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NEET • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Mixed difficulty

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Showing 151-180 of 245 questions

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151 Medium
151 of 245
Analyzing +4 | -1
Assertion:- When charges are shared between two parallel plate capacitors, charge of system is conserved but some energy is lost.
Reason:- During the sharing of charges, some energy is dissipated as heat.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion because charge is conserved, but energy is lost as heat due to resistance in connecting wires during charge sharing.
152 Medium
152 of 245
Analyzing +4 | -1
Assertion: A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant k{k} is introduced between the plates. The energy stored becomes k{k} times.
Reason: The surface density of charge on the plate remains constant.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because the surface charge density changes when a dielectric is inserted with the battery connected.
153 Medium
153 of 245
Application +4 | -1
ABCABC is an equilateral triangle of side 2m2m. If E→=10  NC−1\overrightarrow E = 10\,\,N{C^{ - 1}} then VA−VB{V_A} - {V_B} is
View answer and explanation
Correct option: B
−10V- 10V
Option B (−10V- 10V) is correct because the potential difference is calculated as VA−VB=−E⋅dV_A - V_B = -E \cdot d, where d is the displacement vector from B to A.
154 Medium
154 of 245
Understanding +4 | -1
Torque acting on an electric dipole in a uniform electric field is maximum if the angle between p and E is
View answer and explanation
Correct option: C
90°
Option C (90°) is correct because the torque on an electric dipole is maximum when the angle between the dipole moment and the electric field is 90 degrees.
155 Medium
155 of 245
Application +4 | -1
The capacitance of an air capacitor is 15μF15\mu F the separation between the parallel plates is 6mm.6mm. A copper plate of 3mm3mm thickness is introduced symmetrically between the plates. The capacitance now becomes
View answer and explanation
Correct option: D
30μF30\mu F
Option D (30μF30\mu F) is correct because inserting a copper plate reduces the effective distance between the plates, increasing the capacitance.
156 Medium
156 of 245
Understanding +4 | -1
A soap bubble is given a negative charge, then its radius
View answer and explanation
Correct option: B
Increases
Option B is correct because the negative charge on the soap bubble will cause repulsion between the charges, increasing the surface area and thus the radius.
157 Medium
157 of 245
Understanding +4 | -1
Three capacitors of capacity C1,C2,C3{C_1},{C_2},{C_3} are connected in series. Their total capacity will be
View answer and explanation
Correct option: C
(C1−1+C2−1+C3−1)−1{\left( {C_1^{ - 1} + C_2^{ - 1} + C_3^{ - 1}} \right)^{ - 1}}
Option C is correct. The total capacitance of capacitors in series is the inverse of the sum of the inverses of individual capacitances.
158 Medium
158 of 245
Analyzing +4 | -1
Identify the WRONG statement
View answer and explanation
Correct option: C
The electrical potential energy of a proton electron system will increase if the separation between the two is increased
Option C (The electrical potential energy of a proton electron system will increase if the separation between the two is increased) is the WRONG statement because increasing the separation between a proton and electron decreases the potential energy (which is negative).
159 Easy
159 of 245
Application +4 | -1
The capacity of a parallel plate condenser consisting of two plates each 10 cm square and are separated by a distance of 2 mm is [Take air as the medium between the plates]
View answer and explanation
Correct option: D
4.42×10−12  F4.42 \times {10^{ - 12}}\,\,F
Option D (4.42×10−12 F4.42 \times {10^{ - 12}}\,F) is correct because it is the result of calculating the capacitance of a parallel plate capacitor using the given dimensions and the permittivity of air.
160 Medium
160 of 245
Understanding +4 | -1
Which among the following represents the expression of displacement current during charging of a capacitor? (Symbols have their usual meaning)
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Correct option: D
All of these
Option D (All of these) is correct because all the given expressions are valid representations of the displacement current during the charging of a capacitor.
