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NEET • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Mixed difficulty

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Showing 121-150 of 245 questions

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121 Medium
121 of 245
Analyzing +4 | -1
An electric dipole is placed in an electric field generated by a point charge. Then which of the following statements is true?
View answer and explanation
Correct option: D
The torque on the dipole due to the field may be zero
Option D (The torque on the dipole due to the field may be zero) is correct because the torque is zero when the dipole is aligned with or anti-aligned with the electric field.
122 Medium
122 of 245
Understanding +4 | -1
An electric dipole is kept in non-uniform electric field. It experiences
View answer and explanation
Correct option: A
A force and a torque
Option A (A force and a torque) is correct because a non-uniform electric field exerts both a net force and a torque on an electric dipole.
123 Medium
123 of 245
Understanding +4 | -1
Two metal spheres of capacitance C1{C_1} and C2{C_2} carry some charges. They are put in contact and then separated. The final charges Q1{Q_1} and Q2{Q_2} on them will satisfy
View answer and explanation
Correct option: B
Q1Q2=C1C2\frac{{{Q_1}}}{{{Q_2}}} = \frac{{{C_1}}}{{{C_2}}}
Option B (Q1Q2=C1C2\frac{{{Q_1}}}{{{Q_2}}} = \frac{{{C_1}}}{{{C_2}}}) is correct because when the spheres are in contact, they have the same potential, and the charge is distributed proportionally to their capacitances.
124 Medium
124 of 245
Remembering +4 | -1
If a dipole of dipole moment p⃗\vec{\text{p}} is placed in a uniform electric field E→,\overrightarrow{\mathrm{E}}, then torque acting on it is given by
View answer and explanation
Correct option: B
τ⃗=p→×E→\vec{\tau}=\overrightarrow{\mathrm{p}} \times \overrightarrow{\mathrm{E}}
Option B (τ⃗=p→×E→\vec{\tau}=\overrightarrow{\mathrm{p}} \times \overrightarrow{\mathrm{E}}) is correct because the torque on a dipole in a uniform electric field is given by the cross product of the dipole moment and the electric field.
125 Hard
125 of 245
Analyzing +4 | -1
Assertion (A) : If we see along the axis of a charged ring, the magnitude of electric field is minimum at centre and magnitude of electric potential is maximum.

Reason (R): Electric field is a vector quantity while electric potential is scalar.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because while both statements are true, the scalar vs. vector nature doesn't directly explain the field/potential behavior on the ring's axis.
126 Medium
126 of 245
Application +4 | -1
A point QQ lies on the perpendicular bisector of an electrical dipole of dipole moment p.p. If the distance of QQ from the dipole is rr (much larger than the size of the dipole), then electric field at QQ is proportional to
View answer and explanation
Correct option: D
pp and r−3{r^{ - 3}}
Option D (pp and r−3{r^{ - 3}}) is correct because the electric field due to a dipole at a point on the perpendicular bisector is inversely proportional to the cube of the distance and directly proportional to the dipole moment.
127 Medium
127 of 245
Analyzing +4 | -1
Two similar parallel-plate capacitors each of capacity C0C_0 are connected in series. The combination is connected with a voltage source of V0V_0. Now, separation between the plates of one capacitor is increased by a distance dd and the separation between the plates of another capacitor is decreased by the distance d/2d / 2. The distance between the plates of each capacitor was dd before the change in separation. Then, select the correct choice.
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Correct option: B
The new capacity of the system will decrease
Option B (The new capacity of the system will decrease) is correct because the equivalent capacitance of series capacitors decreases when one capacitor's separation increases and the other's decreases by half the amount.
128 Hard
128 of 245
Application +4 | -1
A capacitor of capacitance CC has charge QQ and stored energy is W.W. If the charge is increased to 3Q,3Q, the stored energy will be
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Correct option: C
9W9W
Option C (9W9W) is correct because the energy stored is proportional to the square of the charge, so tripling the charge increases the energy by a factor of 9.
129 Medium
129 of 245
Remembering +4 | -1
Dielectric constant of a medium is also known as:
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Correct option: D
Relative permittivity
Option D (Relative permittivity) is correct because the dielectric constant is defined as the ratio of the permittivity of the medium to the permittivity of free space, which is the relative permittivity.
