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NEET • PHYSICS • MOTION IN A STRAIGHT LINE
Motion in a straight line practice · Mixed difficulty
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151
Medium
151 of 200
Analyzing
+4 | -1
Consider the acceleration, velocity and displacement of a tennis ball as it falls to the ground and bounces back. Directions of which of these changes in the process
View answer and explanation
Correct option: B
Displacement and Velocity
Option B (Displacement and Velocity) is correct because the acceleration due to gravity remains constant in the downward direction, but the velocity and displacement change direction upon bouncing.
152
Easy
152 of 200
Application
+4 | -1
If Position of a particle is given by , then which of the following is true?
View answer and explanation
Correct option: C
Velocity is zero at
The correct answer is C (Velocity is zero at t=1 s) because the derivative of the position function, representing velocity, equals zero at t=1.
153
Medium
153 of 200
Understanding
+4 | -1
The numerical ratio of displacement to the distance covered is always
View answer and explanation
Correct option: C
Equal to or less than one
Option D (Both statements are false) is correct. Speed is always non-negative, and direction is accounted for by velocity, not speed.
154
Easy
154 of 200
Analyzing
+4 | -1
Assertion (A): Speed of a particle may decrease, even if acceleration is increasing.
Reason (R): This will happen if acceleration is positive.
Reason (R): This will happen if acceleration is positive.
View answer and explanation
Correct option: C
If Assertion is true, but the Reason is false.
Option C (If Assertion is true, but the Reason is false) is correct. The speed of a particle can decrease even if the acceleration is increasing, but this occurs when the acceleration is in the opposite direction to the velocity, not necessarily when acceleration is positive.
155
Medium
155 of 200
Understanding
+4 | -1
A body is moving along a straight line path with constant velocity. At an instant of time the distance travelled by it is s and its displacement is D, then
View answer and explanation
Correct option: C
D = S
Option C (D = S) is correct because when a body moves along a straight line path with constant velocity, the distance traveled is equal to the magnitude of the displacement.
156
Medium
156 of 200
Understanding
+4 | -1
Statement-I: The speed of a body can be negative.
Statement-II: If the body is moving in the opposite direction of positive motion, then its speed is negative.
Statement-II: If the body is moving in the opposite direction of positive motion, then its speed is negative.
View answer and explanation
Correct option: D
Both statements are false
Option C (Equal to or less than one) is correct because the magnitude of displacement is always less than or equal to the distance covered.
157
Easy
157 of 200
Application
+4 | -1
A particle moving with uniform acceleration has its final velocity where is the distance travelled by the body then the acceleration
View answer and explanation
Correct option: B
Option B () is correct because it is derived by differentiating the given velocity equation with respect to x and using the chain rule.
158
Easy
158 of 200
Application
+4 | -1
A car travels equal distances in the same direction with velocities and respectively. The average velocity of the car over the whole journey of motion is
View answer and explanation
Correct option: D
Option D () is correct because it represents the harmonic mean of the velocities, converted to m/s.
159
Hard
159 of 200
Application
+4 | -1
Two particles are moving with velocities 22 m/sec and
3 m/sec along X-axis in opposite direction. Their initial
positions are at x = 30 m, x = 180 m respectively. find
time interval after which they meet with each other
3 m/sec along X-axis in opposite direction. Their initial
positions are at x = 30 m, x = 180 m respectively. find
time interval after which they meet with each other
View answer and explanation
Correct option: C
6 sec
Option C (6 sec) is correct because it is the time calculated by considering the relative velocity and the initial separation between the two particles.
160
Easy
160 of 200
Application
+4 | -1
The velocity of light in vaccum is . Calculate the time taken by it to travel a distance of
View answer and explanation
Correct option: C
Option C () is correct because it is calculated by dividing the distance by the speed of light.
161
Medium
161 of 200
Understanding
+4 | -1
The numerical ratio of displacement to distance for a moving object is
View answer and explanation
Correct option: D
Equal to or less than 1
Option D (Equal to or less than 1) is correct because the magnitude of displacement is always less than or equal to the distance traveled. The ratio can be 1 only if the object moves in a straight line without changing direction.
162
Medium
162 of 200
Analyzing
+4 | -1
A body is projected up with a speed ‘u' and the time taken by it is T to reach the maximum height H. Pick out the correct statement
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Correct option: B
It acquires velocity u/2 in T/2sec
Option B (It acquires velocity u/2 in T/2sec) is correct because, under constant gravitational acceleration, velocity changes linearly with time. Therefore, half the initial velocity is reached in half the total time to reach maximum height.
163
Medium
163 of 200
Understanding
+4 | -1
Stopping distance of a moving vehicle is directly proportional to
View answer and explanation
Correct option: A
Square of the initial velocity
Option A (Square of the initial velocity) is correct because stopping distance is proportional to the square of the initial velocity, as derived from kinematic equations.
164
Medium
164 of 200
Application
+4 | -1
A man goes 10 m towards North, then 20 m towards east then displacement is
View answer and explanation
Correct option: A
22.5 m
Option A (22.5 m) is incorrect. The correct answer should be 22.36 m, which is not listed. The closest option is A, but it is rounded.
