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NEET • CHEMISTRY • THERMODYNAMICS
Thermodynamics practice · Mixed difficulty
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301
Easy
301 of 560
Understanding
+4 | -1
Which is not a spontaneous process?
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Correct option: C
Heat flowing from colder body to a hotter body
Option C (Heat flowing from colder body to a hotter body) is correct because heat naturally flows from a hotter body to a colder body, not the other way around. This violates the second law of thermodynamics.
302
Easy
302 of 560
Understanding
+4 | -1
For the precipitation of AgCl by ions and HCl:
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Correct option: C
∆G=-ve
Option C (∆G=-ve) is correct because the precipitation of AgCl is a spontaneous process under normal conditions, and spontaneous processes have a negative change in Gibbs free energy.
303
Hard
303 of 560
Application
+4 | -1
When of manganese (At. mass ) dissolves in dilute at under atmospheric pressure, the work done in the process is :
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Correct option: C
Option C () is correct because the work done is negative, indicating expansion against atmospheric pressure, and is calculated using .
304
Easy
304 of 560
Remembering
+4 | -1
Calorie is equivalent to:
View answer and explanation
Correct option: B
4.184 Joule
Option B (4.184 Joule) is correct because 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of water by 1 degree Celsius, which is equivalent to 4.184 Joules.
305
Easy
305 of 560
Understanding
+4 | -1
The value of for an open and isolated system respectively is
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Correct option: C
Non-zero; zero
Option C (Non-zero; zero) is correct because an open system can exchange both energy and matter with the surroundings, so its internal energy can change, while an isolated system cannot exchange either, so its internal energy remains constant.
306
Hard
306 of 560
Understanding
+4 | -1
Consider the following reactions:
Enthalpy of formation of is
Enthalpy of formation of is
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Correct option: D
Option D () is correct because reaction (ii) directly represents the formation of one mole of H2O(l) from its elements in their standard states.
307
Easy
307 of 560
Application
+4 | -1
If kcal then the heat of neutralization for complete neutralization of one mole of by a base will be :
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Correct option: B
Option B (-27.4 kcal) is correct because the heat of neutralization for a strong acid and strong base is additive, and sulfuric acid has two acidic protons.
308
Medium
308 of 560
Understanding
+4 | -1
Heat of neutralisation of which acid-base reaction is - 57.32 kJ for?
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Correct option: D
Option D () is correct because it represents the neutralization of a strong acid () with a strong base (), which results in a heat of neutralization of -57.32 kJ.
309
Hard
309 of 560
Understanding
+4 | -1
The correct relation between electron gain enthalpy and electron affinity is
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Correct option: C
Option C () is correct because it represents the relationship between electron gain enthalpy and electron affinity, considering the conversion from electron affinity to enthalpy change.
310
Medium
310 of 560
Analyzing
+4 | -1
Given that
the enthalpy of formation of carbon monoxide will be
the enthalpy of formation of carbon monoxide will be
View answer and explanation
Correct option: B
Option B () is correct because it is derived from Hess's Law by manipulating the given equations to obtain the formation equation for CO.
311
Easy
311 of 560
Understanding
+4 | -1
All the naturally occurring processes, i.e., spontaneous proceed spontaneously in a direction which leads to:
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Correct option: A
Decrease of free energy
Option A (Decrease of free energy) is correct because spontaneous processes always proceed in a direction that lowers the Gibbs free energy of the system.
312
Medium
312 of 560
Understanding
+4 | -1
Absorption of gasses on solid surface is generally exothermic because
View answer and explanation
Correct option: B
Entropy decreases
Option B (Entropy decreases) is correct because when gases are adsorbed onto a solid surface, their freedom of movement is restricted, leading to a decrease in entropy.
313
Medium
313 of 560
Understanding
+4 | -1
The work done during the process when 1 mole of gas is allowed to expand freely into vacuum is:
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Correct option: A
Zero
Option A (Zero) is correct because when a gas expands freely into a vacuum, the external pressure is zero, resulting in no work being done.
314
Medium
314 of 560
Remembering
+4 | -1
Which one among the following is the correct expression for isothermal reversible change?
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Correct option: B
Option B is correct because the correct expression for isothermal reversible work is w = -2.303nRTlog(Vf/Vi).
315
Medium
315 of 560
Analyzing
+4 | -1
will be highest for the reaction:
View answer and explanation
Correct option: B
Option B () is correct because it involves the decomposition of a solid into a solid and a gas, leading to a significant increase in entropy.
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316
Medium
316 of 560
Remembering
+4 | -1
Entropy change of fusion at constant pressure is given by:
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Correct option: A
Option A () is correct because the entropy change of fusion at constant pressure is defined as the enthalpy of fusion divided by the temperature at the melting point.
