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NEET • PHYSICS • MAGNETIC EFFECT OF CURRENT
Magnetic effect of current practice · Mixed difficulty
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151
Medium
151 of 280
Application
+4 | -1
A circular loop of radius 0.0157 m carries a current of 2.0 A. The magnetic field at the center of the loop is
View answer and explanation
Correct option: B
Option B is correct because the magnetic field at the center of a circular loop is calculated using the formula B = μ₀I / 2R.
152
Easy
152 of 280
Analyzing
+4 | -1
Statement I: An electron moving in the positive -direction enters a region where uniform electric and magnetic fields exist perpendicular to each other. The electric field is in the negative -direction. If the electron travels undeflected in this region, the direction of the magnetic field is along the negative -axis.
Statement II: If a charged particle moves in a direction perpendicular to a magnetic field, the direction of the force acting on it is given by Fleming's left hand rule.
Statement II: If a charged particle moves in a direction perpendicular to a magnetic field, the direction of the force acting on it is given by Fleming's left hand rule.
View answer and explanation
Correct option: B
Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I
Option C (Both and are constant) is correct because the radius of the circular path depends on both velocity and magnetic field strength, and both must be constant for the radius to remain constant.
153
Medium
153 of 280
Application
+4 | -1
A straight wire of length of and carrying a current of is placed in a uniform magnetic field of induction 2 tesla. If the magnetic field is perpendicular to the length of the wire, the force acting on the wire is
View answer and explanation
Correct option: B
1.2 N
Option B (1.2 N) is correct because it is calculated using the formula for the force on a current-carrying wire in a magnetic field.
154
Hard
154 of 280
Application
+4 | -1
A galvanometer gives full scale deflection with in its coil. The resistance of its coil is . How much shunt resistance is required to convert it into an ammeter to read current upto ?
View answer and explanation
Correct option: C
Option C () is correct because it's the shunt resistance value that allows the galvanometer to measure up to 1.8 A, given its internal resistance and full-scale deflection current.
155
Hard
155 of 280
Application
+4 | -1
A direct current flows through a solenoid, entering in an anticlockwise sense at the end A. This solenoid, made to float on still water will:
View answer and explanation
Correct option: A
have the end A point towards north
Option D () is correct because the specific charge is calculated using the geometry of the deflection and the magnetic field.
156
Medium
156 of 280
Analyzing
+4 | -1
A particle moving in the -plane experiences a velocity dependent force where and are the and components of its velocity If is the acceleration of the particle, then which of the following statements is true for the particle?
View answer and explanation
Correct option: A
Quantity is constant in time.
Option C (The proton trajectory will be less curved than the electron trajectory) is correct because the radius of curvature in an electric field is proportional to mass and inversely proportional to charge and electric field strength. Since the proton is much more massive, its trajectory will be less curved.
157
Medium
157 of 280
Understanding
+4 | -1
A wire of length L is placed parallel to the lines
of force in a uniform magnetic field B. If I is
the current in the wire, then it will experience:
of force in a uniform magnetic field B. If I is
the current in the wire, then it will experience:
View answer and explanation
Correct option: D
no force
Option D (no force) is correct because the force on a current-carrying wire in a magnetic field is zero when the wire is parallel to the magnetic field.
158
Medium
158 of 280
Understanding
+4 | -1
The magnetic dipole moment of a current carrying conducting loop depends on
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the magnetic dipole moment of a current-carrying loop is directly proportional to the number of turns, the current, and the area of the loop.
159
Hard
159 of 280
Application
+4 | -1
A solenoid of length 0.4 m and having 500 turns of wire carries a current of 3 amp. A thin coil having 10 turns of wire and of radius 0.01 m carries a current of 0.4 amp. Calculate the torque required to hold the coil in the middle of the solenoid with its axis perpendicular to the axis of solenoid
View answer and explanation
Correct option: C
Option C () is correct because it is the calculated torque required to hold the coil perpendicular to the solenoid's axis.
160
Easy
160 of 280
Application
+4 | -1
Charge is uniformly spread on a thin ring of radius . The ring rotates about its axis with a uniform frequency Hz. The magnitude of magnetic induction at the centre of the ring is
View answer and explanation
Correct option: B
Option B () is correct because the magnetic field at the center of a rotating charged ring is proportional to the charge, frequency, and inversely proportional to the radius.
161
Medium
161 of 280
Remembering
+4 | -1
The cyclotron assembly is filled with
View answer and explanation
Correct option: D
Vacuum.
Option D is correct. A vacuum is used in a cyclotron to minimize collisions between the accelerated particles and air molecules.
162
Medium
162 of 280
Remembering
+4 | -1
Field inside a solenoid is
View answer and explanation
Correct option: B
directly proportional to current
Option B (directly proportional to current) is correct because the magnetic field inside a solenoid is directly proportional to the current flowing through it.
163
Medium
163 of 280
Application
+4 | -1
A straight wire carrying current is turned into a circular loop. If the magnitude of magnetic moment associated with it in M.K.S. unit is , the length of wire will be
View answer and explanation
Correct option: B
Option B () is correct because it correctly relates the length of the wire to the magnetic moment and current.
164
Medium
164 of 280
Analyzing
+4 | -1
A charged particle is moving in the presence of electric field and magnetic field The directions of and are such that the charged particle moves in a straight line and its speed increases. The relations amongst , and velocity must be such that
View answer and explanation
Correct option: B
and are all parallel to each other
Option B ( and are all parallel to each other) is correct because if all three vectors are parallel, the magnetic force is zero, and the electric force accelerates the particle in a straight line.
