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NEET • PHYSICS • ELECTROMAGNETIC WAVES

Electromagnetic waves practice · Mixed difficulty

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Showing 121-145 of 145 questions

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121 Easy
121 of 145
Application +4 | -1
The wave function [in S.I unit] for an electromagnetic wave is given as ψ(x,t)=103sin⁡π[3×106x−9×1014t]\psi \left( {x,t} \right) = {10^3}\sin \pi \left[ {3 \times {{10}^6}x - 9 \times {{10}^{14}}t} \right] The speed of the wave is [in m/s]
View answer and explanation
Correct option: B
3×1083 \times {10^8}
Option B (3×1083 \times {10^8}) is correct because the speed of the wave can be found by dividing the coefficient of t by the coefficient of x.
122 Easy
122 of 145
Remembering +4 | -1
Rays in electromagnetic spectrum that has lowest frequency are
View answer and explanation
Correct option: A
Microwaves
Option A is correct because Microwaves have the lowest frequency among the given options in the electromagnetic spectrum.
123 Medium
123 of 145
Analyzing +4 | -1
When an electromagnetic waves enter the ionised layer of ionosphere, the motion of electron cloud produces a space current and the electric field has its own capacitative displacement current, then
View answer and explanation
Correct option: B
the space current lags behind the displacement current by a phase 180∘180^{\circ}.
Option B is correct because the space current, caused by the motion of electrons, lags behind the displacement current by 180 degrees due to the inertia of the electrons.
124 Hard
124 of 145
Remembering +4 | -1
Electromagnetic energy is radiated by:

(a) Stationary charge

(b) A charge in uniform motion

(c) An accelerated charge only

(d) An accelerated charge and a charge in uniform motion

Choose the correct statement.
View answer and explanation
Correct option: C
(c) only
Option C, (c) only, is correct because electromagnetic radiation is produced only by accelerated charges.
125 Easy
125 of 145
Understanding +4 | -1
In the case of a photon :-
View answer and explanation
Correct option: D
Its speed can change but cannot become equal to zero.
Option D (Its speed can change but cannot become equal to zero) is correct because a photon always travels at the speed of light in a given medium, and it cannot be stopped.
126 Easy
126 of 145
Application +4 | -1
The velocity of electromagnetic waves in a dielectric medium of constant 4 is
View answer and explanation
Correct option: A
1.5×108ms−11.5 \times {10^8}\mathrm{m}{\mathrm{s}^{ - 1}}
Option A (1.5×108  ms−11.5 \times {10^8}\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because the velocity of electromagnetic waves in a dielectric medium is given by v=c/ϵrv = c / \sqrt{\epsilon_r}, where ϵr\epsilon_r is the dielectric constant.
127 Hard
127 of 145
Application +4 | -1
An FM radio station, antenna radiates a power of 10 kW10 \mathrm{~kW} at a wavelength of 3 m3 \mathrm{~m}. Assume the radiated power is confined to and is uniform over a hemisphere with antenna at its centre. Emax⁡E_{\max } at a distance of 10 km10 \mathrm{~km} from antenna is
View answer and explanation
Correct option: D
0.10NC−10.10 \mathrm{NC}^{-1}
Option D (0.10NC−10.10 \mathrm{NC}^{-1}) is correct because the maximum electric field is related to the power and distance by Emax=2Pπϵ0cr2E_{max} = \sqrt{\frac{2P}{\pi \epsilon_0 c r^2}}.
128 Medium
128 of 145
Understanding +4 | -1
Given below are two statements:

Statement I : Electromagnetic waves are not deflected by electric and magnetic field.

Statement II: The amplitude of electric field and the magnetic field in electromagnetic waves are related to each other as E0=μ0ε0B0E_0=\sqrt{\frac{\mu_0}{\varepsilon_0}} B_0.