317
Medium
317 of 560
Remembering
+4 | -1
The enthalpy change accompanying a reaction
is called
is called
View answer and explanation
Correct option: A
reaction enthalpy
Option A (reaction enthalpy) is correct because the enthalpy change accompanying a reaction is specifically termed the reaction enthalpy.
318
Medium
318 of 560
Application
+4 | -1
The enthalpy and entropy change for the reaction,Are 30 kJandrespectively. The temperature at which the reaction will be in equilibrium is:
View answer and explanation
Correct option: C
285.7 K
Option C (285.7 K) is correct because the equilibrium temperature is calculated using T = ∆H/∆S.
319
Hard
319 of 560
Application
+4 | -1
An ideal gas undergoes isothermal compression from to against a constant external pressure of . Heat released in this process is used to increase the temperature of 1 mole of . If molar heat capacity of is , the temperature of increases by
View answer and explanation
Correct option: D
Option D (2/3 K) is correct because the heat released during isothermal compression is used to increase the temperature of Aluminum, and the temperature increase is calculated using the formula q = nCΔT.
320
Medium
320 of 560
Application
+4 | -1
The value of for freezing of 10g of (enthalpy of fusion is 80 cal/g) at and 1 atm pressure is:
View answer and explanation
Correct option: D
-12.25 J/K
Option D (-12.25 J/K) is correct because the change in entropy during freezing is calculated using the formula , where Q is the heat released during freezing and T is the temperature in Kelvin.
321
Hard
321 of 560
Application
+4 | -1
To raise the temperature of 1 mole gas from to , how much heat is require while
View answer and explanation
Correct option: B
Option B (354 cal) is correct because it is calculated by integrating the given Cp function over the temperature range.
322
Easy
322 of 560
Understanding
+4 | -1
At constant pressure and temperature, the direction of any chemical reaction is one where, the … decrease.
View answer and explanation
Correct option: C
Gibbs energy
Option C (Gibbs energy) is correct because at constant pressure and temperature, the direction of a spontaneous chemical reaction is towards a decrease in Gibbs free energy.
323
Hard
323 of 560
Application
+4 | -1
g sample of is decomposed in a Bomb calorimeter. The temperature of calorimeter increase by . The heat capacity of the system is . The value of is
(Given molar heat of decomposition of at constant volume is )
(Given molar heat of decomposition of at constant volume is )
View answer and explanation
Correct option: A
1
Option A (1) is correct because it represents the mass of NH4NO3 required to produce the given temperature change in the calorimeter, calculated using the heat capacity and molar heat of decomposition.
324
Easy
324 of 560
Application
+4 | -1
Heat of formation of and are -26.4, -94.0 Kcal/mole respectively. What is the heat of combustion of CO in K cals?
View answer and explanation
Correct option: C
Option C () is correct because the heat of combustion of CO is calculated using the heats of formation of CO and CO2 and applying Hess's Law.
325
Medium
325 of 560
Application
+4 | -1
The heat of neutralisation of a strong acid and a strong alkali is 57.0 kJ . The heat released when 0.5 mole of solution is mixed with 0.2 mole of KOH is
View answer and explanation
Correct option: B
11.4 kJ
Option B (11.4 kJ) is correct because the heat released is determined by the limiting reactant (KOH) and the heat of neutralization.
326
Easy
326 of 560
Application
+4 | -1
The work done in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 litres to 20 litres at is
View answer and explanation
Correct option: B
Option B () is correct because it represents the work done for a reversible expansion, calculated using the formula with R in ergs.
327
Easy
327 of 560
Understanding
+4 | -1
Standard state Gibbs free energy changes for the isomerization reaction,cis-2-pentene⇌trans-2-pentene is -3.67 kJ/mol at 400K. If more trans-2-pentene is added to the reaction vessel, then:
View answer and explanation
Correct option: C
More cis-2-pentene is formed
Option C (More cis-2-pentene is formed) is correct because adding more trans-2-pentene will shift the equilibrium towards the reactants (cis-2-pentene) to counteract the change, according to Le Chatelier's principle.
328
Easy
328 of 560
Application
+4 | -1
What is the melting point of benzene if and ?
View answer and explanation
Correct option: B
Option B () is correct because the melting point is calculated using the formula .
329
Medium
329 of 560
Understanding
+4 | -1
In an irreversible process taking place at constant T and P and in which only pressure volume work is being done, the change in Gibbs free energy (dG) and change in entropy
View answer and explanation
Correct option: B
Option B () is correct because, in an irreversible process at constant T and P, entropy increases and Gibbs free energy decreases.
330
Hard
330 of 560
Application
+4 | -1
When 500 J heat is given to the gas X in an isobaric process its work done comes out as 142.8 J. The gas X is
View answer and explanation
Correct option: B
Option B (NH3) is correct because the calculated value of Cp/Cv is closest to that of NH3.
Revision notes and key takeaways
Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.
Showing 301-330 of 560 questions