165
Medium
165 of 280
Application
+4 | -1
A charged particle with charge enters a region of constant, uniform and mutually orthogonal fields and with a velocity perpendicular to both , and comes out without any change in magnitude or direction of . Then
View answer and explanation
Correct option: A
Option A is correct because the condition for a charged particle to move undeflected in mutually perpendicular electric and magnetic fields is .
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166
Hard
166 of 280
Application
+4 | -1
A tightly wound long solenoid carries a current of 1.5 A. An electron is executing uniform circular motion inside the solenoid with a time period of 75 ns. The number of turns per metre in the solenoid is ____.
[Take mass of electron charge of electron
[Take mass of electron charge of electron
View answer and explanation
Correct option: A
250
The correct answer is 250 because it is the calculated number of turns per meter in the solenoid based on the given parameters and the formula relating the magnetic field to the electron's circular motion.
167
Medium
167 of 280
Understanding
+4 | -1
The ratio of voltage sensitivity () and current sensitivity () of a moving coil galvanometer is
View answer and explanation
Correct option: A
Option A () is correct because voltage sensitivity is current sensitivity divided by the galvanometer resistance (G).
168
Medium
168 of 280
Understanding
+4 | -1
A current carrying small loop behaves like a small magnet. If be its area and its magnetic moment, the current in the loop will be
View answer and explanation
Correct option: A
Option A () is correct because the current in the loop is the magnetic moment divided by the area, derived from the formula M = IA.
169
Medium
169 of 280
Application
+4 | -1
The coils and having the radii in the ratio carrying currents in the ratio 5:1 and have the number of turns in the ratio 1:5. The ratio of magnetic inductions at their centres is
View answer and explanation
Correct option: B
Option B is correct because the ratio of magnetic inductions is calculated using the formula B = (μ₀NI) / (2r), considering the ratios of radii, currents, and number of turns.
170
Medium
170 of 280
Remembering
+4 | -1
The magnetic field at the center of current I carrying loop of radius , is
View answer and explanation
Correct option: A
Option A () is correct because it represents the formula for the magnetic field at the center of a current-carrying loop.
171
Medium
171 of 280
Analyzing
+4 | -1
Consider a wire carrying a steady current, placed in a uniform magnetic field perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do no work. This implies that,
View answer and explanation
Correct option: B
Some charges inside the wire move to the surface as a result of
Option B (Some charges inside the wire move to the surface as a result of ) is correct because the magnetic force on the moving charges inside the wire causes them to accumulate on the surface, creating a potential difference but doing no net work.
172
Easy
172 of 280
Remembering
+4 | -1
The AC voltage across a resistance can be measured using a :
View answer and explanation
Correct option: A
Hot wire voltmeter
Option A (Hot wire voltmeter) is correct because hot wire voltmeters measure AC voltage based on the heating effect of the current, which is independent of the current's direction.
173
Medium
173 of 280
Application
+4 | -1
A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be of its value at the centre of the coil, is
View answer and explanation
Correct option: B
Option B is correct because the distance is calculated by setting the magnetic induction to 1/8th of its value at the center and solving for the distance using the formula for magnetic field on the axis of a circular coil.
174
Easy
174 of 280
Remembering
+4 | -1
A current carrying conductor placed in a magnetic field experiences maximum force when angle between current and magnetic field is
View answer and explanation
Correct option: B
Option B () is correct because the force is maximum when the angle between the current and magnetic field is 90 degrees.
175
Medium
175 of 280
Remembering
+4 | -1
Tangent galvanometer measures
View answer and explanation
Correct option: B
Current
Option B (Current) is correct because a tangent galvanometer is specifically designed to measure electric current based on the tangent law of magnetism.
176
Easy
176 of 280
Application
+4 | -1
The ratio of time periods of -particle and proton moving on circular path in uniform transverse magnetic field :-
View answer and explanation
Correct option: A
Option A is correct because the time period of a charged particle in a magnetic field is proportional to its mass and inversely proportional to its charge, leading to a ratio of 2:1 for an alpha particle and a proton.
177
Medium
177 of 280
Analyzing
+4 | -1
A cyclotron is used to accelerate protons deuterons and -particles . While exiting under similar conditions, the minimum is gained by :
View answer and explanation
Correct option: C
deuterons
Option C is correct. The minimum KE is gained by deuterons because KE is proportional to (q2/m) and deuteron has the smallest q2/m ratio.
178
Medium
178 of 280
Understanding
+4 | -1
In a solenoid, if number of turns is doubled. then self inductance will become
View answer and explanation
Correct option: D
quadruped.
Option D (quadruped) is correct because self-inductance is proportional to the square of the number of turns.
179
Easy
179 of 280
Remembering
+4 | -1
The magnetic field at a point on one end of a solenoid having turns per metre length and carrying a current of ampere is given by
View answer and explanation
Correct option: B
Option B () is correct because it is the formula for the magnetic field at one end of a solenoid.
180
Easy
180 of 280
Understanding
+4 | -1
Magnetic field dB to a current element at any
point on its axis is
point on its axis is
View answer and explanation
Correct option: B
zero
Option B (zero) is correct because the magnetic field due to a current element at any point on its axis is zero, as the angle between dl and r is 0 or 180 degrees, making the cross product zero.
Revision notes and key takeaways
Review MAGNETIC EFFECT OF CURRENT in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 280 questions
