Which of the following will be the most effective in the coagulation of ${\rm{Fe}}{\left( {{\rm{OH}}} \right)_3}$ sol?

${\rm{M}}{{\rm{g}}_3}{\left( {{\rm{P}}{{\rm{O}}_4}} \right)_2}$

Back to SURFACE CHEMISTRY

Your Progress

0 / 139 Answered

Correct

Incorrect

Accuracy

NEET • CHEMISTRY • SURFACE CHEMISTRY

Surface chemistry practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →

Showing 121-139 of 139 questions

Preparing practice and saved progress…

121 Medium

121 of 139

Understanding +4 | -1

x

is amount of adsorbate and

m

is amount of adsorbent, which of the following relations is related to adsorption process?

View answer and explanation

Correct option: A

\frac{x}{m} = P \times T

Option B (

\frac{x}{m} = f\left( P \right)

at constant T) is correct because it represents the relationship between the amount of adsorbate adsorbed per unit mass of adsorbent as a function of pressure at a constant temperature, which is the basis of adsorption isotherms.

122 Easy

122 of 139

Remembering +4 | -1

Which adsorption takes place at low temperature?

View answer and explanation

Correct option: A

Physical

Option A is correct because physical adsorption (physisorption) is favored at low temperatures due to weak van der Waals forces.

123 Easy

123 of 139

Application +4 | -1

Which of the following is the most effective in the coagulation of gold sol?

View answer and explanation

Correct option: B

\mathrm{MgC}{\mathrm{l}_2}

Option B (

\mathrm{MgC}{\mathrm{l}_2}

) is correct because gold sol is negatively charged, and according to the Hardy-Schulze rule, the cation with the highest charge will be most effective for coagulation.

Mg^{2+}

has a higher charge than

Na^+

124 Easy

124 of 139

Remembering +4 | -1

Which of the following statements is correct about Langmuir’s adsorption isotherm?

View answer and explanation

Correct option: A

It forms monolayer

Option A (It forms monolayer) is correct because Langmuir's adsorption isotherm assumes the formation of a monolayer of adsorbate on the adsorbent surface.

125 Medium

125 of 139

Remembering +4 | -1

The heat evolved in physisorption lies in the range (kJ/mol) of

View answer and explanation

Correct option: A

20-40

Option A (20-40) is correct because the heat evolved in physisorption is generally in the range of 20-40 kJ/mol due to weak van der Waals forces.

126 Medium

126 of 139

Understanding +4 | -1

The coagulating power of ions for haemoglobin decreases in the order

View answer and explanation

Correct option: B

PO_4^{3 - } > SO_4^{2 - } > C{l^ - }

Option D (

PO_4^{3 - } > SO_4^{2 - } > C{l^ - }

) is correct because the coagulating power increases with the charge of the ion, according to the Hardy-Schulze rule.

127 Easy

127 of 139

Analyzing +4 | -1

Flocculation value of

\mathrm{BaCl}_2

is much less than that of

\mathrm{KCl}

for sol

\mathrm{A}

and flocculation value of

\mathrm{Na}_2 \mathrm{SO}_4

is much less than that of

\mathrm{NaBr}

for sol

\mathrm{B}

. The correct statement among the following is

View answer and explanation

Correct option: B

Sol A is positively charged and Sol B is negatively charged.

Option B is correct because the flocculation value is inversely proportional to the charge on the sol. Lower flocculation value implies higher charge, hence A is positive and B is negative.

128 Easy

128 of 139

Remembering +4 | -1

In physical adsorption gas molecules are bound on the solid surface by

View answer and explanation

Correct option: D

Van der Waals’ forces

Option D (Van der Waals’ forces) is correct because physical adsorption involves weak intermolecular forces, specifically Van der Waals forces, between the gas molecules and the solid surface.

129 Hard

129 of 139

Application +4 | -1

One gram of activated carbon has a surface area of

1000 \mathrm{~m}^2

. Considering complete coverage as well as monomolecular adsorption, how much ammonia at

1 \mathrm{~atm}

and

273 \mathrm{~K}

would be adsorbed on the surface of

\frac{44}{7} \mathrm{~g}

carbon if radius of a ammonia molecules is

10^{-8} \mathrm{~cm}

View answer and explanation

Correct option: A

7.46

Option A (7.46) is correct because it is the calculated amount of ammonia adsorbed based on the given surface area and molecular radius.

130 Medium

130 of 139

Application +4 | -1

The graph of

\log \frac{x}{m}

\log p

for an adsorption process is a straight line inclined at an angle of

45^{\circ}

with intercept equal to 0.6020 . The mass of gas adsorbed per unit mass of adsorbent at the pressure of _____

0.4 \mathrm{~atm}

\times 10^{-1}

(Nearest integer).

