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NEET • PHYSICS • ELECTRIC POTENTIAL AND CAPACITANCE

Electric potential and capacitance practice · Mixed difficulty

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31 Medium
31 of 245
Understanding +4 | -1
Two capacitors connected in parallel having the capacities C1{C_1} and C2{C_2} are given ′q′'q' charge, which is distributed among them. The ratio of the charge on C1{C_1}  and C2{C_2} will be
View answer and explanation
Correct option: A
C1C2\frac{{{C_1}}}{{{C_2}}}
Option A (C1C2\frac{{{C_1}}}{{{C_2}}}) is correct because in parallel, the voltage is the same across both capacitors, and the charge is proportional to the capacitance.
32 Medium
32 of 245
Understanding +4 | -1
The outer sphere of a spherical air capacitor is earthed. For increasing its capacitance
View answer and explanation
Correct option: B
Dielectric material is filled between the two spheres
Option B (Dielectric material is filled between the two spheres) is correct because introducing a dielectric increases the capacitance of a capacitor.
33 Medium
33 of 245
Understanding +4 | -1
An air capacitor is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase
View answer and explanation
Correct option: D
The charge and the capacitance
Option D is correct. Filling the space with a dielectric increases the capacitance and, since the voltage is constant, it also increases the charge stored.
34 Medium
34 of 245
Analyzing +4 | -1
A parallel plate capacitor with dielectric is charged completely and then the battery is disconnected. Now the dielectric is pulled out. Due to such pulling the
View answer and explanation
Correct option: D
Energy stored in the capacitor will increase
Option D (Energy stored in the capacitor will increase) is correct because when the dielectric is pulled out after disconnecting the battery, the voltage increases, leading to an increase in stored energy.
35 Easy
35 of 245
Remembering +4 | -1
A powerful machine used for producing high positive potentials is
View answer and explanation
Correct option: D
Van de graaff generator.
Option D is correct because a Van de Graaff generator is specifically designed to produce high positive potentials.
36 Easy
36 of 245
Application +4 | -1
Two identical capacitors have same capacitance CC. One of them is charged to the potential VV and other to the potential 2V2 V. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is:
View answer and explanation
Correct option: A
14CV2\frac{1}{4} {CV}^2
Option A (14CV2\frac{1}{4} {CV}^2) is correct because it represents the decrease in energy after the capacitors are connected, calculated by finding the difference between the initial and final energies.
37 Easy
37 of 245
Remembering +4 | -1
If E1E_1 be the electric field strength of a short dipole at a point on its axial line and E2E_2 that on the equatorial line at the same distance, then
View answer and explanation
Correct option: D
E1=2E2E _1=2 E _2
Option D (E1=2E2E _1=2 E _2) is correct because the electric field strength on the axial line of a short dipole is twice that on the equatorial line at the same distance.
38 Easy
38 of 245
Application +4 | -1
The difference in the effective capacitance of two equal capacitors when joined in parallel and series is 3  μF.3\,\,\mu F. The value of each capacitor is
View answer and explanation
Correct option: B
2  μF2\,\,\mu F
Option B (2  μF2 \,\,\mu F) is correct because it satisfies the condition that the difference in effective capacitance in parallel and series is 3  μF3 \,\,\mu F.
39 Medium
39 of 245
Application +4 | -1
Three capacitors of capacitance 3  μ  F3\;\mu \;F are connected in a circuit. Then their maximum and minimum capacitance will be
View answer and explanation
Correct option: A
9  μ  F,  1  μ  F9\;\mu \;F,\;1\;\mu \;F
Option A (9  μ  F,  1  μ  F9 \;\mu \;F,\;1 \;\mu \;F) is correct because maximum capacitance is achieved in series and minimum in parallel.
40 Medium
40 of 245
Application +4 | -1
Two spherical conductors A and B of radii 1  mm1\;mm and 2 mmmm are separated by a distance of 5  cm5\;cm and are uniformly charged. If the spheres are connected by a conducting wire then in equilibrium condition, the ratio of the magnitude of the electric fields at the surfaces of spheres A and B is
View answer and explanation
Correct option: B
2:12:1
Option B (2:1) is correct because when the spheres are connected, they have the same potential, and the electric field at the surface is E = V/R, so the ratio of electric fields is inversely proportional to the ratio of radii.
41 Easy
41 of 245
Application +4 | -1
An electric dipole is made up of two equal and opposite charges of 2×10−6C2 \times 10^{-6} {C} at a distance of 3 cm3 {~cm}. If this is kept in an electric field of 2×1052 \times 10^5 N/C{N} / {C}, then the maximum torque acting on the dipole is
View answer and explanation
Correct option: A
0.012
Option A (0.012) is correct because the maximum torque is calculated using the formula τ=pEsin⁡θ\tau = pE \sin{\theta}, where p=qdp = qd and sin⁡θ=1\sin{\theta} = 1 for maximum torque.
42 Medium
42 of 245
Understanding +4 | -1
Statement I : The circuits containing capacitor be handed cautiously, even when there is no current.

