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NEET • CHEMISTRY • SOLUTIONS

Solutions practice · Medium

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Showing 61-90 of 90 questions
61 Medium
61 of 90
Analyzing +4 | -1
Assertion (A): Azeotropic mixtures are formed only by non-ideal solutions.

Reason (R): The composition of the vapour phase is same as that of the liquid phase of an azeotropic mixture.
View answer and explanation
Correct option: B
Both A & R are true, R is not correct explanation of A
Option B (Both A & R are true, R is not correct explanation of A) is correct because azeotropic mixtures are indeed formed by non-ideal solutions, and the vapor phase composition is the same as the liquid phase, but the latter doesn't explain the former.
62 Medium
62 of 90
Analyzing +4 | -1
Statement I: Molarity of a solution is always greater than that of molality.

Statement II: Ratio of molarity and molality depends on density of solvent.
View answer and explanation
Correct option: D
If Statement I is false but Statement II is correct
Option D is correct because Statement I is false (molarity is not always greater than molality) and Statement II is correct (the ratio of molarity and molality depends on the density of the solvent).
63 Medium
63 of 90
Remembering +4 | -1
Relation between partial pressure and mole fraction is stated by
View answer and explanation
Correct option: B
Raoult's law
Option B (Raoult's law) is correct because it relates partial pressure and mole fraction in ideal solutions.
64 Medium
64 of 90
Remembering +4 | -1
A solution which boils at constant temperature is called:
View answer and explanation
Correct option: A
Azeotrope
A solution that boils at a constant temperature is called an azeotrope, making option A the correct answer. Azeotropes are mixtures with a fixed boiling point.
65 Medium
65 of 90
Understanding +4 | -1
One component of a solution follows Raoult’s law over the entire range 0≤x1≤10 \le {x_1} \le 1 . The second component must follow Raoult’s law in the range when x2{x_2} is
View answer and explanation
Correct option: D
0≤x2≤10 \le {x_2} \le 1
Option D (0≤x2≤10 \le {x_2} \le 1) is correct because if one component follows Raoult's law over the entire range, the other component must also follow Raoult's law over the entire range for the solution to be ideal.
66 Medium
66 of 90
Analyzing +4 | -1
Total vapour pressure of mixture of 1 mol of volatile
Component A (PAo=100  mm Hg)\left( {P_A^\mathrm{o} = 100\,\,mm\,Hg} \right) and 3 mol of volatile
Component B (PBo=80  mm Hg)\left( {P_B^\mathrm{o} = 80\,\,mm\,Hg} \right) is 90 mm Hg, for such case:
View answer and explanation
Correct option: D
All the above statements are correct
Option D (All the above statements are correct) is correct because the total vapor pressure is less than expected from Raoult's law, indicating negative deviation, which lowers the boiling point and implies weaker A-B interactions.
67 Medium
67 of 90
Analyzing +4 | -1
Assertion: The molarity of a solution depends on the temperature of the solvent.

