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NEET • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Easy

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Showing 1-30 of 61 questions

1 Easy

1 of 61

Application +4 | -1

A body is projected vertically up with ‘u’. Its velocity at half its maximum height is

View answer and explanation

Correct option: D

u/\sqrt 2

Option D (

u/\sqrt 2

) is correct because the velocity at half the maximum height is calculated using conservation of energy or kinematic equations.

2 Easy

2 of 61

Application +4 | -1

A scooter starts from rest have an acceleration of

1 \mathrm{~ms}^{-2}

while a car

150 \mathrm{~m}

behind it starts from rest with an acceleration of

2 \mathrm{~ms}^{-2}

. After how much time, the car catches up with the scooter?

View answer and explanation

Correct option: B

\sqrt{300} \mathrm{~s}

Option B (

\sqrt{300} \mathrm{~s}

) is correct because it represents the time when the distance traveled by the car equals the distance traveled by the scooter plus the initial separation.

3 Easy

3 of 61

Application +4 | -1

A motor vehicle travelled the first one third of a distance ‘S ’ at a speed of

{V_1} = 10\,kmph

, the second one third at a speed of

{V_2} = 20\,kmph

and the last one third at a speed of

{V_3} = 60\,kmph

determine the mean speed of the vehicle over the entire distance ‘S ’

View answer and explanation

Correct option: D

18 kmph

Option D (18 kmph) is correct because it is the harmonic mean of the three speeds, calculated appropriately for equal distances.

4 Easy

4 of 61

Application +4 | -1

A body starts from rest with uniform acceleration

a.

If its velocity after

n

second is

v,

then its displacement in the last 2 s is

View answer and explanation

Correct option: D

\frac{{2v\left( {n - 1} \right)}}{n}

Option D (

\frac{{2v\left( {n - 1} \right)}}{n}

) is correct because the displacement in the last 2 seconds can be found by subtracting the displacement in (n-2) seconds from the displacement in n seconds.

5 Easy

5 of 61

Understanding +4 | -1

A ball of mass

{m_1}

and another ball of mass

{m_2}

are dropped from equal height. If time taken by the balls are

{t_1}

and

{t_2}

respectively, then

View answer and explanation

Correct option: B

{t_1} = {t_2}

Option B (

{t_1} = {t_2}

) is correct because the time taken for an object to fall from a height is independent of its mass when air resistance is negligible.

6 Easy

6 of 61

Application +4 | -1

A stone is dropped from the top of a cliff. It is seen to hit the ground below after 4.2 s. How high is the cliff?

View answer and explanation

Correct option: A

86.44 m

Option A (86.44 m) is correct because it is calculated using the equation of motion for free fall,

h = \frac{1}{2}gt^2

7 Easy

7 of 61

Application +4 | -1

A particle is moving in a straight line such that its velocity is given by

v = {t^4} + 3{t^2} + 8\,\,m/s

. Find acceleration at time

t = 1\,s

View answer and explanation

Correct option: A

10\,m/{s^2}

Option A (

10\,m/{s^2}

) is correct because it is the value obtained by differentiating the velocity function with respect to time and evaluating at t=1s.

8 Easy

8 of 61

Application +4 | -1

t=\sqrt{x}+4

, then

\left(\frac{d x}{d t}\right)_{t=4}

View answer and explanation

Correct option: B

zero

Option B (zero) is correct because when t=4, x=0, and therefore dx/dt at t=4 is zero.

9 Easy

9 of 61

Application +4 | -1

A boy standing at the top of a tower of 20 m height drops a stone. Assuming

g = 10\,m/{s^2},

the velocity with which it hits the ground is

View answer and explanation

Correct option: C

20.0 m/s

Option C (20.0 m/s) is correct because it accurately calculates the final velocity using the kinematic equation

v^2 = u^2 + 2as

10 Easy

10 of 61

Analyzing +4 | -1

Statement-1: Two balls of different masses are thrown vertically upwards with same speed. They will pass through their point of projection in the downward direction with the same speed in absence of air resistance.
Statement-2: In absence of air resistance, the mechanical energy of a projectile is conserved.

View answer and explanation

Correct option: A

Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1

Option A (Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1) is correct because both statements are true and the conservation of mechanical energy explains why the balls return with the same speed.