Statement II : A dielectric differs from an insulator.
View answer and explanation
Correct option: B
Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I
Option B (Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I) is correct because both statements are true, but the dielectric property doesn't explain the cautious handling of capacitors.
43 Medium
43 of 245
Remembering +4 | -1
‘Debye’ is the unit of
View answer and explanation
Correct option: B
Electric dipolement
Option B (Electric dipolement) is correct because Debye is the unit of electric dipole moment.
44 Easy
44 of 245
Analyzing +4 | -1
Assertion (A) : When an uncharged capacitor is charged by a battery, only 50%50 \% of the energy supplied by a battery is stored in the capacitor.

Reason (R): Rest 50%50 \% is lost.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct. The assertion is true because half the energy is dissipated as heat in the connecting wires, and the reason is true because energy is indeed lost, but the reason doesn't explain why only 50% is stored.
45 Medium
45 of 245
Analyzing +4 | -1
Statement-1: Two concentric conducting spherical shells are charged. The charge on the outer shell is varied keeping the charge on inner shell constant, as a result the electric potential difference between the two shells does not change.
Statement-2: If charge is changed on an isolated thin conducting spherical shell, the potential at all points inside the shell changes by same amount.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because changing the outer shell's charge changes the potential by the same amount everywhere inside, including the inner shell, thus not affecting the potential difference.
46 Easy
46 of 245
Understanding +4 | -1
A spherical equipotential surface is not possible
View answer and explanation
Correct option: B
For a dipole
Option B (For a dipole) is correct because the equipotential surfaces for a dipole are complex and not spherical.
47 Easy
47 of 245
Analyzing +4 | -1
Assertion (A) : In series combination, charges on two capacitors are always equal.

Reason (R) : If charges are same, the total potential difference applied across two capacitors will be distributed in inverse ratio of capacities.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because while both statements are true, the reason doesn't directly explain why charges are equal in series.
48 Medium
48 of 245
Application +4 | -1
If 3 charges are placed at the vertices of equilateral triangle of charge ′q′'q' each. What is the net potential energy, if the side of equilateral Δ\Delta is l  cml\;cm
View answer and explanation
Correct option: C
14πε03q2l\frac{1}{{4\pi {\varepsilon _0}}}\frac{{3{q^2}}}{l}
Option C (14πε03q2l\frac{1}{{4\pi {\varepsilon _0}}}\frac{{3{q^2}}}{l}) is correct because the total potential energy is the sum of the potential energies of each pair of charges, and there are three such pairs.
49 Easy
49 of 245
Application +4 | -1
An electric charge 10−6μC10^{-6} \mu \mathrm{C} is placed at origin (0,0)(0,0) m of X-Y co-ordinate system. Two points PP and QQ are situated at (3,3)m(\sqrt{3}, \sqrt{3}) \mathrm{m} and (6,0)m(\sqrt{6}, 0) \mathrm{m} respectively. The potential difference between the points PP and QQ will be:
View answer and explanation
Correct option: B
0 V0 \mathrm{~V}
Option B (0 V) is correct because points P and Q are equidistant from the charge, hence they are at the same potential, resulting in zero potential difference.
50 Easy
50 of 245
Remembering +4 | -1
The electric potential of the earth is taken to be
View answer and explanation
Correct option: A
0
Option A (0) is correct because the Earth is taken as a reference point for electrical potential and is assigned a potential of zero.
51 Easy
51 of 245
Application +4 | -1
A point AA is at potential +500 Volt+500 \mathrm{~Volt} and BB is a point of potential −500 Volt.-500 \mathrm{~Volt}. The work done by an external agent to take a unit positive charge from AA to BB is
View answer and explanation
Correct option: B
−1000J-1000J
Option B (-1000J) is correct because the work done by an external agent to move a positive charge against the electric field is negative and equal to q(V_B - V_A).
52 Medium
52 of 245
Understanding +4 | -1
An electric dipole of moment p placed in a uniform electric field E has minimum potential energy when the angle between p and E is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the potential energy of a dipole in an electric field is minimum when the dipole moment is aligned with the electric field (angle is zero).
53 Hard
53 of 245
Application +4 | -1
A charge QQ is uniformly distributed through out the volume of a dielectric sphere of radius RR. If potential at its surface is 24 volts. Then potential at r=R2r=\frac{R}{2} and r=3R2r=\frac{3 R}{2} respectively are. (where rr distance from the centre of sphere) :-
View answer and explanation
Correct option: B
33 V,16 V33 \mathrm{~V}, 16 \mathrm{~V}
Option B (33 V, 16 V) is correct. Inside the sphere (r < R), V = (kQ/2R3)(3R2 - r2). Outside the sphere (r > R), V = kQ/r. Using these, we find the potentials at r = R/2 and r = 3R/2.
54 Easy
54 of 245
Application +4 | -1
Capacity of parallel plate capacitor in air and on immersing it into oil is 50 mF50 \,{mF} and 110 mF110 \,{mF} respectively. The dielectric constant of oil is
View answer and explanation
Correct option: D
2.2
Option D (2.2) is correct because the dielectric constant is the ratio of the capacitance with the dielectric to the capacitance in air.
55 Hard
55 of 245
Analyzing +4 | -1
Assertion (A): At a point electric potential is decreasing along xx-axis at a rate of 10 V/m10 \mathrm{~V} / \mathrm{m}. Therefore, xx-component of electric field at this point should be 10 V/m10 \mathrm{~V} / \mathrm{m} along xx-axis.