Reason: Molarity is defined as the number of moles of solute per litre of solution, and the volume of the solvent changes with temperature.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option B is correct because both the assertion and reason are true, but the reason explains the effect of temperature on volume, not the fundamental definition of molarity.
68 Medium
68 of 90
Understanding +4 | -1
The van’t Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is
View answer and explanation
Correct option: A
3
Option A is correct because barium hydroxide, being a strong electrolyte, dissociates into three ions in solution.
69 Medium
69 of 90
Analyzing +4 | -1
Henry’s constant (in kbar) for four gases α\alpha, β\beta, γ\gamma and δ\delta in water at 298 K is given below:
αβγδKH5022×10−50.5\begin{array}{cccccccccccccccccccc} {}&\alpha &\beta &\gamma &\delta \\ {{K_H}}&{50}&2&{2 \times {{10}^{ - 5}}}&{0.5} \end{array}
(density of water =103 kg m−3= {10^3}\,kg\,{m^{ - 3}} at 298 K)
This implies that
View answer and explanation
Correct option: D
The pressure of a 55.5 molal solution of δ\delta is 250 bar
Option D is correct because according to Henry's law, the partial pressure of a gas is proportional to its mole fraction in the solution. Using the given Henry's constant for δ and the molality, we can calculate the pressure, which is approximately 250 kbar.
70 Medium
70 of 90
Understanding +4 | -1
The degree of dissociation '∝\propto' of a weak electrolyte is
View answer and explanation
Correct option: A
i−1n−1\frac{{i - 1}}{{n - 1}}
Option A is correct because the degree of dissociation is related to the van't Hoff factor and the number of ions produced.
71 Medium
71 of 90
Remembering +4 | -1
Molal depression constant is given by the expression:
View answer and explanation
Correct option: D
ΔTfm\frac{{\Delta {T_f}}}{m}
Option D is correct because the molal depression constant (KfK_f) is calculated by dividing the freezing point depression (ΔTf\Delta T_f) by the molality (m).
72 Medium
72 of 90
Understanding +4 | -1
The condition for the validity of Henry’s law are :
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because all the listed conditions are necessary for Henry's law to be valid.
73 Medium
73 of 90
Application +4 | -1
Vapour pressure of dilute aqueous solution of glucose is 750  mm750\;mm of mercury at 373  K373\;K. The mole fraction of solute is
View answer and explanation
Correct option: A
176\frac{1}{{76}}
Option A (176\frac{1}{{76}}) is correct because it is calculated using Raoult's Law and the definition of mole fraction.
74 Medium
74 of 90
Understanding +4 | -1
On mixing 10 mL10\,mL of carbon tetrachloride with 10 mL10\,mL of benzene the total volume of the solution is:
View answer and explanation
Correct option: C
= 20 mL
Option C (= 20 mL) is correct because when mixing carbon tetrachloride and benzene, which are non-polar liquids, the solution formed is nearly ideal, resulting in no significant volume change.
75 Medium
75 of 90
Remembering +4 | -1
Two solutions of different osmotic pressure. The solution of lower osmotic pressure is called
View answer and explanation
Correct option: C
Hypotonic
Option C (Hypotonic) is correct because a hypotonic solution has a lower osmotic pressure compared to another solution.
76 Medium
76 of 90
Analyzing +4 | -1
Assertion (A): Van't Hoff factor for benzoic acid in aqueous medium is 2 assuming complete ionisation.

Reason (R): Van't Hoff factor for 100%100 \% ionised solute equal to the number of ions produced.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option D is correct because the assertion is false as benzoic acid associates in aqueous medium, not ionizes, and the reason is true.
77 Medium
77 of 90
Application +4 | -1
18g glucose (C6H22O6)\left( {{C_6}{H_{22}}{O_6}} \right) is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is.
View answer and explanation
Correct option: B
752.4752.4
Option B (752.4) is correct because it is calculated using Raoult's Law, which relates vapor pressure lowering to the mole fraction of the solute.
78 Medium
78 of 90
Understanding +4 | -1
Which one of the following electrolyte has the same value of the vant Hoff factor (i) as that of A2(SO4)3{A_2}{\left( {S{O_4}} \right)_3} (if all are 100% ionised)
View answer and explanation
Correct option: D
K4[Fe(CN)6]{K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]
Option D is correct because both A2(SO4)3{A_2}{\left( {S{O_4}} \right)_3} and K4[Fe(CN)6]{K_4}{\left[ {Fe{{\left( {CN} \right)}_6}} \right]} dissociate into 5 ions.
79 Medium
79 of 90
Remembering +4 | -1
Which is correct representation of phase rule?
View answer and explanation
Correct option: B
F+P=C+2F + P = C + 2
Option B (F+P=C+2F + P = C + 2) is correct because it represents the Gibbs phase rule, where F is the degrees of freedom, P is the number of phases, and C is the number of components.
80 Medium
80 of 90
Analyzing +4 | -1
Which of the given solutions has highest osmotic pressure?
View answer and explanation
Correct option: A
1  N  NaNO31\;N\;\mathrm{NaN}{\mathrm{O}_3}
Option A (1  N  NaNO31\;N\;\mathrm{NaN}{\mathrm{O}_3}) is correct because, at the same normality, it has the lowest van't Hoff factor compared to the other options, which have higher numbers of ions upon dissociation.
81 Medium
81 of 90
Understanding +4 | -1
What happen at increasing pressure at constant temperature
View answer and explanation
Correct option: B
Solubility of gas increase in liquid
Option B (Solubility of gas increase in liquid) is correct because, according to Henry's Law, the solubility of a gas in a liquid increases with increasing pressure at constant temperature.
82 Medium
82 of 90
Application +4 | -1
If 0.2 m aqueous solution of K4[Fe(CN)6]{K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right] is 100% ionized then the freezing point of the solution will be (Kf=1.86 K kg mol−1)\left( {{K_f} = 1.86\,K\,kg\,mo{l^{ - 1}}} \right)
View answer and explanation
Correct option: B
−1.860C- {1.86^0}C
Option A is incorrect. The correct answer is -1.86, which is not listed. The freezing point depression is calculated using the van't Hoff factor and the molality.
83 Medium
83 of 90
Understanding +4 | -1
The melting point of most of the solid substances increase with an increase of pressure acting on them. However, ice melts at a temperature lower than its usual melting point, when the pressure increase. This is because :
View answer and explanation
Correct option: A
Ice is less denser than water
Option A (Ice is less denser than water) is correct because the increased pressure favors the liquid phase (water) which is denser, causing ice to melt at a lower temperature.
84 Medium
84 of 90
Remembering +4 | -1
The van't Hoff factor (i) for a dilute aqueous solution of glucose is:
View answer and explanation
Correct option: B
1
Glucose is a non-electrolyte and does not dissociate in solution; therefore, its van't Hoff factor is 1, making option B the correct answer.
85 Medium
85 of 90
Understanding +4 | -1
Assertion (A): Molality is independent of temperature.