161 Medium
161 of 245
Application +4 | -1
The work done in carrying a charge of 5μC5\mu C from a point AA to a point BB in an electric field is 10mJ10mJ. The potential difference (VB−VA)\left( {{V_B} - {V_A}} \right) is then
View answer and explanation
Correct option: B
−2kV- 2kV
Option B (- 2kV) is correct because the potential difference is calculated using the formula W=q(VB−VA)W = q(V_B - V_A), where W is the work done and q is the charge.
162 Medium
162 of 245
Application +4 | -1
The plates of a parallel plate condenser are pulled apart with a velocity v.v. If at any instant their mutual distance of separation is d,d, then the magnitude of the time of rate of change of capacity depends on dd as follows
View answer and explanation
Correct option: B
1/d21/{d^2}
Option B (1/d21/{d^2}) is correct because the rate of change of capacitance is inversely proportional to the square of the distance between the plates.
163 Easy
163 of 245
Understanding +4 | -1
A positively charged particle is released from rest in an uniform electric field. The electric potential energy of the charge
View answer and explanation
Correct option: C
Decreases because the charge moves along the electric field
Option C is correct because a positively charged particle moves along the electric field from a region of higher potential to lower potential, thus decreasing its electric potential energy.
164 Medium
164 of 245
Analyzing +4 | -1
Considering a group of positive charges, which of the following statements is correct?
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Correct option: A
Net potential of the system cannot be zero at a point but net electric field can be zero at that point.
Option A is correct because the electric potential is a scalar quantity and cannot be zero if all charges are positive, while the electric field is a vector quantity and can be zero due to cancellation.
165 Medium
165 of 245
Remembering +4 | -1
The capacity of parallel plate condenser depends on
View answer and explanation
Correct option: D
The separation between the plates
Option D (The separation between the plates) is correct because the capacitance of a parallel plate capacitor is inversely proportional to the distance between the plates.
166 Easy
166 of 245
Analyzing +4 | -1
A parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved farther apart by pulling at them by means of insulating handles, then
View answer and explanation
Correct option: D
The voltage across the capacitor increases
Option D (The voltage across the capacitor increases) is correct because when the plates are moved apart after disconnecting the battery, the charge remains constant, and the capacitance decreases, leading to an increase in voltage.
167 Medium
167 of 245
Understanding +4 | -1
The potential at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively
View answer and explanation
Correct option: D
0o{0^\mathrm{o}} and 180o{180^\mathrm{o}}
Option D (0o{0^\mathrm{o}} and 180o{180^\mathrm{o}}) is correct because the potential due to a dipole is maximum when the angle is 0 degrees and minimum when the angle is 180 degrees.
168 Medium
168 of 245
Understanding +4 | -1
The intensity of electric field at a point between the plates of a charged capacitor
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Correct option: D
Does not depend upon the distance between the plates
Option D is correct. The electric field between the plates of a charged capacitor is uniform and does not depend on the distance between the point and the plates.
169 Medium
169 of 245
Application +4 | -1
0.2F0.2F capacitor is charged to 600  V600\;V by a battery. On removing the battery, it is connected with another parallel plate condenser of 1F.1F. The potential decreases to
View answer and explanation
Correct option: A
100  volts100\;volts
Option A (100 volts) is correct because the total charge is conserved and redistributed between the two capacitors, leading to a new potential.
170 Medium
170 of 245
Application +4 | -1
Capacitance (in  F)\left( {\mathrm{in\;}F} \right) of a spherical conductor with radius 1  m1\;m is
View answer and explanation
Correct option: A
1.1×10−101.1 \times {10^{ - 10}}
Option A is correct. The capacitance of a spherical conductor is given by C = 4πε₀r.
171 Medium
171 of 245
Remembering +4 | -1
The value of electric potential at any point due to any electric dipole is
View answer and explanation
Correct option: D
k.p⃗.r⃗r3k.\frac{{\vec p.\vec r}}{{{r^3}}}
Option D (k.p⃗.r⃗r3k.\frac{{\vec p.\vec r}}{{{{r^3}}}}) is correct because the electric potential due to an electric dipole is proportional to the dot product of the dipole moment and the position vector, divided by the cube of the distance.
