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NEET • PHYSICS • GRAVITATION

Gravitation practice · Mixed difficulty

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Showing 181-210 of 255 questions

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181 Medium
181 of 255
Application +4 | -1
A satellite can be in a geostationary orbit around earth in an orbit of radius rr . If the angular velocity of earth about its axis doubles, a satellite can now be in a geostationary orbit around earth of radius
View answer and explanation
Correct option: C
r(4)1/3\frac{r}{{{{(4)}^{1/3}}}}
Option C (r(4)1/3\frac{r}{{{{(4)}^{1/3}}}}) is correct because the radius of a geostationary orbit is inversely proportional to the cube root of the square of the angular velocity.
182 Medium
182 of 255
Analyzing +4 | -1
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The escape velocities of planet AA and BB are same. But AA and BB are of unequal mass.
Reason R : The product of their mass and radius must be same, M1R1=M2R2{M_1}{R_1} = \mathrm{ }{M_2}{R_2}
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: B
A is correct but R is not correct.
Option B (A is correct but R is not correct) is correct. Assertion A can be true if the ratio of mass to radius is the same for both planets. Reason R is incorrect because escape velocity depends on 2GM/R, so M/R should be same, not M*R.
183 Hard
183 of 255
Application +4 | -1
The minimum energy required to launch a satellite of mass mm from the surface of earth of mass MM and radius RR in a circular orbit at an altitude of 2R2 R from the surface of the earth is:
View answer and explanation
Correct option: D
5GmM6R\frac{5 G m M}{6 R}
Option D (5GmM6R\frac{{5 G m M}}{{{6 R}}}) is correct because it represents the difference between the final energy in orbit and the initial potential energy on the Earth's surface.
184 Easy
184 of 255
Understanding +4 | -1
Statement-1: Two particles are to be projected from the surface of earth so that particles just leave the gravitational field of earth. One particle is projected vertically upward and another is at an angle of 45∘45^{\circ} with vertical. Speed given to both particles is same.
Statement-2: Escape speed does not depend upon angle of projection.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true
Option A (Statement-1 is true, Statement-2 is true) is correct because escape speed is independent of the angle of projection, and thus the same speed will allow both particles to escape.
185 Medium
185 of 255
Application +4 | -1
What should be the angular velocity of earth so that a body on its equator is weightless?
View answer and explanation
Correct option: C
1800rad  s−1\frac{1}{{800}}\mathrm{rad\;}{\mathrm{s}^{ - 1}}
Option A (1800rad  s−1\frac{1}{{800}}\mathrm{rad\;}{\mathrm{s}^{ - 1}}) is correct because it is the angular velocity at which the centripetal acceleration equals the gravitational acceleration.
186 Medium
186 of 255
Understanding +4 | -1
The earth revolves about the sun in an elliptical orbit with mean radius 9.3×107m9.3 \times {10^7}m in a period of 1 year. Assuming that there are no outside influences
View answer and explanation
Correct option: B
The earth’s angular momentum remains constant
Option B (The earth’s angular momentum remains constant) is correct. In the absence of external torques, angular momentum is conserved.
187 Easy
187 of 255
Analyzing +4 | -1
A satellite is moving in a circular orbit round the earth with a diameter of orbit 2R2 R. At a certain point a rocket fixed to the satellite is fired such that it increases the velocity of the satellite tangentially. The resulting orbit of the satellite would be
View answer and explanation
Correct option: C
elliptical orbit with minimum distance from the earth equal to RR
Option C (elliptical orbit with minimum distance from the earth equal to RR) is correct because increasing the tangential velocity at a point in a circular orbit will result in an elliptical orbit with the point of velocity increase being the perigee (closest point).
188 Easy
188 of 255
Application +4 | -1
A body revolved around the sun 27 times faster than the earth. What is the ratio of their radii
View answer and explanation
Correct option: B
19\frac{1}{9}
Option B (19\frac{1}{9}) is correct because, using Kepler's third law (T2∝R3T^2 \propto R^3), if the body revolves 27 times faster, its time period is 1/27 of Earth's, leading to a radius ratio of (1/27)(2/3) = 1/9.
189 Easy
189 of 255
Application +4 | -1
A person can jump safely from a height of 8 m on the earth on a planet where acceleration due to gravity is 5 ms−2,5\,m{s^{ - 2}}, the maximum height from which can jump safely [ge=10 ms−2]\left[ {{g_e} = 10\,m{s^{ - 2}}} \right]
View answer and explanation
Correct option: B
16 m
Option B (16 m) is correct because the potential energy at the maximum height must be the same on both Earth and the planet.
190 Easy
190 of 255
Analyzing +4 | -1
Statement-1: A particle is at a height R{R} from the surface of earth (Here R{R} is radius of earth). If mass of particle is m{m} then its gravitational potential energy is mgR{mgR}
Statement-2: If a particle is slowly lifted above the surface of earth then work is done by external agent. Work done by external agent is wasted in the form of heat energy.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is false
Option D (Statement-1 is false, Statement-2 is false) is correct because gravitational potential energy at height R is -GMm/2R, and work done by the external agent is stored as potential energy, not wasted as heat.
191 Easy
191 of 255
Understanding +4 | -1
Statement-1: Work done by gravitational field in cyclic process is zero
Statement-2: Work done by conservative field does not depend upon path.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true
Option A is correct because both statements are true: the work done by a gravitational field in a cyclic process is zero, and the work done by a conservative field is path-independent.
192 Medium
192 of 255
Analyzing +4 | -1
A particle of mass mm is dropped from a great height hh above the hole in the earth dug along its diameter. Then, which of the following statement is correct?
View answer and explanation
Correct option: D
The speed of the particle at the centre of earth equals GM(R+3h)R(R+h)\sqrt{\frac{G M(R+3 h)}{R(R+h)}}, where RR and MM are the radius and mass of the earth, respectively.
Option D (The speed of the particle at the centre of earth equals GM(R+3h)R(R+h)\sqrt{\frac{G M(R+3 h)}{R(R+h)}}, where RR and MM are the radius and mass of the earth, respectively.) is correct because it is derived from the conservation of energy principle.
193 Medium
193 of 255
Application +4 | -1
The acceleration due to gravity increase by 0.5%0.5\% when we go from the equator to the poles. What will be the time period of the pendulum at the equator which beats seconds at the poles?
View answer and explanation
Correct option: D
2.005 s
Option D (2.005 s) is correct because it accounts for the change in gravity affecting the pendulum's period.
194 Easy
194 of 255
Understanding +4 | -1
Statement-1: A planet is moving around the sun in an elliptical orbit. Then from aphelion point to perihelion point the speed of the planet continuously increases.
Statement-2: According to Kepler's second law, the areal velocity of the line joining planet to the sun is constant.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true
Option A is correct because the planet's speed increases from aphelion to perihelion, and Kepler's second law states that areal velocity is constant.
195 Easy
195 of 255
Analyzing +4 | -1
Assertion: The change of weight with height hh near the earth's surface is proportional to h0h^0
Reason: Since gravitational potential is given by V=−GM/rV=-G M / r
View answer and explanation
Correct option: B
Assertion is True, Reason is True; Reason is NOT a correct explanation for Assertion
Option B (Assertion is True, Reason is True; Reason is NOT a correct explanation for Assertion) is correct because the weight change with height is approximately constant near the surface, and the gravitational potential is given by the stated formula, but the potential doesn't directly explain the constant weight change.
196 Medium
196 of 255
Understanding +4 | -1
If satellite is shifted towards the earth. Then time period of satellite will be
View answer and explanation
Correct option: B
Decrease
Option B (Decrease) is correct. As the satellite is shifted towards the Earth, its orbital radius decreases, leading to a decrease in its time period.
197 Medium
197 of 255
Application +4 | -1
A particle does uniform circular motion in a horizontal plane. The radius of the circle is 20 cm. The centripetal force acting on the particle is 10 N. It's kinetic energy is
View answer and explanation
Correct option: D
1.0 J
Option D (1.0 J) is correct because the kinetic energy can be calculated using the centripetal force and radius.
198 Easy
198 of 255
Application +4 | -1
The percentage decrease in the weight of a rocket, when taken to a height of 32 km32 \mathrm{~km} above the surface of earth will, be:

