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NEET • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Mixed difficulty

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61 Medium
61 of 245
Application +4 | -1
There is an air filled 1pF1pF parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to 2pF2pF. The dielectric constant of wax is
View answer and explanation
Correct option: B
4
Option B (4) is correct because the dielectric constant is calculated using the formula for capacitance with a dielectric, considering the change in plate separation.
62 Medium
62 of 245
Analyzing +4 | -1
A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in
View answer and explanation
Correct option: C
Decrease in the potential difference across the plates, reduction in the stored energy, but no change in the charge on the plates
Option C (Decrease in the potential difference across the plates, reduction in the stored energy, but no change in the charge on the plates) is correct because inserting a dielectric increases capacitance, which decreases the potential difference and stored energy while charge remains constant.
63 Medium
63 of 245
Understanding +4 | -1
Ten electrons are equally spaced and fixed around a circle of radius R.R. Relative to V=0V = 0 at infinity, the electrostatic potential VV and the electric field EE at the centre CC are
View answer and explanation
Correct option: B
V≠0  and  E⃗=0V \ne 0\;\mathrm{and\;}\vec E = 0
Option B (V≠0  and  E⃗=0V \ne 0\;\mathrm{and\;}\vec E = 0) is correct because the potential due to multiple charges is non-zero, but the electric field at the center due to symmetrically placed equal charges is zero.
64 Easy
64 of 245
Understanding +4 | -1
Some charge is being given to a conductor. Then, its potential
View answer and explanation
Correct option: C
Is same throughout the conductor.
The correct answer is C (Is same throughout the conductor) because in electrostatic equilibrium, the electric field inside a conductor is zero, implying that the potential is constant throughout.
65 Medium
65 of 245
Analyzing +4 | -1
Statement-I: In bringing an electron towards a proton electrostatic potential energy of the system increases.

Statement-II: Potential due to proton is positive.
View answer and explanation
Correct option: D
Statement-I is false, Statement-II is false
Option C (Statement-I is false, Statement-II is true) is incorrect. Statement-I is false because bringing an electron towards a proton decreases the potential energy of the system. Statement-II is true because protons have a positive charge, and thus create a positive potential.
66 Easy
66 of 245
Understanding +4 | -1
Two charged conducting spheres of radii a\mathrm{a} and b\mathrm{b} are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:
View answer and explanation
Correct option: C
ab\frac{\mathrm{a}}{\mathrm{b}}
Option C is correct because when two charged conductors are connected, they reach the same potential. Therefore, the ratio of their charges is equal to the ratio of their radii, i.e., Q1/Q2=a/bQ_1/Q_2 = a/b.
67 Medium
67 of 245
Application +4 | -1
A non-conducting ring of radius 0.5  m0.5\;m carries a total charge of 1.11×10−10C1.11 \times {10^{ - 10}}C distributed non-uniformly on its circumference producing an electric field E⃗\vec E everywhere in space. The value of the line integral ∫l=0l=∞−E⃗.dl→  (l=0\int_{l = 0}^{l = \infty } { - \vec E.\overrightarrow {dl} \;(l = 0} being centre of the ring) in volt is
View answer and explanation
Correct option: A
+2+ 2
Option A (+2+ 2) is correct because the line integral of the electric field from the center to infinity is equal to the potential difference between those points, which is the potential at the center.
68 Easy
68 of 245
Understanding +4 | -1
A parallel plate capacitor is connected with a battery whose potential difference remains constant . If the plates of the capacitor are shifted apart then the intensity of electric field :
View answer and explanation
Correct option: B
remains constant but charge on plates decreases.
Option B (remains constant but charge on plates decreases) is correct because the potential difference is kept constant by the battery, and as the plates are shifted apart, the capacitance decreases, leading to a decrease in charge.
69 Medium
69 of 245
Understanding +4 | -1
When one electron is taken towards the other electron, then the electric potential energy of the system
View answer and explanation
Correct option: B
Increases
Option B (Increases) is correct because bringing two electrons closer increases the potential energy due to repulsive forces.
70 Hard
70 of 245
Remembering +4 | -1
The energy stored in a parallel plate capacitor can be treated as the energy of the electric field. The energy per unit volume, due to the electric field is
View answer and explanation
Correct option: B
12ε0E2\frac{1}{2} \varepsilon_0 E^2
Option B (12ε0E2\frac{1}{2} \varepsilon_0 E^2) is correct because it represents the energy per unit volume (energy density) of the electric field in a capacitor.