130 Medium
130 of 245
Application +4 | -1
A potential difference of 300  volts300\;volts is applied to a combination of 2.0μF2.0\mu F and 8.0μF8.0\mu F capacitors connected in series. The charge on the 2.0μF2.0\mu F capacitor is
View answer and explanation
Correct option: B
4.8×10−4C4.8 \times {10^{ - 4}}C
Option A (2.4×10−4C2.4 \times {10^{ - 4}}C) is correct because the charge is the same on capacitors in series, and it's calculated using the equivalent capacitance and the applied voltage.
131 Easy
131 of 245
Application +4 | -1
The energy stored in a capacitor of capacitance 100μF100 \mu F is 50J50 J. Its potential difference is
View answer and explanation
Correct option: C
1000 V
Option C (1000 V) is correct because it is calculated using the formula for energy stored in a capacitor: U = (1/2)CV2.
132 Medium
132 of 245
Understanding +4 | -1
An electric dipole of moment P⃗\vec{P} placed in a uniform electric field E⃗\vec{E} has maximum potential energy when the angle between P⃗\vec{P} and E⃗\vec{E} is
View answer and explanation
Correct option: C
π\pi
Option C (π\pi) is correct because the potential energy of a dipole in an electric field is given by U=−pEcos⁡θU = -pE \cos{\theta}, which is maximum when cos⁡θ=−1\cos{\theta} = -1, i.e., θ=π\theta = \pi.
133 Medium
133 of 245
Understanding +4 | -1
For measurement of potential difference, potentiometer is preferred in comparison to voltmeter because:-
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Correct option: D
Potentiometer does not take current from the circuit
Option D (Potentiometer does not take current from the circuit) is correct because a potentiometer measures potential difference without drawing current from the circuit, making it more accurate.
134 Medium
134 of 245
Application +4 | -1
A parallel plate air capacitor has a capacitance of 100μμF.100\mu \mu F. The plates are at a distance dd apart. If a slab of thickness t(t≤d)t\left( {t \le d} \right) and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be
View answer and explanation
Correct option: C
200  μμF200\;\mu \mu F
Option C (200μμF200\mu \mu F) is correct because inserting a dielectric slab increases the capacitance, and the formula for capacitance with a dielectric is used to calculate the new capacitance.
135 Easy
135 of 245
Application +4 | -1
A capacitor of capacitance C1C_1 is charged to a potential VV and then connected in parallel to an uncharged capacitor of capacitance C2C_2. The final potential difference across each capacitor will be
View answer and explanation
Correct option: A
C1VC1+C2\frac{C_1 V}{C_1+C_2}
Option A (C1VC1+C2\frac{C_1 V}{C_1+C_2}) is correct because the total charge is conserved, and the final potential is the total charge divided by the total capacitance.
136 Hard
136 of 245
Application +4 | -1
An electric field (−30i^+20j^)Vm−1(-30 \hat{\mathrm{i}}+20 \hat{\mathrm{j}}) \mathrm{Vm}^{-1} exists in the space. If potential at the origin is zero then potential at (5 m,3 m)(5 \mathrm{~m}, 3 \mathrm{~m}) is given by
View answer and explanation
Correct option: B
90 V90 \mathrm{~V}
Option B (90 V) is correct because the potential difference is calculated by integrating the electric field along the path from the origin to (5 m, 3 m).
137 Medium
137 of 245
Application +4 | -1
The mean free path of electrons in a metal is 4×10−8m.4 \times {10^{ - 8}}m. The electric field which can give on an average 2  eV2\;eV energy to an electron in the metal will be in units of V/mV/m
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Correct option: D
5×1075 \times {10^7}
Option D (5×1075 \times {10^7}) is correct because it is calculated using the relationship between electric field, energy, and mean free path.
138 Medium
138 of 245
Understanding +4 | -1
A closed solid conductor of irregular shape is given some charge. Which of the following statement is correct?
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Correct option: A
Potential of conductor will change if its shape is changed
Option A (Potential of conductor will change if its shape is changed) is correct because the potential of a conductor depends on its geometry, and changing the shape alters the charge distribution and thus the potential.
139 Medium
139 of 245
Understanding +4 | -1
The plates of a charged condenser is connected to a voltmeter. If the plates are moved apart, the reading of voltmeter will
View answer and explanation
Correct option: A
Increase
Option A is correct because as the plates move apart, the capacitance decreases, and since the charge remains constant, the voltage increases.
