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NEET • CHEMISTRY • THERMODYNAMICS
Thermodynamics practice · Mixed difficulty
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61
Hard
61 of 560
Application
+4 | -1
The heat evolved on combustion of of starch, , into and is What is the standard enthalpy of formation of of starch? Heat of formation of and are and .
View answer and explanation
Correct option: C
Option C () is correct because it is calculated by using the heat of combustion of starch and the heats of formation of CO2 and H2O to find the standard enthalpy of formation of starch.
62
Medium
62 of 560
Application
+4 | -1
At 27℃ one mole of an ideal gas is compressed isothermally and reversible from a pressure of 2 atm to 10 atm. The value of ∆E and q are (R=2 cal)
View answer and explanation
Correct option: A
0, -965.84 cal
Option A (0, -965.84 cal) is correct because for an isothermal process, ∆E = 0, and q = -W. The work done is calculated using the formula for reversible isothermal compression.
63
Hard
63 of 560
Application
+4 | -1
An engine operating between 150℃ and 25℃ takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is
View answer and explanation
Correct option: D
147.7 J
Option D (147.7 J) is the correct work done by the engine, calculated using the Carnot efficiency formula.
64
Hard
64 of 560
Application
+4 | -1
Heat of formation of two moles of is . Bond energies of and bonds are and respectively. The value of the bond energy of will be
View answer and explanation
Correct option: D
Option D () is correct because it is calculated using the heat of formation and the given bond energies of H-H and N-H bonds, applying Hess's Law.
65
Medium
65 of 560
Analyzing
+4 | -1
At the same conditions of pressure, volume and
temperature, work done is maximum for which
gas if all gases have equal masses?
temperature, work done is maximum for which
gas if all gases have equal masses?
View answer and explanation
Correct option: A
Option A (NH3) is correct because, with equal masses, the gas with the smallest molar mass (NH3) will have the most moles, leading to maximum work done.
66
Easy
66 of 560
Understanding
+4 | -1
The standard heat of combustion of solid boron is :
View answer and explanation
Correct option: D
Option D () is correct because the standard heat of combustion of solid boron is related to the formation of B2O3, considering the stoichiometry of the reaction.
67
Medium
67 of 560
Understanding
+4 | -1
A gas expands isothermally and reversibly. The work done by the gas is:
View answer and explanation
Correct option: C
Maximum
Option C (Maximum) is correct because a reversible isothermal expansion allows the system to perform the maximum possible work as it maintains equilibrium throughout the process.
68
Easy
68 of 560
Understanding
+4 | -1
Which of the following factors do not affect heat capacity?
View answer and explanation
Correct option: D
Temperature of the system
Option D, Temperature of the system, is correct because heat capacity is an intrinsic property that depends on the size, composition, and nature of the system, but not the temperature.
69
Hard
69 of 560
Application
+4 | -1
If,...(i)...(ii)...(iii)...(iv)The enthalpy of formation of at 298 K will be:
View answer and explanation
Correct option: A
Option A (-754.4 kJ) is correct because it represents the sum of the enthalpy changes of the reactions that form H2SO4 from its elements.
70
Hard
70 of 560
Application
+4 | -1
The enthalpy of vapourisation of a certain liquid at its boiling point of is . The value of change in entropy for the process is
View answer and explanation
Correct option: B
Option B () is correct because it is the result of dividing the enthalpy of vaporization by the boiling point in Kelvin.
71
Easy
71 of 560
Application
+4 | -1
Workdone for the conversion of 0.5 mole of water at to steam at pressure is (heat of vaporisation of water at is )
View answer and explanation
Correct option: A
Option A () is correct because it is the work done calculated using during the phase change from water to steam.
72
Easy
72 of 560
Application
+4 | -1
For a reaction, ∆H=9.08 kJ and ∆S=35.7 J. Which of the following statement is correct for the reaction?
View answer and explanation
Correct option: C
Spontaneous and endothermic
Option C (Spontaneous and endothermic) is correct because ∆H is positive (endothermic) and ∆G is negative (spontaneous) at high temperatures, calculated using ∆G = ∆H - T∆S.
73
Hard
73 of 560
Understanding
+4 | -1
For an isothermal free expansion of an ideal gas correct option is:
View answer and explanation
Correct option: D
Option D () is correct because in an isothermal free expansion of an ideal gas, there is no heat exchange (q=0), no work done (w=0), and no change in enthalpy ().
74
Easy
74 of 560
Understanding
+4 | -1
The enthalpy of formation of ammonia gas at 298 K is - 46.11 kJ . The equation to which this value relates is:
View answer and explanation
Correct option: A
Option A () is correct because it represents the formation of one mole of ammonia from its elements in their standard states.
75
Hard
75 of 560
Understanding
+4 | -1
The temperature coefficient of e.m.f. of a cell can be given by:
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because all the given expressions are valid representations of the temperature coefficient of e.m.f. of a cell.
