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NEET • PHYSICS • MAGNETIC EFFECT OF CURRENT

Magnetic effect of current practice · Mixed difficulty

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271 Medium
271 of 280
Application +4 | -1
A galvanometer with its coil resistance 25Ω25\Omega requires a current of 1mA for its full deflection. In order to construct an ammeter to read up of a current of 2A, the approximate value of the shunt resistance should be
View answer and explanation
Correct option: D
1.25×10−2Ω1.25 \times {10^{ - 2}}\Omega
Option D (1.25×10−2Ω1.25 \times {10^{ - 2}}\Omega) is correct because it is calculated using the formula for shunt resistance in an ammeter.
272 Easy
272 of 280
Application +4 | -1
A horizontal overhead power line carries a current of 90 A90 \mathrm{~A} in east to west direction. What is the magnitude and direction of the magnetic field due to the current, 1.5 m1.5 \mathrm{~m} below the line?
View answer and explanation
Correct option: A
1.2×10−5 T1.2 \times 10^{-5} \mathrm{~T} towards south
Option A is correct because the magnetic field is calculated using the formula for the magnetic field around a long straight wire, and the direction is determined by the right-hand rule.
273 Medium
273 of 280
Analyzing +4 | -1
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason
R.
Assertion A: For measuring the potential difference across a resistance of 600 Ω600 \,\Omega, the
voltmeter with resistance 1000 Ω1000 \,\Omega will be preferred over voltmeter with resistance 4000 Ω.4000\,\Omega.
Reason R: Voltmeter with higher resistance will draw smaller current than voltmeter with lower resistance.
In the light of the above statements, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: C
A is not correct but R is correct
A is not correct but R is correct because a voltmeter with higher resistance draws smaller current, but a higher resistance voltmeter is preferred when measuring potential difference across a *higher* resistance, not a lower one.
274 Medium
274 of 280
Remembering +4 | -1
A moving coil galvanometer has NN number of turns in a coil of effective area AA, it carries a current II. The magnetic field BB is radial. The torque acting on the coil is
View answer and explanation
Correct option: D
NABIN A B I
Option D (NABIN A B I) is correct because the torque acting on a moving coil galvanometer is given by the formula τ=NABI\tau = NABI, where N is the number of turns, A is the area, B is the magnetic field, and I is the current.
275 Medium
275 of 280
Analyzing +4 | -1
Statement A: When a proton and a neutron enter into a transverse magnetic field with equal speeds, then they trace circular paths of equal radii.
Statement B: In a transverse magnetic field the period of revolution of a charged particle in a circular path is directly proportional to the mass of the particle.
View answer and explanation
Correct option: D
A is not correct and B is correct
Option D is correct. Statement A is incorrect because the radii depend on the charge, and Statement B is correct because the period is directly proportional to mass.
276 Hard
276 of 280
Application +4 | -1
Two particles having same charge and K.E enter at right angles into the same magnetic field and travel in circular paths of radii 2cm and 3cm respectively. The ratio of their masses is
View answer and explanation
Correct option: A
4:94:9
Option A (4:94:9) is correct because the radius of the circular path is proportional to the square root of the mass when charge and kinetic energy are constant.
277 Medium
277 of 280
Application +4 | -1
The earth’s magnetic induction at a certain point is 7×10−5  Wbm−27 \times {10^{ - 5}}\;\mathrm{Wb}{\mathrm{m}^{ - 2}}. This is to be annulled by the magnetic induction at the center of a circular conducting loop of radius 15 cm. The required current in the loop is
View answer and explanation
Correct option: B
5.6 A
Option B (5.6 A) is correct because the current is calculated by equating the magnetic field at the center of the loop to the Earth's magnetic field.
278 Medium
278 of 280
Analyzing +4 | -1
Assertion (A): In ammeter, current in shunt is always greater than current in galvanometer.

Reason (R): Value of shunt resistance may be smaller than galvanometer resistance and is parallel to it.
View answer and explanation
Correct option: D
(A) is false, (R) is true
(A) is false, (R) is true because in an ammeter, the current in the shunt is greater than the current in the galvanometer, and the shunt resistance is smaller than the galvanometer resistance and is connected in parallel.
279 Medium
279 of 280
Analyzing +4 | -1
In a region an electron is moving in a circle. What can be the possible field there?
View answer and explanation
Correct option: D
Both (2) and (3)
Option D (Both (2) and (3)) is correct because an electron can move in a circle under the influence of a time-varying electric field (due to induced magnetic field) or a uniform magnetic field.
280 Medium
280 of 280
Understanding +4 | -1
Three moving coil galvanometers
A,B  and  CA,\mathrm{ }B\,\,and\,\,C
are made of coils of three different material having torsional constant 1.8  ×  10−8,  2.8  ×  10−81.8\,\, \times \,\,{10^{ - 8}},\,\,2.8\,\, \times \,\,{10^{ - 8}}and 3.8  ×  10−83.8\,\, \times \,\,{10^{ - 8}} respectively. If the three galvanometers are identical in all other respect, then in which of the above cases sensitivity is maximum?
View answer and explanation
Correct option: A
A\begin{array}{llllllllllllllllllll} A \end{array}
Option A (A) is correct because sensitivity is inversely proportional to the torsional constant, so the galvanometer with the smallest torsional constant will have the highest sensitivity.
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