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NEET • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Easy

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31 Easy
31 of 61
Analyzing +4 | -1
Statement I : Two objects moving with velocities v1v_1 and v2v_2 in the opposite directions, have their relative velocity along the direction of the one with a larger velocity.

Statement II : The relative velocity between two bodies moving with velocity v1\mathbf{v}_1 and v2\mathbf{v}_2 in same direction is given by v=v1−v2\mathbf{v}=\mathbf{v}_1-\mathbf{v}_2
View answer and explanation
Correct option: D
Statement I is false, Statement II is true
Statement I is false, Statement II is true. Statement I is incorrect because the relative velocity's direction depends on the vector difference, not just the larger velocity. Statement II correctly defines relative velocity.
32 Easy
32 of 61
Application +4 | -1
A room has dimensions 3 m×4 m×5 m3\,m \times 4\,m \times 5\,m. A fly starting at one comer ends up at the diametrically opposite conner. The magnitude of the displacement of the fly is
View answer and explanation
Correct option: D
5 2 m5\,\sqrt 2 \,m
Option D (52 m5\sqrt 2 \,m) is correct because the displacement is the straight-line distance between opposite corners, calculated using the 3D distance formula: 32+42+52=50=52\sqrt{{3^2 + 4^2 + 5^2}} = \sqrt{{50}} = 5\sqrt{2}.
33 Easy
33 of 61
Analyzing +4 | -1
The distance travelled by a particle is directly proportional to t\sqrt{t}, where tt is time elapsed. Which of the following is correct regarding the motion of the particle?
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Correct option: C
Particle is moving with decreasing retardation
Particle is moving with decreasing retardation. Since distance is proportional to the square root of time, velocity decreases with time, implying retardation.
34 Easy
34 of 61
Application +4 | -1
A train is moving slowly on a straight track with a constant speed of 2 m s−12 \mathrm{~m} \mathrm{~s}^{-1}. A passenger in that train starts walking at a steady speed of 2 m s−12 \mathrm{~m} \mathrm{~s}^{-1} to the back of the train in the opposite direction of the motion of the train. So, to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be
View answer and explanation
Correct option: A
0
Option A (0) is correct because the passenger's velocity relative to the platform is the train's velocity minus the passenger's walking velocity, resulting in zero.
35 Easy
35 of 61
Understanding +4 | -1
If a body is moving along a straight path then which of the following is true?
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Correct option: C
Distance may be greater than the magnitude of displacement
Option A (Distance is always equal to magnitude of displacement) is incorrect. Option C (Distance may be greater than the magnitude of displacement) is correct because if the body changes direction, the distance covered will be greater than the magnitude of the displacement.
36 Easy
36 of 61
Application +4 | -1
A very large number of balls are thrown vertically upwards in quick succession in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is 5m, the number of ball thrown per minute is (take g=10  ms−2g = 10\;m{s^{ - 2}})
View answer and explanation
Correct option: C
60
Option C (60) is correct because the number of balls thrown per minute is calculated based on the time it takes for each ball to reach its maximum height.
37 Easy
37 of 61
Application +4 | -1
A hall has dimensions 10 m×12 m×14 m10\,m \times 12\,m \times 14\,m. A fly starting at one corner ends up at a diagonally opposite corner what is the magnitude of distance if it travels along three edges of hall
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Correct option: B
26 m
Option C (36 m) is correct because the fly travels along three edges, so the distance is the sum of the dimensions: 10 m + 12 m + 14 m = 36 m.
38 Easy
38 of 61
Understanding +4 | -1
A particle covers equal distance around a circular path, in equal intervals of time. Which of the following quantities connected with the motion of the particle remains constant with time?
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Correct option: C
Speed
Option C (Speed) is correct because speed is the magnitude of velocity, and if equal distances are covered in equal intervals of time, the speed remains constant.
39 Easy
39 of 61
Understanding +4 | -1
If an object is falling freely in vacuum, then body moves with
View answer and explanation
Correct option: B
Uniform acceleration
Option B (Uniform acceleration) is correct because the only force acting on the object is gravity, which produces a constant acceleration.
40 Easy
40 of 61
Understanding +4 | -1
A body is thrown vertically upwards with a velocity u. Find the true statement from the following
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Correct option: D
Velocity is zero at the highest point and maximum height reached is u2/2g{u^2}/2g
Option D (Velocity is zero at the highest point and maximum height reached is u2/2g{u^2}/2g) is correct because at the highest point, the velocity is momentarily zero, and the maximum height can be derived using kinematic equations.