165
Medium
165 of 200
Analyzing
+4 | -1
A body starts from rest and travels a distance S with uniform acceleration, then moves uniformly a distance 2 S uniformly, and finally comes to gest after moving further 5 S under uniform retardation. The ratio of average velocity to maximum velocity is
View answer and explanation
Correct option: C
Option C () is correct because it is derived by calculating the average and maximum velocities and then finding their ratio.
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166
Easy
166 of 200
Understanding
+4 | -1
Velocity of a body on reaching the point from which it was projected upwards, is
View answer and explanation
Correct option: D
v = - u
Option D (v = - u) is correct because the final velocity is equal in magnitude but opposite in direction to the initial velocity when a body returns to its starting point under gravity.
167
Hard
167 of 200
Application
+4 | -1
Amongst the following equation of motion, which represents uniformly accelerated motion?
View answer and explanation
Correct option: C
Option C () is correct because solving for x yields an equation of the form , which represents uniformly accelerated motion.
168
Medium
168 of 200
Analyzing
+4 | -1
In one dimensional motion, instantaneous speed satisfies .
View answer and explanation
Correct option: B
The displacement in time satisfies
Option B is correct because it provides the correct range for displacement based on the maximum speed and time interval.
169
Medium
169 of 200
Remembering
+4 | -1
Which branch of physics deals with motion without considering its causes?
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Correct option: C
Kinematics
Option C (Kinematics) is correct because kinematics specifically deals with the description of motion without considering the forces that cause it.
170
Medium
170 of 200
Application
+4 | -1
A train started from rest from a station and accelerated at for 10sec. Then it travels at constant speed for 30 sec and there after it decelerated at until it stopped at the next station. The distance between two stations is
View answer and explanation
Correct option: C
750 m
Option C (750 m) is correct because it is the total distance calculated by summing the distances traveled during acceleration, constant speed, and deceleration.
171
Medium
171 of 200
Analyzing
+4 | -1
The relative velocity or of two bodies and may be
I. greater than velocity of body A
II. greater than velocity of body B
III. less than the velocity of body A
IV. less than the velocity of body B
I. greater than velocity of body A
II. greater than velocity of body B
III. less than the velocity of body A
IV. less than the velocity of body B
View answer and explanation
Correct option: D
I, II, III and IV
I, II, III and IV. The relative velocity can be greater or less than the individual velocities depending on the direction of motion.
172
Easy
172 of 200
Application
+4 | -1
The x and y coordinates of a particle at any time are given by and . Where x and y are in metre and in seconds. The acceleration of particle at sec is
View answer and explanation
Correct option: D
Option D () is correct because it is the magnitude of the acceleration vector calculated by finding the second derivatives of the x and y coordinates with respect to time and evaluating at t=5s.
173
Hard
173 of 200
Analyzing
+4 | -1
The distance x covered by a particle in one-dimensional motion varies with time t as . The accelerating of the particle varies as
View answer and explanation
Correct option: A
Option A () is correct because the acceleration is inversely proportional to the cube of the distance x, derived from differentiating the given equation.
174
Easy
174 of 200
Application
+4 | -1
A police jeep is chasing with velocity of a thief in another jeep moving with velocity . Police fires a bullet with muzzle velocity of . The velocity with which it will strike the car of the thief is
View answer and explanation
Correct option: A
Option A (150 m/s) is correct because it calculates the relative velocity of the bullet with respect to the thief's car.
175
Easy
175 of 200
Analyzing
+4 | -1
The velocity of a particle is given by the equation where is in and is time in seconds then :
View answer and explanation
Correct option: C
minimum velocity is zero
Option D (minimum velocity is zero) is correct because the minimum velocity occurs when the derivative of the velocity function is zero, leading to a zero velocity value.
176
Medium
176 of 200
Understanding
+4 | -1
A graph is shown between velocity an time for the motion of a particle. The area under the curve between the time intervals gives
View answer and explanation
Correct option: B
Displacement of the particle
Option B (Displacement of the particle) is correct because the area under the velocity-time graph represents the displacement of the particle.
177
Hard
177 of 200
Application
+4 | -1
Two bodies move in a straight line towards each other with initial velocities and and with constant accelerations and directed against their corresponding initial velocities. The maximum initial separation between them for which they will meet during the motion is:
View answer and explanation
Correct option: B
Option B () is correct because it represents the maximum initial separation for the two bodies to meet, considering their initial velocities and decelerations.
178
Medium
178 of 200
Understanding
+4 | -1
Assertion : Displacement of a body is vector sum of the area under velocity- time graph.
Reason : Displacement is a vector quantity.
Reason : Displacement is a vector quantity.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion.
Option A (Assertion is correct, reason is correct; reason is a correct explanation for assertion) is correct because the area under the velocity-time graph represents displacement, and displacement is a vector quantity, making the vector sum relevant.
179
Hard
179 of 200
Application
+4 | -1
A ball is thrown vertically upwards. It was observed at a height h twice with a time interval t. The initial velocity of the ball is
View answer and explanation
Correct option: C
Option C () is correct because it is derived from the equations of motion, considering the time interval between the ball passing the height h twice.
180
Medium
180 of 200
Understanding
+4 | -1
A graph is drawn between velocity and time for the motion of a particle. The area under the curve between the time intervals gives
View answer and explanation
Correct option: B
Displacement of the particle
Option B (Displacement of the particle) is correct because the area under a velocity-time graph represents the displacement of the particle.
Revision notes and key takeaways
Review MOTION IN A STRAIGHT LINE in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 200 questions