11 Easy

11 of 61

Application +4 | -1

Two stones are falling at a place from heights in the ratio 2 : 3. Their velocities on reaching the ground are in the ratio

View answer and explanation

Correct option: C

\sqrt 2 :\sqrt 3

Option C (

\sqrt 2 :\sqrt 3

) is correct because the final velocity is proportional to the square root of the height from which the stone falls, as derived from the kinematic equation

v^2 = 2gh

12 Easy

12 of 61

Understanding +4 | -1

The velocity of a body at a given instant of time during motion is:

View answer and explanation

Correct option: C

Instantaneous velocity

=\lim \limits_{{\Delta t \rightarrow 0}} \frac{\Delta \vec{s}}{\Delta t}

Option C (Instantaneous velocity

=\lim \limits_{{\Delta t \rightarrow 0}} \frac{\Delta \vec{s}}{\Delta t}

) is correct because it represents the definition of instantaneous velocity as the limit of the average velocity as the time interval approaches zero.

13 Easy

13 of 61

Application +4 | -1

A body moves from one corner of an equilateral triangle of side 10 cm to the same corner along the sides. Then the distance and displacement are respectively

View answer and explanation

Correct option: B

30 cm & 0 cm

Option B (30 cm & 0 cm) is correct because the distance is the total length traveled along the sides (10 cm + 10 cm + 10 cm = 30 cm), and the displacement is zero since the body returns to its starting point.

14 Easy

14 of 61

Understanding +4 | -1

The slope of velocity-time graph for motion with uniform velocity is equal to

View answer and explanation

Correct option: C

Zero

Option C (Zero) is correct because the slope of a velocity-time graph represents acceleration, and for uniform velocity, the acceleration is zero.

15 Easy

15 of 61

Understanding +4 | -1

Find the average velocity when a particle complete the circle of radius

1 \mathrm{~m}

10 \mathrm{~s}

View answer and explanation

Correct option: D

Zero

Option D (Zero) is correct because the average velocity is defined as the total displacement divided by the total time, and the displacement for a complete circle is zero.

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16 Easy

16 of 61

Application +4 | -1

A body starts to fall freely under gravity. The distances covered by it in first, second and third second are in

View answer and explanation

Correct option: A

0.04380787

Option A (0.04380787) is correct because the ratio of distances covered in successive seconds under free fall is proportional to the odd integers.

17 Easy

17 of 61

Application +4 | -1

A car covers 60 km at a uniform speed of 120 kmph and the next 60 km at a uniform speed of 80 kmph. Find the total time taken.

View answer and explanation

Correct option: B

75 minutes

Option B (75 minutes) is correct because it's the total time calculated by summing the time taken for each segment of the journey at different speeds.

18 Easy

18 of 61

Application +4 | -1

A stone dropped from the top of the tower touches the ground in 4 sec. The height of the tower is about

View answer and explanation

Correct option: A

80 m

Option A (80 m) is correct because the height of the tower is calculated using the formula for free fall under gravity.

19 Easy

19 of 61

Analyzing +4 | -1

A particle is moving along

x

-axis whose acceleration is given by

a=3 x-4

, where

x

is the location of the particle. At

t=0

, the particle is at rest at

x=4 / 3

. The distance travelled by the particle in 5 seconds is

View answer and explanation

Correct option: A

zero

Option A (zero) is correct because the particle's acceleration leads it to oscillate around x=4/3, and with the given initial conditions, it never moves from its initial position.

20 Easy

20 of 61

Understanding +4 | -1

A ball thrown vertically upwards with an initial velocity of 2.4 m/s returns in 4 s. The total displacement of the ball is

View answer and explanation

Correct option: A

Zero

Option A (Zero) is correct because the total displacement of the ball is zero since it returns to its starting point.

21 Easy

21 of 61

Application +4 | -1

A ball dropped onto the floor from a height of 40 m and rebounds of a height of 10 m. If the ball is in contact with the floor of 0.02 s, its average acceleration during contact is

View answer and explanation

Correct option: B

2100\,\,m\mathrm{/}{s^2}

Option B (

2100\,\,m\mathrm{/}{s^2}

) is correct because it is calculated using the change in velocity during contact and the contact time.