172 Medium
172 of 245
Understanding +4 | -1
On increasing the plate separation of a charged condenser, the energy
View answer and explanation
Correct option: A
Increases
Option A (Increases) is correct because increasing the plate separation increases the potential difference for a constant charge, thus increasing the energy stored.
173 Medium
173 of 245
Application +4 | -1
What is the potential energy of the equal positive point charges of 1μC1\mu C each held 1  m1\;m apart in air
View answer and explanation
Correct option: A
9×10−3  J9 \times {10^{ - 3}}\;J
Option A (9 × 10-3 J) is correct because the potential energy of two point charges is calculated using U = kQ1Q2/r.
174 Medium
174 of 245
Understanding +4 | -1
The potential to which a conductor is raised, depends on
View answer and explanation
Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because the potential of a conductor depends on both the amount of charge and the geometry and size of the conductor.
175 Medium
175 of 245
Application +4 | -1
An electric dipole consists of two opposite charges, each of magnitude 1.0 μ\mathrm{\mu }C separated by a distance of 2.0 cm. the dipole is placed in an external electric field of 105{10^5} NC−1N{C^{ - 1}}. The maximum torque on the dipole is
View answer and explanation
Correct option: C
2×10−3\times {10^{ - 3}}N-m
Option C (2×10−3\times {10^{ - 3}}N-m) is correct because it is the maximum torque calculated using the formula torque = dipole moment * electric field.
176 Medium
176 of 245
Application +4 | -1
A parallel plate air capacitor is charged to a potential difference of V.V. After disconnecting the battery, distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates
View answer and explanation
Correct option: B
Increases
Option D (5×1075 \times {10^7}) is correct because the electric field is the energy gained divided by the charge and the mean free path.
177 Medium
177 of 245
Understanding +4 | -1
The electric potential inside a conducting sphere
View answer and explanation
Correct option: C
Remains constant from centre to surface
Option C is correct because the electric field inside a conductor is zero, so the potential is constant and equal to the potential at the surface.
178 Medium
178 of 245
Application +4 | -1
An electric dipole consists of two opposite charges of magnitude q=1×10−6  q = 1 \times {10^{ - 6\;}} C separated by 2.0 cm. the dipole is placed in an external field of 1×1051 \times {10^5} NC−1\mathrm{N}{\mathrm{C}^{ - 1}}. What maximum torque does the field exert on the dipole? How much work must an external agent do to turn the dipole end for end, starting from position of alignment (θ=00\mathrm{\theta } = {0^0})
View answer and explanation
Correct option: D
2×10−3  N−m,  4×10−3  J2 \times {10^{ - 3\;}}\mathrm{N} - \mathrm{m},\;4 \times {10^{ - 3}}\mathrm{\;J}
Option D (2×10−3  N−m,  4×10−3  J2 \times {10^{ - 3\;}}\mathrm{N} - \mathrm{m},\;4 \times {10^{ - 3}}\mathrm{\;J}) is correct because it accurately calculates the maximum torque and work done using the electric dipole moment and electric field.
179 Medium
179 of 245
Application +4 | -1
An electric dipole of moment pp is placed in the position of stable equilibrium in uniform electric field of intensity E.E. It is rotated through an angle θ\theta from the initial position. The potential energy of electric dipole in the final position is
View answer and explanation
Correct option: D
−pEcos⁡θ- pE\cos \theta
Option D (−pEcos⁡θ- pE\cos \theta) is correct because the potential energy of a dipole in an electric field is given by U=−pEcos⁡θU = -pE \cos \theta, where θ\theta is the angle between the dipole moment and the electric field.
180 Easy
180 of 245
Understanding +4 | -1
Two spheres of unequal radii are supplied with equal quantity of charges. The potential will
View answer and explanation
Correct option: B
Be more on the smaller sphere
Option B is correct because the electric potential is inversely proportional to the radius, so the smaller sphere will have a higher potential.
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