of the stone which attains smaller height is
View answer and explanation
Correct option: C
30∘30^{\circ}
Option C (30∘30^{\circ}) is correct because it satisfies the condition where the maximum height difference is half the sum of the maximum heights, given equal ranges.
195 Easy
195 of 303
Application +4 | -1
A ball is projected with kinetic energy EE at an angle of 45∘45^\circ to the horizontal. At the highest point during its flight, its kinetic energy will be
View answer and explanation
Correct option: B
E/2E/2
Option B (E/2E/2) is correct because at the highest point, only the horizontal component of velocity remains, and the kinetic energy is reduced by half.
196 Medium
196 of 303
Application +4 | -1
If A⃗.B⃗=3∣A⃗×B⃗∣\vec A.\vec B = \sqrt 3 \left| {\vec A \times \vec B} \right| then angle between A⃗\vec A and B⃗\vec B will be
View answer and explanation
Correct option: A
π6\frac{\pi }{6}
Option A (π6\frac{\pi }{6}) is correct because it is derived from the relationship between the dot product and cross product magnitudes, where tan⁡θ=13\tan \theta = \frac{1}{\sqrt{3}}.
197 Hard
197 of 303
Analyzing +4 | -1
Two vectors A⃗ and B⃗\mathrm{\vec A}\,and\,\mathrm{\vec B} are inclined at an angle θ\theta. Now if the vectors are interchanged then the resultant turns through an angle β\beta. Which of the following relation is true
View answer and explanation
Correct option: B
tan⁡α2=(A−BA+B)tan⁡θ2\tan \frac{\alpha }{2} = {\left( {\frac{{A - B}}{{A + B}}} \right)}\tan \frac{\mathrm{\theta }}{2}
Option B is correct because it represents the correct relationship between the angle of the resultant and the angle between the vectors when they are interchanged.
198 Medium
198 of 303
Analyzing +4 | -1
Let a→+b→+c→=0→,∣a→∣=3,∣b→∣=4,∣c→∣=5\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}+\overrightarrow{\mathrm{c}}=\overrightarrow{0},|\overrightarrow{\mathrm{a}}|=3,|\overrightarrow{\mathrm{b}}|=4,|\overrightarrow{\mathrm{c}}|=5
Statement-I: Angle between a⃗\vec{\mathrm{a}} and b⃗\vec{\mathrm{b}} is π2\frac{\pi}{2}
Statement-II: ∣a→+b→∣2=∣a→∣2+∣b→∣2+2∣a→⋅b→∣|\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}|^2=|\overrightarrow{\mathrm{a}}|^2+|\overrightarrow{\mathrm{b}}|^2+2|\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{b}}|
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because both statements are individually true and relevant to vector algebra.
199 Hard
199 of 303
Application +4 | -1
At what angle must the two forces (x+y)(x+y) and (x−y)(x-y) act, so that the resultant may be x2+y2\sqrt{x^2+y^2} ?
View answer and explanation
Correct option: A
cos⁡−1[−x2+y22(x2−y2)]\cos ^{-1}\left[-\frac{x^2+y^2}{2\left(x^2-y^2\right)}\right]
Option A (cos⁡−1[−x2+y22(x2−y2)]\cos ^{-1}\left[-\frac{x^2+y^2}{2\left(x^2-y^2\right)}\right]) is correct because it is derived from the law of cosines, solving for the angle between the two forces.
200 Medium
200 of 303
Remembering +4 | -1
Which of the following statement is correct?
View answer and explanation
Correct option: A
Displacing a vector parallel to itself leaves the vector unchanged
Displacing a vector parallel to itself leaves the vector unchanged. This is a fundamental property of vectors.
201 Easy
201 of 303
Understanding +4 | -1
Statement-I: Angle between i^+j^\hat{i}+\hat{j} and i^\hat{i} is 45∘45^{\circ}.
Statement-II: i^+j^\hat{i}+\hat{j} is equally inclined to both i^\hat{i} and j^\hat{j} and the angle between i^\hat{i} and j^\hat{j} is 90∘90^{\circ}
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct because the angle between i^+j^\hat{i}+\hat{j} and i^\hat{i} is indeed 45 degrees, and the second statement correctly explains why.
202 Easy
202 of 303
Understanding +4 | -1
Which of the following statement is true?
View answer and explanation
Correct option: B
When the coordinate axes are rotated through some angle, components of the vector change but the vector's magnitude remains constant.
Option B is correct because rotating the coordinate axes changes the components of a vector, but its magnitude remains invariant.
203 Easy
203 of 303
Application +4 | -1
A body throws a ball with a velocity of 15 m/s at an angle of 15∘15^\circ with the horizontal. The distance at which the ball strikes the ground is
View answer and explanation
Correct option: D
11.25 m
Option D (11.25 m) is correct because the range is calculated using the initial velocity, angle of projection, and acceleration due to gravity.
204 Medium
204 of 303
Application +4 | -1
If 0.5i^+0.8j^+ck^0.5\hat i + 0.8\hat j + \mathrm{c\hat k} is a unit vector, then the value of c is
View answer and explanation
Correct option: A
0.11\sqrt {0.11}
Option A (0.11\sqrt {0.11}) is correct because the magnitude of a unit vector must be 1, and this value of c satisfies that condition.
205 Easy
205 of 303
Application +4 | -1
The angle made by the vector A⃗=i^+j^ \vec A = \hat i + \hat j\, with y-axis is
View answer and explanation
Correct option: B
45∘45^\circ
The angle made by a vector with the y-axis can be found using the arctangent function. Since the x and y components are equal, the angle with the y-axis is 45 degrees, making option B correct.
206 Easy
206 of 303
Understanding +4 | -1
A vector is added to an equal and opposite vector of similar nature, forms a
View answer and explanation
Correct option: C
null vector
Option C (null vector) is correct because adding a vector to its equal and opposite results in a vector with zero magnitude, which is a null vector.
207 Medium
207 of 303
Understanding +4 | -1
Statement-I: A null vector is a vector whose magnitude is zero and direction is arbitrary.
Statement-II: A null vector does not exist.
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B (Statement-I is true and statement-II is false) is correct because a null vector has zero magnitude and arbitrary direction, and therefore it exists.
208 Hard
208 of 303
Application +4 | -1
A vector perpendicular to the vector (i+2j)\left( {i + 2j} \right) and having magnitude 353\sqrt 5 units is
View answer and explanation
Correct option: B
6i−3j6i - 3j
Option B (6i−3j6i - 3j) is correct because it is perpendicular to the given vector and has the specified magnitude.
209 Easy
209 of 303
Understanding +4 | -1
At the top of the trajectory of a projectile, the acceleration is
View answer and explanation
Correct option: D
gg
Option D (gg) is correct because the acceleration of a projectile is always equal to the acceleration due to gravity, regardless of its position in the trajectory.
210 Easy
210 of 303
Application +4 | -1
If Aˉ=5i+7j−3k\bar A = 5i + 7j - 3k and Bˉ=2i+2j−ak\bar B = 2i + 2j - ak are perpendicular vectors. The value of aa is
View answer and explanation
Correct option: D
-8
Option D (-8) is correct because the dot product of two perpendicular vectors is zero, allowing us to solve for 'a'.
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