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NEET • PHYSICS • ELECTROMAGNETIC WAVES
Electromagnetic waves practice · Mixed difficulty
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Showing 91-120 of 145 questions
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91
Medium
91 of 145
Application
+4 | -1
The amplitude of electric field in a parallel beam of light of intensity is
View answer and explanation
Correct option: D
Option D () is correct because the amplitude of the electric field is calculated using the intensity formula .
92
Medium
92 of 145
Analyzing
+4 | -1
If a charge particle of charge and mass is released at origin in gravity free space having and
and , then its speed
and , then its speed
View answer and explanation
Correct option: B
Depends only on co-ordinate
Option B is correct because the electric field is along the y-axis, causing acceleration in the y-direction. The magnetic field, also along the y-axis, does not exert a force on the particle since the velocity is initially along the y-axis. Therefore, the speed depends only on the y-coordinate.
93
Medium
93 of 145
Application
+4 | -1
Light with energy flux of is incident on a well polished disc of radios 3.5 cm for one hour. The momentum transferred to the disc is [in kgm ]
View answer and explanation
Correct option: B
Option B () is correct because it is the momentum transferred calculated using the formula for a reflecting surface.
94
Medium
94 of 145
Understanding
+4 | -1
Radio wave diffract around building although light waves do not. The reason is that radio waves
View answer and explanation
Correct option: B
Have much larger wavelength than light
Option B (Have much larger wavelength than light) is correct because diffraction is more pronounced when the wavelength of the wave is comparable to the size of the obstacle.
95
Medium
95 of 145
Application
+4 | -1
In an EMW in free space the root mean square value of the electric field is . The peak value of the magnetic field is [in Tesla]
View answer and explanation
Correct option: B
Option B () is correct because it is calculated using the relationship between electric and magnetic field amplitudes in an electromagnetic wave and the given RMS electric field.
96
Easy
96 of 145
Application
+4 | -1
In a place e.m. wave, the electric field oscillates sinusoidally at a frequency of and amplitude . The amplitude of oscillating magnetic field will be :-
View answer and explanation
Correct option: C
Option C () is correct because the amplitude of the oscillating magnetic field is calculated using the formula , where c is the speed of light.
97
Medium
97 of 145
Analyzing
+4 | -1
Assertion: The microwaves are better carriers of signals than radio waves.
Reason: The electromagnetic waves do not require any medium for propagation.
Reason: The electromagnetic waves do not require any medium for propagation.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because both statements are true, but the reason doesn't explain why microwaves are better carriers.
98
Easy
98 of 145
Remembering
+4 | -1
Rays in electromagnetic spectrum that has shortest wavelength are
View answer and explanation
Correct option: D
X-rays
Option D is correct because X-rays have the shortest wavelength among the given options in the electromagnetic spectrum.
99
Hard
99 of 145
Application
+4 | -1
Light with energy flux of falls on a non-reflecting surface of area at normal in cadence the momentum delivered in 30 minutes is [in kgm/s]
View answer and explanation
Correct option: B
Option B () is correct because it is calculated by finding the momentum delivered by the light to the surface over the given time.
100
Medium
100 of 145
Remembering
+4 | -1
For an electromagnetic wave traveling in free space
View answer and explanation
Correct option: A
Option A () is correct because the electric field amplitude is equal to the speed of light times the magnetic field amplitude in an electromagnetic wave.
101
Easy
101 of 145
Remembering
+4 | -1
Displacement Current is:
View answer and explanation
Correct option: D
Due to time Varying Electric field
Option D is correct because displacement current arises from a time-varying electric field, as described by Maxwell's equations.
102
Easy
102 of 145
Remembering
+4 | -1
The S.I. unit of displacement current is:
View answer and explanation
Correct option: C
Ampere
Option C (Ampere) is correct because displacement current, like regular current, is measured in Amperes.
103
Medium
103 of 145
Analyzing
+4 | -1
An electromagnetic wave travelling along -axis is given as: . Choose the INCORRECT options from the following;
View answer and explanation
Correct option: D
Option D is the INCORRECT option because for an electromagnetic wave traveling along the z-axis, the electric and magnetic fields are perpendicular to the direction of propagation, meaning their cross product with the direction vector is non-zero.
104
Medium
104 of 145
Application
+4 | -1
A plane electromagnetic wave is propagating along the direction with its polarization along the direction The correct form of the magnetic field of the wave would be (here is an appropriate constant)
View answer and explanation
Correct option: C
Option C () is correct because the magnetic field must be perpendicular to both the direction of propagation and the polarization direction of the electric field.
105
Medium
105 of 145
Understanding
+4 | -1
The magnetic field and electric field in an electromagnetic wave are:
View answer and explanation
Correct option: C
mutually perpendicular but with phase difference
Option C (mutually perpendicular but with phase difference) is correct because the electric and magnetic fields in an electromagnetic wave are perpendicular to each other and oscillate in phase.
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106
Medium
106 of 145
Remembering
+4 | -1
In an Electromagnetic Wave, direction of propagation is in the direction of
View answer and explanation
Correct option: C
Option C () is correct because the direction of propagation of an electromagnetic wave is given by the Poynting vector, which is proportional to the cross product of the electric and magnetic field vectors.