22 Easy

22 of 61

Understanding +4 | -1

A body

A

is dropped vertically from the top of a tower. If another identical body

B

is projected thrown from the same point at the same instant, then

View answer and explanation

Correct option: A

both

A

and

B

will reach the ground simultaneously

Option A (both

A

and

B

will reach the ground simultaneously) is correct because the vertical motion of both bodies is governed by the same acceleration due to gravity and initial vertical velocity (zero).

23 Easy

23 of 61

Analyzing +4 | -1

A particle is moving on a straight line path with constant acceleration directed along the direction of instantaneous velocity. Which of the following statements are false about the motion of particle?

View answer and explanation

Correct option: D

All of the above

Option D (All of the above) is correct because all the statements are false when a particle moves with constant acceleration along the direction of instantaneous velocity.

24 Easy

24 of 61

Application +4 | -1

An elevator car whose floor to ceiling distance is

2.7 \mathrm{~m}

starts ascending with a constant acceleration of

1.2 \mathrm{~ms}^{-2} .2 \mathrm{~s}

after the start, a bolt falls from the ceiling of the car. The free fall time of the bolt is (Take,

g=9.8 \mathrm{~ms}^{-2}

)

View answer and explanation

Correct option: D

\sqrt{\frac{5.4}{11}} \mathrm{~s}

Option D (

\sqrt{\frac{5.4}{11}} \mathrm{~s}

) is correct because it accounts for the initial upward velocity of the bolt due to the elevator's acceleration and the additional distance covered during the fall.

25 Easy

25 of 61

Understanding +4 | -1

Assertion: The actual distance covered by an object in a given time interval can be equal to or greater than the magnitude of the displacement.

Reason: The distance covered is a scalar quantity, while the displacement is a vector quantity.

View answer and explanation

Correct option: B

If both assertion and reason are true, but reason is not correct explanation of the assertion.

Option B (If both assertion and reason are true, but reason is not correct explanation of the assertion) is correct because both statements are factually correct, but the scalar/vector nature of distance and displacement doesn't directly explain why distance can be greater than or equal to the magnitude of displacement.

26 Easy

26 of 61

Understanding +4 | -1

Let

\vec{v}

and

\vec{a}

denote the velocity and acceleration respectively of a body in one dimensional motion. Then correct option is

View answer and explanation

Correct option: C

Speed will decrease when

\vec{V}

and

\vec{a}

anti-parallel

Option C (Speed will decrease when

\vec{V}

and

\vec{a}

anti-parallel) is correct because when velocity and acceleration are in opposite directions, the object is decelerating, hence its speed decreases.

27 Easy

27 of 61

Understanding +4 | -1

Which of the following statements is true for a car moving on the road?

View answer and explanation

Correct option: B

With respect to the frame of reference attached to the person sitting in the car, the car is at rest.

Option B (With respect to the frame of reference attached to the person sitting in the car, the car is at rest) is correct because, relative to the person inside, the car's position doesn't change.

28 Easy

28 of 61

Application +4 | -1

A block slides down a slope of angle

\theta

with constant velocity. It is then projected up with a velocity of

10\,m{s^{ - 1}}\,

g = 10\,m{s^{ - 2}}

and

\theta = 30^\circ

. The maximum distance it can go up the plane before coming to stop is

View answer and explanation

Correct option: B

5 m

Option B (5 m) is correct because it accurately calculates the maximum distance traveled up the plane by first finding the coefficient of friction and then using kinematic equations.

29 Easy

29 of 61

Understanding +4 | -1

The velocity-time graph of particle comes out to be a non-linear curve. The motion is

View answer and explanation

Correct option: C

non-uniform accelerated motion

Option C (non-uniform accelerated motion) is correct because a non-linear velocity-time graph indicates that the acceleration is changing with time.

30 Easy

30 of 61

Understanding +4 | -1

Velocity of a body on reaching the point from which it was projected upwards, is

View answer and explanation

Correct option: D

v = u

Option D (

v = u

) is correct because, neglecting air resistance, the velocity of a body on reaching the point from which it was projected upwards is equal in magnitude and opposite in direction to the initial velocity.

Revision notes and key takeaways

Review MOTION IN A STRAIGHT LINE in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 61 single-correct-answer MCQs on MOTION IN A STRAIGHT LINE.
✓ Try each question before opening its answer. Read the explanation where one is available.
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