Reason (R): There is no volume factor in the expression of molality.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option A (Both A & R are true, R is the correct explanation of A) is correct because molality is defined as moles of solute per kilogram of solvent, which is mass-based and therefore independent of temperature.
86 Medium
86 of 90
Analyzing +4 | -1
A liquid freezes at 7∘C7^{\circ} \mathrm{C} and boils at 77∘C.77^{\circ} \mathrm{C}. If the KfK_{\mathrm{f}} and KbK_{\mathrm{b}} values for the liquid are 5.65.6 and 2.5 deg/molal,2.5 \, \mathrm{deg} / \mathrm{molal}, respectively, then the ratio of molar latent heat of fusion to molar latent heat of vaporization is
View answer and explanation
Correct option: C
2:72: 7
Option C (2:7) is correct because the ratio of molar latent heat of fusion to vaporization is directly proportional to the ratio of freezing point depression constant to boiling point elevation constant, considering the temperature difference.
87 Medium
87 of 90
Analyzing +4 | -1
An open beaker of water in equilibrium with water vapour is in a sealed container. When few grams of glucose are added to the beaker of water, the rate at which water molecules
View answer and explanation
Correct option: C
leaves the vapour increases
Option C (leaves the vapour increases) is correct because adding glucose lowers the water potential of the solution, reducing the rate of evaporation and increasing condensation.
88 Medium
88 of 90
Understanding +4 | -1
Statement I : Mole fraction is the ratio of moles of a substance to the total moles in the solution.

Statement II : Mole fraction does not depend on temperature of solution.

In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: C
Both statement I and statement II are true
Option C (Both statement I and statement II are true) is correct because mole fraction is the ratio of moles of a substance to the total moles in the solution and is independent of temperature.
89 Medium
89 of 90
Analyzing +4 | -1
An acid 'AA' is 0.4 N0.4 \mathrm{~N}. In a neutralization process 50 ml50 \mathrm{~ml} of 'AA' is mixed with 30 ml30 \mathrm{~ml} of sodium carbonate solution (42.49/litre) and 10 mL10 \mathrm{~mL} of the resulting solution is diluted to 50 mL50 \mathrm{~mL} and then 5 mL5 \mathrm{~mL} of this solution (B)(B) is completely neutralised with certain volume of 40 times diluted solution of (A)(A). find the volume of diluted solution. of (A)(A) required for the neutralization of BB (in mL\mathrm{mL})
View answer and explanation
Correct option: A
5
Option A is correct. The problem involves a series of neutralization reactions and dilutions. By carefully tracking the equivalents of acid and base at each step, we can determine the volume of diluted acid required to neutralize the final solution, which is 5 mL.
90 Medium
90 of 90
Understanding +4 | -1
Solubility of a substance is its maximum amount that can be dissolved in a specified amount of solvent.
It depends upon

(i) nature of solute \quad (ii) nature of solvent \quad (iii) temperature \quad (iv) pressure
View answer and explanation
Correct option: D
(i), (ii), (iii) and (iv)
Option D ((i), (ii), (iii) and (iv)) is correct because the solubility of a substance depends on the nature of the solute, the nature of the solvent, the temperature, and the pressure.
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