107
Medium
107 of 145
Remembering
+4 | -1
In a medium of dielectric constant , the electric field is . If is permittivity of the free space, the electric displacement vector is
View answer and explanation
Correct option: D
Option D () is correct because the electric displacement vector in a medium is given by the product of the dielectric constant, permittivity of free space, and the electric field.
108
Medium
108 of 145
Understanding
+4 | -1
If a long hollow copper pipe carries a direct current, the magnetic field associated with the current will be
View answer and explanation
Correct option: B
Only outside the pipe
Option B (Only outside the pipe) is correct because, according to Ampere's law, the magnetic field inside a hollow conductor carrying a direct current is zero, and the field exists only outside.
109
Easy
109 of 145
Understanding
+4 | -1
Let the velocities of light in vacuum and glass are represented by and . When electrons move through glass with a velocity , there emitted a visible radiation in glass if
View answer and explanation
Correct option: A
Option A () is correct because Cherenkov radiation is emitted when a charged particle moves through a dielectric medium faster than the speed of light in that medium.
110
Medium
110 of 145
Understanding
+4 | -1
The average value of electric energy density in an Electromagnetic Waves is ( is peak value)
View answer and explanation
Correct option: D
Option D () is correct because the average electric energy density is half of the product of permittivity and the square of the RMS electric field, and the RMS electric field is .
111
Medium
111 of 145
Understanding
+4 | -1
The energy of an electromagnetic wave contained in a small volume oscillates with
View answer and explanation
Correct option: A
Double the frequency of the wave
Option A (Double the frequency of the wave) is correct because the energy density is proportional to the square of the electric or magnetic field, and squaring a sinusoidal function doubles its frequency.
112
Medium
112 of 145
Remembering
+4 | -1
Phase difference between electric field and magnetic field associated with a plane
polarized light is
polarized light is
View answer and explanation
Correct option: A
zero
Option A (zero) is correct because the electric and magnetic fields in a plane polarized light wave are in phase.
113
Easy
113 of 145
Analyzing
+4 | -1
A proton moving with a constant velocity passes through a region of space without any change in its velocity. If and represent the electric and magnetic fields respectively, then the region of space may have:
(A)
(B)
(C)
(D)
Choose the most appropriate answer from the options given below:
(A)
(B)
(C)
(D)
Choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: C
(A), (B) and (D) only
Option C ((A), (B) and (D) only) is correct because a proton can move with constant velocity if there are no fields, only a magnetic field (velocity parallel to B), or both electric and magnetic fields such that their forces cancel out.
114
Medium
114 of 145
Understanding
+4 | -1
The ratio of average electric energy density and total average energy density of electromagnetic wave is
View answer and explanation
Correct option: D
Option D () is correct because the average electric energy density is half of the total average energy density in an electromagnetic wave, as the energy is equally distributed between the electric and magnetic fields.
115
Hard
115 of 145
Application
+4 | -1
An alternating voltage (in volts) is connected to one microfarad capacitor. The reading of the ammeter shall be
View answer and explanation
Correct option: D
Option D is correct because the current is calculated using the formula where .
116
Medium
116 of 145
Understanding
+4 | -1
A parallel plate capacitor is charged to . Due to a radioactive source, the plate loss charge at the rate of The magnitude of displacement current is
View answer and explanation
Correct option: A
Option A () is correct because the displacement current is equal to the rate of change of charge on the capacitor plates.
117
Easy
117 of 145
Understanding
+4 | -1
If are the electric and magnetic field vectors of E.M waves then the direction of propagation of E.M wave is along the direction of
View answer and explanation
Correct option: C
Option C, , is correct because the direction of propagation of an electromagnetic wave is given by the Poynting vector, which is proportional to the cross product of the electric and magnetic field vectors.
118
Medium
118 of 145
Application
+4 | -1
An electromagnetic wave is travelling to the east. At one instant at a given point its E vector points straight up. What is the direction of is B vector ?
View answer and explanation
Correct option: C
South
Option C (South) is correct because the direction of propagation, electric field, and magnetic field are mutually perpendicular, and following the right-hand rule, if E is up and the wave travels East, B must be South.
119
Medium
119 of 145
Application
+4 | -1
The wave function (in S.I units) for an electromagnetic wave is given as . The speed of wave is :
View answer and explanation
Correct option: B
Option B () is correct because the speed of the wave is calculated by dividing the coefficient of time by the coefficient of position in the wave equation.
120
Easy
120 of 145
Application
+4 | -1
A plane electromagnetic wave travels in a medium of relative permittivity 2 and relative permeability If the magnitude of magnetic intensity is at a point, then the electric field at that point in ___ .
View answer and explanation
Correct option: A
Option A (1.80) is correct because the electric field is calculated using the formula , where is the speed of light in the medium.
Revision notes and key takeaways
Review ELECTROMAGNETIC WAVES in your textbook or class notes, then use this set to check your understanding.
Showing 91-120 of 145 questions