(Radius of earth =6400 km=6400 \mathrm{~km} )
View answer and explanation
Correct option: A
1%1 \%
Option A (1%1 \%) is correct because the percentage decrease in weight is approximately 2h/R2h/R, where h is the height above the Earth's surface and R is the Earth's radius. So, (2 * 32)/6400 = 0.01 or 1%.
199 Medium
199 of 255
Understanding +4 | -1
Gravitational force between two point masses is found to be F when both are in vacuum. If both the masses are immersed in water, new gravitational force will be
View answer and explanation
Correct option: C
F
Option C (F) is correct because the gravitational force depends only on the masses and the distance between them, not the surrounding medium.
200 Medium
200 of 255
Understanding +4 | -1
A satellite of the earth is revolving in a circular orbit with a uniform speed vv. If the gravitational force suddenly disappears, the satellite will
View answer and explanation
Correct option: B
Move with a velocity vv, tangentially to the original orbit
Option B (Move with a velocity vv, tangentially to the original orbit) is correct because the satellite will continue to move in a straight line tangent to its original orbit due to inertia.
201 Easy
201 of 255
Analyzing +4 | -1
Assertion(A): If radius of earth suddenly shrinks to half its present value without changing its mass, then the period of an earth's satellite will not change.
Reason(R): Time period of a satellite does not depend upon the mass of earth.
View answer and explanation
Correct option: C
If Assertion is correct but Reason is correct.
Option C (Assertion is correct but Reason is correct) is correct because the assertion about the satellite's period not changing is true, and the reason about the time period not depending on the mass of the earth is also true, but the reason doesn't explain the assertion.
202 Medium
202 of 255
Understanding +4 | -1
A body of mass m is taken to the boom of a deep mine. Then
View answer and explanation
Correct option: D
Its weight decreases
Option D (Its weight decreases) is correct because the acceleration due to gravity decreases as you go down into the Earth, therefore the weight decreases.
203 Medium
203 of 255
Understanding +4 | -1
Every planet revolves around the sun in an elliptical
orbit:

A. The force acting on a planet is inversely
proportional to square of distance from sun.

B. Force acting on planet is inversely proportional
to product of the masses of the planet and the
sun.

C. The Centripetal force acting on the planet is
directed away from the sun.

D. The square of time period of revolution of
planet around sun is directly proportional to
cube of semi-major axis of elliptical orbit.

Choose the correct answer from the options given
below:
View answer and explanation
Correct option: D
A and D only
Option D is correct because the gravitational force is inversely proportional to the square of the distance, and the square of the period is proportional to the cube of the semi-major axis.
204 Medium
204 of 255
Understanding +4 | -1
Two satellites of earth, S1 and S2{S_1}\,and\,{S_2}, are moving in the same orbit. The mass of S1{S_1} is four times the mass of S2{S_2}. Which one of the following statements is true?
View answer and explanation
Correct option: C
S1 and S2{S_1}\,and\,{S_2} are moving with the same speed
Option C (S1 and S2{S_1}\,and\,{S_2} are moving with the same speed) is correct. Orbital speed depends only on the mass of the Earth and the radius of the orbit, which are the same for both satellites.
205 Easy
205 of 255
Remembering +4 | -1
Period of revolution of a geostationary satellite around the earth is
View answer and explanation
Correct option: B
24 hours
Option B (24 hours) is correct because a geostationary satellite must have the same period as the Earth's rotation to remain in a fixed position relative to the Earth.
206 Easy
206 of 255
Application +4 | -1
Assume that the earth rotates in a circular orbit round the sun in 365 days. If the mass of the sun gets four time but the radius of the orbit remains unchanged, the length of the year would be approximately.
View answer and explanation
Correct option: A
182.5 days
Option A (182.5 days) is correct because the period of revolution is inversely proportional to the square root of the mass of the sun.
207 Medium
207 of 255
Application +4 | -1
The maximum and minimum distances of a comet from the sun are 1.4×1012m and 6×1010m1.4 \times {10^{12}}m\,and\,6 \times {10^{10}}m respectively. If its velocity nearest to the sun is 7×104ms−17 \times {10^4}\mathrm{m}{\mathrm{s}^{ - 1}}, what is the velocity in the farthest position? Assume the paths of comet in both instantaneous positions are circular
View answer and explanation
Correct option: A
3×103ms−13 \times {10^3}\mathrm{m}{\mathrm{s}^{ - 1}}
Option A (3×103ms−13 \times {10^3}\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because angular momentum is conserved, and the velocity is inversely proportional to the distance.
208 Easy
208 of 255
Application +4 | -1
A satellite is moving around the earth with speed V in a circular orbit of radius r. If the orbit radius is decreased by 1%, its speed will
View answer and explanation
Correct option: B
increased by 0.5%
Option B (increased by 0.5%) is correct because the orbital speed is inversely proportional to the square root of the radius, so a decrease in radius leads to an increase in speed.
209 Easy
209 of 255
Application +4 | -1
Infinite number of masses each 2 kg are placed along the x-axis at x=±1 m, ±2 m, ± 4 m, +......x = \pm 1\,m,\, \pm 2\,m,\, \pm \,4\,m,\, + ...... The magnitude of the resultant gravitational potential in terms of gravitation constant G at the origin (x = 0) is
View answer and explanation
Correct option: B
8G
Option C (4G) is correct because the sum of the geometric series converges to 4G.
210 Easy
210 of 255
Application +4 | -1
The ratio of the accelerations due to gravity on two planets P1&P2P_1 \& P_2 is K1K_1. The ratio of their respective radii is K2K_2. The ratio of their respective escape velocities is
View answer and explanation
Correct option: A
k1k2\sqrt{k_1 k_2}
Option A (k1k2\sqrt{k_1 k_2}) is correct because escape velocity is proportional to the square root of the product of g and R.
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