Given :

\log 2=0.3010

View answer and explanation

Correct option: A

Option A (16) is correct because the mass of gas adsorbed per unit mass of adsorbent is calculated using the Freundlich isotherm, resulting in 1.6, which is 16 × 10^-1.

131 Easy

131 of 139

Analyzing +4 | -1

Select wrong statement.

View answer and explanation

Correct option: A

If a very small amount of

\mathrm{AlC}{\mathrm{l}_3}

is added to gold sol, coagulation occurs, but if a large quantity of

\mathrm{AlC}{\mathrm{l}_3}

is added, there is no coagulation.

Option A is the wrong statement because adding a large quantity of electrolyte to a sol can lead to peptization, not necessarily preventing coagulation.

132 Medium

132 of 139

Remembering +4 | -1

Which of the following is an example of associated colloid

View answer and explanation

Correct option: A

Soap in water

Option A (Soap in water) is correct because soap molecules in water aggregate to form micelles, which are characteristic of associated colloids.

133 Easy

133 of 139

Application +4 | -1

Which of the following will be the most effective in the coagulation of

\mathrm{Fe}{\left( {\mathrm{OH}} \right)_3}

sol?

View answer and explanation

Correct option: D

\mathrm{M}{\mathrm{g}_3}{\left( {\mathrm{P}{\mathrm{O}_4}} \right)_2}

Option D (

\mathrm{M}{\mathrm{g}_3}{\left( {\mathrm{P}{\mathrm{O}_4}} \right)_2}

) is correct because, according to the Hardy-Schulze rule, the ion with the highest charge will have the maximum coagulation power. Since

\mathrm{Fe}{\left( {\mathrm{OH}} \right)_3}

is a positive sol, we need to look for the anion with the highest charge, which is

PO_4^{3-}

134 Easy

134 of 139

Remembering +4 | -1

The process which is catalysed by one of the products formed during the reaction is known as :

View answer and explanation

Correct option: A

Autocatalysis

The correct answer is A (Autocatalysis) because autocatalysis is when a product of the reaction acts as a catalyst.

135 Easy

135 of 139

Remembering +4 | -1

The enzyme which converts starch to maltose is

View answer and explanation

Correct option: A

Diastase

Option A is correct because diastase is the enzyme that specifically catalyzes the hydrolysis of starch into maltose.

Explore Other Chapters in CHEMISTRY

View All →

CHEMICAL BONDING & MOLECULAR STRUCTURE 595 MCQs THERMODYNAMICS 583 MCQs STRUCTURE OF ATOM 499 MCQs CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 429 MCQs Equilibrium 412 MCQs STATES OF MATTER 410 MCQs

136 Medium

136 of 139

Understanding +4 | -1

Mention the type of reaction to obtain

\mathrm{Au}\left( {\mathrm{sol}} \right)

.
Reaction,

2\mathrm{AuC}{\mathrm{l}_3} + 3\mathrm{HCHO} + 3{\mathrm{H}_2}\mathrm{O} \to 2\mathrm{Au}\left( {\mathrm{sol}} \right) + 3\mathrm{HCOOH} + 6\mathrm{HCl}

View answer and explanation

Correct option: C

Reduction

Option C (Reduction) is correct because the gold ions (

\mathrm{AuC}{\mathrm{l}_3}

) are reduced to gold atoms (

\mathrm{Au}

) in the reaction.

137 Easy

137 of 139

Remembering +4 | -1

The critical micelle concentration (CMC) is

View answer and explanation

Correct option: A

The concentration at which micellisation starts

Option A (The concentration at which micellisation starts) is correct because CMC is defined as the minimum concentration at which micelles begin to form.

138 Easy

138 of 139

Understanding +4 | -1

Which is not correct for catalyst? It :

View answer and explanation

Correct option: B

Changes enthalpy of reaction

Option B (Changes enthalpy of reaction) is correct because a catalyst does not change the enthalpy of the reaction; it only affects the rate.

139 Medium

139 of 139

Analyzing +4 | -1

Assertion : In chemisorption, adsorption first increases with temperature and then decreases.

Reason : Heat keeps on providing more and more activation energy.

View answer and explanation

Correct option: C

If Assertion is correct but Reason is incorrect.

The correct answer is 'If Assertion is correct but Reason is incorrect' because chemisorption initially increases with temperature, but the reason is incorrect as heat eventually decreases adsorption.

Revision notes and key takeaways

Review SURFACE CHEMISTRY in your textbook or class notes, then use this set to check your understanding.

Showing 121-139 of 139 questions

Your Progress

Surface chemistry practice · Mixed difficulty

Explore Other Chapters in CHEMISTRY

Continue Your Practice

Your practice