41 Easy
41 of 61
Application +4 | -1
A particle covers half of its total distance with speed v1{v_1} and the rest half distance with speed v2{v_2}. Its average speed during the complete journey is
View answer and explanation
Correct option: D
2v1v2v1+v2\frac{{2{v_1}{v_2}}}{{{v_1} + {v_2}}}
Option D (2v1v2v1+v2\frac{{2{v_1}{v_2}}}{{{v_1} + {v_2}}}) is correct because the average speed is calculated by dividing the total distance by the total time, considering different speeds for each half of the distance.
42 Easy
42 of 61
Application +4 | -1
A police jeep is chasing a culprit going on a motor bike. The motor bike crosses a turning at a speed of 72 km/h. The jeep follows it a speed of 90 km/h crossing the turning ten seconds later than the bike. Assuming that they travel at constant speeds, how far from the turning will the jeep catch up with the bike? (in km)
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Correct option: A
1
Option A (1 km) is correct because it is calculated by equating the distances traveled by the jeep and the bike from the turning point.
43 Easy
43 of 61
Application +4 | -1
An object is projected upwards with a velocity of 100m/s. It will strike the ground after (approximately)
View answer and explanation
Correct option: B
20 sec
Option B (20 sec) is correct because the time of flight for a projectile is twice the time it takes to reach its maximum height, which can be calculated using kinematic equations.
44 Easy
44 of 61
Understanding +4 | -1
If distance covered by a particle is zero, what can you say about its displacement?
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Correct option: D
It must be zero
Option D (It must be zero) is correct because displacement is the shortest distance between the initial and final points, and if the total distance covered is zero, the object hasn't moved, meaning the displacement is also zero.
45 Easy
45 of 61
Application +4 | -1
A body is thrown vertically upward from a point AA 125 m125 \mathrm{~m} above the ground. It goes up to a maximum height of 250 m250 \mathrm{~m} above the ground and passes through AA on its downward journey. The velocity of the body when it is at a height of 70 m70 \mathrm{~m} above the ground is (Take, g=10 ms−2g=10 \mathrm{~ms}^{-2} )
View answer and explanation
Correct option: B
60 ms−160 \mathrm{~ms}^{-1}
Option B (60 ms−160 \text{{ ms}}^{-1}) is correct because the velocity is calculated using conservation of energy principles.
46 Easy
46 of 61
Application +4 | -1
For a body travelling with uniform acceleration, its final velocity is V=180−7xV = \sqrt {180 - 7x}, where xx is the distance travelled by the body then the acceleration is
View answer and explanation
Correct option: B
−3.5 m/s2- 3.5\,m/{s^2}
Option B ( - 3.5 m/s²) is correct because it is derived from differentiating the given velocity equation with respect to x and using the chain rule.
47 Easy
47 of 61
Application +4 | -1
A body falls for 5 s from rest. If the acceleration due to gravity of earth ceases to act, the distance it develops in the next 3 s is
View answer and explanation
Correct option: C
147 m
Option C (147 m) is correct because it accurately calculates the distance traveled at a constant velocity after the gravity ceases to act.
48 Easy
48 of 61
Understanding +4 | -1
A body thrown vertically upward with an initial velocity of 1.4 m/s returns in 2s. The total displacement of the ball is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the total displacement of the ball is zero since it returns to its starting point.
49 Easy
49 of 61
Application +4 | -1
If Position of a particle is given by x=(4t2−8t)x=\left(4 t^2-8 t\right), then which of the following is true?
View answer and explanation
Correct option: C
Velocity is zero at t=1 s\mathrm{t}=1 \mathrm{~s}
The correct answer is C (Velocity is zero at t=1 s) because the derivative of the position function, representing velocity, equals zero at t=1.
50 Easy
50 of 61
Analyzing +4 | -1
Assertion (A): Speed of a particle may decrease, even if acceleration is increasing.

Reason (R): This will happen if acceleration is positive.
View answer and explanation
Correct option: C
If Assertion is true, but the Reason is false.
Option C (If Assertion is true, but the Reason is false) is correct. The speed of a particle can decrease even if the acceleration is increasing, but this occurs when the acceleration is in the opposite direction to the velocity, not necessarily when acceleration is positive.