140 Medium
140 of 245
Understanding +4 | -1
A charge of Q  coulombQ\;\mathrm{ }coulomb is placed on a solid piece of metal irregular shape. The charge will distribute itself
View answer and explanation
Correct option: C
Such that potential energy of the system is minimised
Option C is correct because the charge distribution on a conductor always seeks to minimize the potential energy of the system.
141 Medium
141 of 245
Understanding +4 | -1
Work done in carrying a charge around an equipotential surface will
View answer and explanation
Correct option: C
Zero
Option C is correct because the potential is constant on an equipotential surface, so no work is required to move a charge along it.
142 Medium
142 of 245
Remembering +4 | -1
In an electric field E\mathbf{E}, the torque acting on a dipole moment p\mathbf{p} is
View answer and explanation
Correct option: B
p×E\mathbf{p} \times \mathbf{E}
Option B (p×E\mathbf{p} \times \mathbf{E}) is correct because the torque on a dipole in an electric field is given by the cross product of the dipole moment and the electric field.
143 Medium
143 of 245
Remembering +4 | -1
Potential and potential gradient is a:
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Correct option: A
Scalar and vector
Option A (Scalar and vector) is correct because electric potential is a scalar quantity, while the potential gradient is a vector quantity.
144 Easy
144 of 245
Application +4 | -1
Three capacitors each of capacitance 1μF1 \mu \mathrm{F} are connected in parallel. To the combination, a fourth capacitor of capacitance 1μF1 \mu \mathrm{F} is connected in series. The resultant capacitance of the system is
View answer and explanation
Correct option: D
(3/4)μF(3 / 4) \mu\mathrm{F}
Option D is correct. First, find the equivalent capacitance of the parallel combination, then combine it in series with the fourth capacitor.
145 Medium
145 of 245
Application +4 | -1
If the force exerted by an electric dipole on a charge q at a distance of 1 m is F, the force at a point 2 m away in the same direction will be
View answer and explanation
Correct option: D
F8\frac{F}{8}
Option D (F8\frac{F}{8}) is correct because the force exerted by a dipole on a charge decreases with the cube of the distance.
146 Medium
146 of 245
Analyzing +4 | -1
Assertion (A): Two capacitor of same capacity are connected first in parallel and then in series. The ratio of resultant capacities in the two cased will be 4:1.4: 1.

Reason (R): In parallel, capacity increases and in series capacity decreases.
View answer and explanation
Correct option: B
Both A and R are true but R is not a correct
explanation for A
Option B (Both A and R are true but R is not a correct explanation for A) is correct. The ratio of capacitances is 4:1, and the reason correctly states the general behavior of capacitors in series and parallel, but doesn't explain the ratio.
147 Medium
147 of 245
Understanding +4 | -1
If the charge on a capacitor is doubled, the value of its capacitance CC will be
View answer and explanation
Correct option: C
Remain the same
Option C (Remain the same) is correct because capacitance is a property of the capacitor itself and depends on its geometry, not the charge stored on it.
148 Medium
148 of 245
Analyzing +4 | -1
Assertion:- A parallel plate capacitor is connected across a battery through a key. A dielectric slab of dielectric constant KK is introduced between the plates. The energy which is stored becomes KK times.
Reason:- The potential difference between the plates remains constant or unchanged.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the potential difference remains constant when connected to a battery.
149 Medium
149 of 245
Application +4 | -1
If there are nn capacitors in parallel connected to V  voltV\;volt source, then the energy stored is equal to
View answer and explanation
Correct option: B
12nCV2\frac{1}{2}nC{V^2}
Option B (12nCV2\frac{1}{2}nC{V^2}) is correct because it represents the total energy stored in n capacitors connected in parallel, where the equivalent capacitance is nC.
150 Medium
150 of 245
Application +4 | -1
If a charged spherical conductor of radius 10cm10cm has potential VV at a point distant 5  cm5\;cm from its centre, then the potential at a point distant 15  cm15\;cm from the centre will be
View answer and explanation
Correct option: B
23V\frac{2}{3}V
Option B (2/3 V) is correct because the potential inside a charged spherical conductor is constant and equal to the potential at the surface, while outside it decreases with distance.
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