71 Medium
71 of 245
Application +4 | -1
A cylindrical capacitor has charge QQ and length L.L. If both the charge and length of the capacitor are doubled, by keeping other parameters fixed, the energy stored in the capacitor
View answer and explanation
Correct option: B
Increases two times
Option B (Increases two times) is correct because doubling both charge and length doubles the energy stored in the cylindrical capacitor.
72 Medium
72 of 245
Understanding +4 | -1
A parallel plate capacitor is charged. If the plates are pulled apart
View answer and explanation
Correct option: B
The potential difference increases
Option B (The potential difference increases) is correct because pulling the plates apart decreases the capacitance, and since the charge remains constant, the potential difference must increase.
73 Hard
73 of 245
Understanding +4 | -1
Given below are two statements.
Statement I : Electric potential is constant within
and at the surface of each conductor.
Statement II : Electric field just outside a charged
conductor is perpendicular to the surface of the
conductor at every point.
In the light of the above statements, choose the
most appropriate answer from the options given
below.
View answer and explanation
Correct option: A
Both statement I and statement II are correct
Option A (Both statement I and statement II are correct) is correct because electric potential is constant within and on the surface of a conductor, and the electric field is always perpendicular to the surface.
74 Medium
74 of 245
Remembering +4 | -1
In which form energy is stored in a capacitor:
View answer and explanation
Correct option: A
Electric field
Option A (Electric field) is correct because the energy in a capacitor is stored in the form of an electric field between its plates.
75 Medium
75 of 245
Application +4 | -1
A sample of HClHCl gas is placed in an electric field of 3×104  NC−1.3 \times {10^4}\;N{C^{ - 1}}. The dipole moment of each HClHCl molecule is 6×10−30c×m.6 \times {10^{ - 30}}c \times m. The maximum torque that can act on a molecule is
View answer and explanation
Correct option: C
18×10−26  Nm18 \times {10^{ - 26}}\;Nm
Option C (18×10−26  Nm18 \times {10^{ - 26}}\;Nm) is correct because it is the maximum torque calculated using the formula torque = dipole moment * electric field.
76 Medium
76 of 245
Application +4 | -1
The electric potential VV at any point (x,y,z)\left( {x,y,z} \right), all in meters in space is given by V=4x2  volt.V = 4{x^2}\;volt. The electric field at the point (1,0,2)\left( {1,0,2} \right) in volt/metervolt/meter, is
View answer and explanation
Correct option: B
8 along negative XX-axis
Option B (8 along negative XX-axis) is correct because the electric field is the negative gradient of the potential, and in this case, it points in the negative x-direction.
77 Easy
77 of 245
Application +4 | -1
The capacity of a capacitor is 20 F and potential is 5 volts. The charge on the capacitor is
View answer and explanation
Correct option: A
100 coulomb
Option A is correct. The charge on the capacitor is calculated using the formula Q = CV, where C is the capacitance and V is the potential.
78 Hard
78 of 245
Understanding +4 | -1
While a capacitor remains connected to a battery and dielectric slab is applied between the plates, then
View answer and explanation
Correct option: B
Charge flows from the battery to the capacitor
Option B (Charge flows from the battery to the capacitor) is correct because the capacitance increases with the dielectric, and since the voltage is constant, the charge must increase.
79 Hard
79 of 245
Analyzing +4 | -1
Assertion (A): Two charges −q-q each are fixed at points AA and BB. When a third charge −q-q is moved from AA to BB, electrical potential energy first decreases than increases.

Reason (R) : Along the line joining AA and BB, the third charge is in stable equilibrium position at centre.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
Option A (If both Assertion and Reason are true and the Reason is correct explanation of the Assertion) is correct because the potential energy decreases as the third charge moves towards the midpoint (stable equilibrium) and then increases as it moves away.
80 Medium
80 of 245
Understanding +4 | -1
The electric potential due to a small electric dipole at a large distance rr from the centre of the dipole is proportional to
View answer and explanation
Correct option: B
1/r1/r
Option B (1/r1/r) is correct because the electric potential due to a dipole decreases as the inverse of the distance from the dipole.
81 Hard
81 of 245
Understanding +4 | -1
A point charge +Q+ Q is located at a distance of ′r′'r' from the centre of an uncharged conducting sphere of radius RR. The electric potential of that sphere is
View answer and explanation
Correct option: A
14π∈0QR\frac{1}{{4\pi { \in _0}}}\frac{Q}{R}
Option A is correct because the potential of a conducting sphere is constant throughout and equal to the potential at its surface, which is due to the induced charge distribution.