In the light of the above statements, choose the correct answer from the options given below :
View answer and explanation
Correct option: C
Statement I is true but statement II is false
Statement I is true because electromagnetic waves are uncharged and thus unaffected by electric and magnetic fields. Statement II is false because the correct relation is E0=cB0=1μ0ϵ0B0E_0 = cB_0 = \frac{1}{\sqrt{\mu_0 \epsilon_0}} B_0.
129 Easy
129 of 145
Application +4 | -1
Wave length of light of frequency 100 Hz is
View answer and explanation
Correct option: B
3×106 m3 \times {10^6}\,m
Option B (3×106 m3 \times {10^6}\,m) is correct because the wavelength is calculated by dividing the speed of light by the frequency.
130 Medium
130 of 145
Analyzing +4 | -1
Statement I: Displacement current decreases with the increase in frequency of a.c. supplied to the capacitor

Statement II: Reactance due to capacitance is directly proprtional to the frequency of a.c.
View answer and explanation
Correct option: B
Statement I is true; statement II is false
Option B is correct because Statement I is true, as displacement current is inversely proportional to frequency, and Statement II is false, as capacitive reactance is inversely proportional to frequency.
131 Medium
131 of 145
Remembering +4 | -1
The wavelength of infrared rays is of the order of
View answer and explanation
Correct option: C
Diverge more
Option A is correct because the wavelength of infrared rays is of the order of 5 × 10-7 m to 10-3 m, with 5 × 10-7 m being the closest.
132 Medium
132 of 145
Remembering +4 | -1
A radar sends the waves towards a distant object and receives the signal reflected by object. These waves are
View answer and explanation
Correct option: D
Micro waves
Option D is correct because Microwaves are used in radar systems to send waves towards distant objects and receive the reflected signal.
133 Medium
133 of 145
Remembering +4 | -1
The energy density associated with electric field E⃗\vec{E} and magnetic field B⃗\vec{B} of an electromagnetic wave in free space is given by (ε0−\left(\varepsilon_{0}-\right. permittivity of free space, μ0\mu_{0} - permeability of free space)
View answer and explanation
Correct option: B
UE=ε0E22, UB=B22μ0U_{E}=\frac{\varepsilon_{0} E^{2}}{2}, \, U_{B}=\frac{B^{2}}{2 \mu_{0}}
Option B (UE=ε0E22, UB=B22μ0U_{E}=\frac{\varepsilon_{0} E^{2}}{2}, \, U_{B}=\frac{B^{2}}{2 \mu_{0}}) is correct because it represents the energy density associated with electric and magnetic fields in an electromagnetic wave.
134 Medium
134 of 145
Application +4 | -1
The electric field associated with an EM wave in vaccum is given by E=i^40 cos⁡(KZ−6×108t)E = \hat i40\,\cos \left( {KZ - 6 \times {{10}^8}t} \right) where E1{E_1} ZZ and tt are in volt/m, metre and secants respectively. The value of wave vector k is
View answer and explanation
Correct option: A
2  m−12\,\,{m^{ - 1}}
Option A (2  m−12\,\,{m^{ - 1}}) is correct because the wave vector k is calculated from the angular frequency and the speed of light.
135 Medium
135 of 145
Remembering +4 | -1
The magnetic energy stored in a long solenoid of area of cross-section AA in a small region of length LL is:
View answer and explanation
Correct option: D
B2AL2μ0\frac{{B}^2 {AL}}{2 \mu_0}
Option D, B2AL2μ0\frac{{B}^2 {AL}}{2 \mu_0}, is correct because it represents the magnetic energy stored per unit volume multiplied by the volume of the region.
136 Easy
136 of 145
Application +4 | -1
Electromagnetic waves travel in a medium with speed of 1.5×108 ms−11.5 \times 10^8 \mathrm{~ms}^{-1}. The relative permeability of the medium is 2.0 . The relative permittivity will be :
View answer and explanation
Correct option: D
2
Option C (4) is correct because the refractive index n=c/v=μrϵrn = c/v = \sqrt{\mu_r \epsilon_r}, and solving for ϵr\epsilon_r gives ϵr=(c/v)2/μr\epsilon_r = (c/v)^2 / \mu_r.
137 Easy
137 of 145
Understanding +4 | -1
Which of the following are not electromagnetic waves
View answer and explanation
Correct option: C
β−rays\beta - rays
Option C is correct because beta rays are streams of particles (electrons or positrons), not electromagnetic waves.
138 Easy
138 of 145
Application +4 | -1
The frequency of a plane electromagnetic wave traveling in vacuum in X-direction is
30 MHz, its wavelength is
View answer and explanation
Correct option: C
10 m
Option C (10 m) is correct because wavelength is the speed of light divided by the frequency.
139 Easy
139 of 145
Remembering +4 | -1
The range of frequency allotted for FM radio is
View answer and explanation
Correct option: B
8888 to 108 MHz108 \mathrm{~MHz}
Option B is correct because the frequency range allotted for FM radio broadcasting is 88 to 108 MHz.
140 Medium
140 of 145
Understanding +4 | -1
An electromagnetic wave of intensity II falls on a surface kept in vacuum and exerts radiation pressure PP on it. Which of the following statement is not true?
View answer and explanation
Correct option: B
Radiation pressure is I/CI / C if the wave is totally reflected.
Option B (Radiation pressure is I/CI / C if the wave is totally reflected.) is not true because the radiation pressure is 2I/c2I/c when the wave is totally reflected.
141 Medium
141 of 145
Application +4 | -1
A plane electromagnetic wave travels in free space along the xx-direction. The electric field component of the wave at a particular point of space and time is E=6 Vm−1E = 6\,V{m^{ - 1}} along yy-direction. Its corresponding magnetic field component, BB would be
View answer and explanation
Correct option: A
2  ×  10−8 T2\,\, \times \,\,{10^{ - 8}}\,T along zz-direction
Option A (2  ×  10−8 T2\,\, \times \,\,{10^{ - 8}}\,T along zz-direction) is correct because the magnetic field is related to the electric field by B=EcB = \frac{E}{c} and the direction is given by the Poynting vector.
142 Medium
142 of 145
Understanding +4 | -1
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