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76
Medium
76 of 560
Understanding
+4 | -1
is equal to
View answer and explanation
Correct option: C
Adiabatic work
Option C (Adiabatic work) is correct because in an adiabatic process, there is no heat exchange with the surroundings, so the change in internal energy is equal to the work done.
77
Medium
77 of 560
Understanding
+4 | -1
Vibrational energy is:
View answer and explanation
Correct option: A
Partially potential and partially kinetic
Option A (Partially potential and partially kinetic) is correct because vibrational energy involves both the movement of atoms (kinetic energy) and the restoring forces between them (potential energy).
78
Medium
78 of 560
Analyzing
+4 | -1
Consider the following reaction occurring in an automobile
the sign of and would be
the sign of and would be
View answer and explanation
Correct option: B
-,+,-
Option B (-,+,-) is correct because combustion reactions are exothermic (negative Δ H), increase disorder (positive Δ S), and are spontaneous (negative Δ G).
79
Hard
79 of 560
Analyzing
+4 | -1
Given,
.....(v)
Heat of formation of will be
.....(v)
Heat of formation of will be
View answer and explanation
Correct option: B
Option B is correct because the heat of formation of KCl can be calculated by manipulating the given equations using Hess's Law.
80
Hard
80 of 560
Application
+4 | -1
A process has and . Out of the values given below, choose the minimum temperature above which the process will be spontaneous
View answer and explanation
Correct option: C
5 K
Option C (5 K) is correct because it represents the minimum temperature above which the process becomes spontaneous, calculated using the Gibbs free energy equation.
81
Medium
81 of 560
Application
+4 | -1
The standard entropies of and are . The value of formation of ammonia is
View answer and explanation
Correct option: A
Option A (-98.9 J K⁻¹ mol⁻¹) is correct because it is calculated using the standard entropies of the reactants and products for the formation of ammonia.
82
Easy
82 of 560
Remembering
+4 | -1
Which reaction is endothermic in nature?
View answer and explanation
Correct option: A
Option A () is correct because decomposition reactions generally require energy input to break bonds, making them endothermic.
83
Medium
83 of 560
Application
+4 | -1
For an adiabatic expansion of a perfect gas ∆P/P is equal to:
View answer and explanation
Correct option: C
Option C () is correct because for an adiabatic process, is constant, and differentiating this gives the relationship between changes in pressure and volume.
84
Medium
84 of 560
Understanding
+4 | -1
The volume of gas is reduced to half from its original volume. The specific heat will be
View answer and explanation
Correct option: C
Remain constant
Option C (Remain constant) is correct because specific heat is an intensive property and does not depend on the amount of substance.
85
Easy
85 of 560
Application
+4 | -1
for is at The for the reaction is equal to
View answer and explanation
Correct option: B
The for the reaction is 165.6 kJ, calculated using the formula .
86
Medium
86 of 560
Application
+4 | -1
Assuming that water vapours are ideal gas. The change in internal energy (∆U) when 1 mol of water is vaporized at 1 bar pressure and 100C. (Given molar enthalpy of vaporization at 1 bar and 373 K is 41 kJ and R=8.3 J ) will be:
View answer and explanation
Correct option: D
Option D () is correct because it is calculated by subtracting the work done during vaporization from the molar enthalpy of vaporization.
87
Medium
87 of 560
Application
+4 | -1
∆H for is 176 kJ at 1240 K. The ∆U for the change is equal to:
View answer and explanation
Correct option: B
165.6 kJ
The for the change is 165.6 kJ, calculated using the formula .
88
Medium
88 of 560
Understanding
+4 | -1
Choose intensive properties in the following:
(i) density (ii) specific volume (iii) Heat capacity
(iv) mole (v) concentration (vi) volume
(i) density (ii) specific volume (iii) Heat capacity
(iv) mole (v) concentration (vi) volume
View answer and explanation
Correct option: C
i, ii, v
Option C (i, ii, v) is correct because density, specific volume, and concentration are intensive properties, independent of the amount of substance.
89
Hard
89 of 560
Application
+4 | -1
In an isobaric process, the ratio of heat supplied to the system (dθ) and work done by the system (dW) for diatomic gas is
View answer and explanation
Correct option: B
Option B () is correct because for a diatomic gas in an isobaric process, the ratio of heat supplied to work done is 7/2.
90
Medium
90 of 560
Analyzing
+4 | -1
Assertion : Many endothermic reactions that are not spontaneous at room temperature become spontaneous at high temperature.
Reason : Entropy of the system increases with increase in temperature.
Reason : Entropy of the system increases with increase in temperature.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B is correct because both the assertion and reason are correct, but the reason doesn't fully explain the assertion. The spontaneity is determined by , and at high temperatures, the term becomes dominant.
Revision notes and key takeaways
Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.
Showing 61-90 of 560 questions