Reason (R) : Magnitude of Ex=∂V∂xE_x=\frac{\partial V}{\partial x}
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because the assertion is false (it should be negative of the rate), but the reason is true (Ex=−∂V∂xE_x = -\frac{\partial V}{\partial x}).
56 Medium
56 of 245
Understanding +4 | -1
Can a metal be used as a medium for dielectric
View answer and explanation
Correct option: B
No
Option B (No) is correct because metals are conductors, and a dielectric material must be an insulator.
57 Medium
57 of 245
Application +4 | -1
An electric dipole is placed making at an angle 60 ∘C60\,^\circ C with an electric field of strength 4×105  N/C4 \times {10^5}\,\,N/C. It experiences a torque equal to 83  N−m8\sqrt 3 \,\,N - m. Calculate the charge on the dipole, if it is of length 4 cm.
View answer and explanation
Correct option: B
10−3C{10^{ - 3}}C
Option B (10−3C{10^{ - 3}}C) is correct because the charge is calculated using the formula for torque τ=pEsin⁡θ=qdEsin⁡θ\tau = pE \sin \theta = qdE \sin \theta, where θ=60°\theta = 60°.
58 Hard
58 of 245
Analyzing +4 | -1
A parallel plate capacitor with plate area AA and distance of separation dd is filled with a dielectric. What is the capacity of the capacitor when permittivity of the dielectric varies as
ε (X)=ε0+  kx,\varepsilon \,(X) = {\varepsilon _0} + \,\,kx, for (0<x≤d2)\left( {0 < x \le \frac{d}{2}} \right)
ε (X)  =  ε0+k (d−x)\varepsilon \,(X)\,\, = \,\,{\varepsilon _0} + k\,(d - x) for (d2≤x≤d)\left( {\frac{d}{2} \le x \le d} \right)
View answer and explanation
Correct option: B
kA2ln⁡(2ε0+kd2ε0)\frac{{kA}}{{2\ln \left( {\frac{{2{\varepsilon _0} + kd}}{{2{\varepsilon _0}}}} \right)}}
kA2ln⁡(2ε0+kd2ε0)\frac{{kA}}{{2\ln \left( {\frac{{2{\varepsilon _0} + kd}}{{2{\varepsilon _0}}}} \right)}} is correct because it is derived by integrating the capacitance over the varying permittivity with respect to distance.
59 Medium
59 of 245
Application +4 | -1
A molecule with a dipole moment pp is placed in an electric field of strength E. Initially the dipole is aligned parallel to the field. If the dipole is to be related to be anti-parallel to the field the work required to be done by an external agency is
View answer and explanation
Correct option: D
2pE2pE
Option D (2pE2pE) is correct because the work required to rotate the dipole from parallel to anti-parallel is equal to the change in potential energy, which is 2pE2pE.
60 Easy
60 of 245
Analyzing +4 | -1
Two capacitances C1C_1 and C2C_2 are connected in series; assume that C1<C2C_1 < C_2. The equivalent capacitance of this arrangement is CC, where:
View answer and explanation
Correct option: B
C1/2<C<C1C_1 / 2 < C < C_1
Option B (C1/2<C<C1C_1 / 2 < C < C_1) is correct because the equivalent capacitance in series is always less than the smallest individual capacitance.
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