Ex=E0sin⁡(kz−ωt)By=B0sin⁡(kz−ωt)\begin{array}{l} E_{x}=E_{0} \sin (k z-\omega t) \\ B_{y}=B_{0} \sin (k z-\omega t) \end{array}

Then the correct relation between E0{E}_{0} and B0{B}_{0} is given by
View answer and explanation
Correct option: C
kE0=ωBo{kE}_{0}=\omega {B}_{{o}}
Option C (kE0=ωBo{kE}_{0}=\omega {B}_{{o}}) is correct because the ratio of the electric field amplitude to the magnetic field amplitude is equal to the speed of light, and c=ω/kc = \omega/k.
143 Medium
143 of 145
Remembering +4 | -1
Which is having minimum wavelength?
View answer and explanation
Correct option: C
γ\gamma-rays
Option D (Cosmic rays) is correct because cosmic rays generally have the shortest wavelengths and highest energies among the given options.
144 Easy
144 of 145
Understanding +4 | -1
The property which is not of an electromagnetic wave travelling in free space is that:
View answer and explanation
Correct option: C
They originate from charges moving with uniform speed
The correct answer is that electromagnetic waves originate from accelerating charges, not charges moving with uniform speed. Option C is the correct answer.
145 Medium
145 of 145
Understanding +4 | -1
A charged particle oscillates about its mean equilibrium position with a frequency of 109{10^9} Hz. Frequency of the Electromagnetic Waves produced by the oscillator is
View answer and explanation
Correct option: C
109{10^9} Hz
Option C (109{10^9} Hz) is correct because the frequency of the electromagnetic waves produced by an oscillating charged particle is the same as the oscillation frequency of the particle.
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