JEE PHYSICS MCQ: GRAVITATION

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Analyzing +4 | -1

In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface

\left( {{T_{st}}} \right)

, (ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth

\left( {{T_{ma}}} \right)

, (iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of

9.8N/kg\left( {{T_{sp}}} \right)

, (iv) Period of an infinite length simple pendulum in the earth’s real gravitational filed

\left( {{T_{is}}} \right)

View answer and explanation

Correct option: C

{T_{sp}} > {T_{is}}

Option C (

{T_{sp}} > {T_{is}}

) is correct because the period of a simple pendulum with length equal to Earth's radius in a uniform field is less than that of an infinite length simple pendulum in Earth's real gravitational field.

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