82 Medium
82 of 245
Analyzing +4 | -1
Assertion:- If three capacitors of capacitances C1<C2<C3\mathrm{C}_1 < \mathrm{C}_2 < \mathrm{C}_3 are connected in series and parallel, then Cparallel >Cseries \mathrm{C}_{\text {parallel }} > \mathrm{C}_{\text {series }}.
Reason:- Cseries =C1+C2+C3\mathrm{C}_{\text {series }}=\mathrm{C}_1+\mathrm{C}_2+\mathrm{C}_3 and 1Cparallel =1C1+1C2+1C3\frac{1}{\mathrm{C}_{\text {parallel }}}=\frac{1}{\mathrm{C}_1}+\frac{1}{\mathrm{C}_2}+\frac{1}{\mathrm{C}_3}
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because the formulas for series and parallel combinations are stated incorrectly in the Reason.
83 Hard
83 of 245
Analyzing +4 | -1
Statement-1: If temperature is increased, the dielectric constant of a polar dielectric decreases whereas that of a non-polar dielectric does not change significantly.
Statement-2: The magniude of dipole moment of individual polar molecule decreases significantly with increase in temperature.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct. The dielectric constant of polar dielectrics decreases with increasing temperature, but Statement-2 is true because the dipole moment of individual polar molecules does not decrease significantly; rather, their alignment decreases due to thermal agitation.
84 Medium
84 of 245
Understanding +4 | -1
When air in a capacitor is replaced by a medium of dielectric constant K,K, the capacity
View answer and explanation
Correct option: B
Increases KK times
Option B (Increases KK times) is correct because the capacitance of a capacitor increases by a factor of K when a dielectric material with dielectric constant K is inserted between the plates.
85 Medium
85 of 245
Application +4 | -1
A parallel plate capacitor has circular plates of 0.08m radius and 1.0×10−3m1.0 \times {10^{ - 3}}m separation. If a P.D. of 100  volt100\;volt is applied, the charge will be
View answer and explanation
Correct option: B
1.8×10−8C1.8 \times {10^{ - 8}}C
Option B (1.8×10−8C1.8 \times {10^{ - 8}}C) is correct because it is the charge calculated using the capacitance and potential difference.
86 Medium
86 of 245
Remembering +4 | -1
Let VV be the electric potential at a given point. Then the electric field Ex{E_x} along xx-direction at that point is given by
View answer and explanation
Correct option: C
−dVdx- \frac{{dV}}{{dx}}
Option C (−dVdx- \frac{{dV}}{{dx}}) is correct because the electric field is the negative gradient of the electric potential.
87 Medium
87 of 245
Analyzing +4 | -1
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason
R.
Assertion A : Two metallic spheres are charged to the same potential. One of them is hollow and
another is solid, and both have the same radii. Solid sphere will have lower charge than the hollow one.
Reason R: Capacitance of metallic spheres depend on the radii of spheres.
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: B
A is false but R is true
Option B is correct because Assertion A is false (solid sphere will have the same charge as the hollow one for the same potential), but Reason R is true (capacitance depends on radii).
88 Medium
88 of 245
Remembering +4 | -1
The energy stored in the condenser is
View answer and explanation
Correct option: B
12QV\frac{1}{2}QV
Option B (12QV\frac{1}{2}QV) is correct because it represents the formula for the energy stored in a capacitor, derived from integrating the work done to charge the capacitor.
89 Medium
89 of 245
Understanding +4 | -1
The electric potential at a point on the axis of an electric dipole depends on the distance rr of the point from the dipole as
View answer and explanation
Correct option: B
∝1r2\propto \frac{1}{{{r^2}}}
Option B (∝1r2\propto \frac{1}{{{r^2}}}) is correct because the electric potential at a point on the axis of an electric dipole is inversely proportional to the square of the distance from the dipole.
90 Medium
90 of 245
Remembering +4 | -1
The condensers of capacity C1and  C2 {C_1}\mathrm{ and }\,\,{C_2}\, are connected in parallel, then the equivalent capacitance is:
View answer and explanation
Correct option: A
C1+C2{C_1} + {C_2}
Option A (C1+C2{C_1} + {C_2}) is correct because the equivalent capacitance of capacitors in parallel is the sum of their individual capacitances.
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