51 Easy
51 of 61
Application +4 | -1
A particle moving with uniform acceleration has its final velocity (v=150+8x)  m/s(v = \sqrt {150 + 8x} )\,\,m\mathrm{/}s where xx is the distance travelled by the body then the acceleration
View answer and explanation
Correct option: B
4  m/s24\,\,m\mathrm{/}{s^2}
Option B (4  m/s24\,\,m\mathrm{/}{s^2}) is correct because it is derived by differentiating the given velocity equation with respect to x and using the chain rule.
52 Easy
52 of 61
Application +4 | -1
A car travels equal distances in the same direction with velocities 60kmh−1 , 20  km  h−160\mathrm{km}{\mathrm{h}^{ - 1}}\,,\,20\;\mathrm{km\;}{\mathrm{h}^{ - 1}} and 10  km  h−110\;\mathrm{km\;}{\mathrm{h}^{ - 1}} respectively. The average velocity of the car over the whole journey of motion is
View answer and explanation
Correct option: D
5 ms−15\,\mathrm{m}{\mathrm{s}^{ - 1}}
Option D (5 ms−15\,\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because it represents the harmonic mean of the velocities, converted to m/s.
53 Easy
53 of 61
Application +4 | -1
The velocity of light in vaccum is 3×108 m/s3 \times {10^8}\,m/s. Calculate the time taken by it to travel a distance of 6×1014 m6 \times {10^{14}}\,m
View answer and explanation
Correct option: C
t=2×106 st = 2 \times {10^6}\,s
Option C (t=2×106 st = 2 \times {10^6}\,s) is correct because it is calculated by dividing the distance by the speed of light.
54 Easy
54 of 61
Understanding +4 | -1
Velocity of a body on reaching the point from which it was projected upwards, is
View answer and explanation
Correct option: D
v = - u
Option D (v = - u) is correct because the final velocity is equal in magnitude but opposite in direction to the initial velocity when a body returns to its starting point under gravity.
55 Easy
55 of 61
Application +4 | -1
The x and y coordinates of a particle at any time tt are given by x=8t2+5t3x = 8{t^2} + 5{t^3} and y=2ty = 2t. Where x and y are in metre and tt in seconds. The acceleration of particle at t=5t = 5 sec is
View answer and explanation
Correct option: D
166 m/s2166\,m/{s^2}
Option D (166 m/s2166\,m/{s^2}) is correct because it is the magnitude of the acceleration vector calculated by finding the second derivatives of the x and y coordinates with respect to time and evaluating at t=5s.
56 Easy
56 of 61
Application +4 | -1
A police jeep is chasing with velocity of 45 km/h45 \mathrm{~km} / \mathrm{h} a thief in another jeep moving with velocity 153 km/h153 \mathrm{~km} / \mathrm{h}. Police fires a bullet with muzzle velocity of 180 m/ s180 \mathrm{~m} / \mathrm{~s}. The velocity with which it will strike the car of the thief is
View answer and explanation
Correct option: A
150 m/s150 \mathrm{~m} / \mathrm{s}
Option A (150 m/s) is correct because it calculates the relative velocity of the bullet with respect to the thief's car.
57 Easy
57 of 61
Analyzing +4 | -1
The velocity v\mathrm{v} of a particle is given by the equation v=6t2−6t3v=6 t^2-6 t^3 where vv is in m/sec\mathrm{m} / \mathrm{sec} and t\mathrm{t} is time in seconds then :
View answer and explanation
Correct option: C
minimum velocity is zero
Option D (minimum velocity is zero) is correct because the minimum velocity occurs when the derivative of the velocity function is zero, leading to a zero velocity value.
58 Easy
58 of 61
Application +4 | -1
If a cyclist takes one minute to complete half revolution on a circular path 120 m radius. What is the average velocity?
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Correct option: D
4 m/s
Option B (4 m/s) is correct because average velocity is total displacement divided by total time. The displacement is twice the radius.
59 Easy
59 of 61
Application +4 | -1
The displacement of a body along XX-axis depends on time as x=t+1\sqrt{x}=t+1. Then, the velocity of body
View answer and explanation
Correct option: A
increases with time
Option A (increases with time) is correct because the velocity is derived from the displacement equation and shows a linear relationship with time.
60 Easy
60 of 61
Understanding +4 | -1
The motion of a particle in straight line is an example of
View answer and explanation
Correct option: B
uniformly accelerated motion
Option B (uniformly accelerated motion) is the most appropriate answer, although the question is vague. It implies constant acceleration.
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