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NEET • CHEMISTRY • PRACTICAL CHEMISTRY

Practical chemistry practice · Mixed difficulty

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31 Hard
31 of 95
Application +4 | -1
100 ml100 \mathrm{~ml} of 0.1 M0.1 \mathrm{~M} aqueous ferric alum solution is completely reduced with Iron to give Ferrous Ions. The volume of 0.1 M0.1 \mathrm{~M} acidified KMnO4\mathrm{KMnO}_4 solution required for complete reaction with ferrous Ions in the solution will be
View answer and explanation
Correct option: C
40 ml40 \mathrm{~ml}
Option C (40 ml) is correct because the ferric alum solution is reduced to ferrous ions, and then KMnO4 oxidizes the ferrous ions back to ferric ions. The stoichiometry of the reaction determines the volume of KMnO4 required.
32 Medium
32 of 95
Application +4 | -1
A hydrated salt of Na2SO3\mathrm{Na}_2 \mathrm{SO}_3 loses 22.22%22.22 \% of its mass on strong heating. The hydrated salt is:
View answer and explanation
Correct option: D
Na2SO3⋅2H2O\mathrm{Na}_2 \mathrm{SO}_3 \cdot 2 \mathrm{H}_2 \mathrm{O}
Option D is correct because the mass loss corresponds to two water molecules being removed from the hydrated salt.
33 Medium
33 of 95
Analyzing +4 | -1
A metal salt solution gives a yellow ppt with silver nitrate. The ppt. dissolves in dil. nitric acid as well as in ammonium hydroxide. The solution contains
View answer and explanation
Correct option: C
Phosphate
Option D (Chromate) is correct because silver chromate (Ag2CrO4Ag_2CrO_4) is a reddish-brown precipitate that dissolves in both dilute nitric acid and ammonium hydroxide.
34 Easy
34 of 95
Remembering +4 | -1
A salt gives violet vapours when treated with conc. H2SO4,\mathrm{H}_2 \mathrm{SO}_4, it contains
View answer and explanation
Correct option: B
I−\mathrm{I}^{-}
Option B (I−\mathrm{I}^{-}) is correct because iodide ions produce violet vapors when treated with concentrated H2SO4\mathrm{H}_2\mathrm{SO}_4.
35 Hard
35 of 95
Analyzing +4 | -1
A student is asked to determine the degree of
hydration of a salt by finding the mass of a
clean dried crucible and lid followed by the
mass of the crucible and lid containing a
sample of the salt. The crucible, lid and salt
are heated in a Bunsen burner flame, cooled,
and weighed. If the crucible, lid and salt are
heated only once instead of the recommended
three times, what will be the effect on the
degree of hydration compared with the actual
value?
View answer and explanation
Correct option: B
Too low
Option A (Too low) is correct because if the heating is incomplete, some water of hydration will remain in the salt, leading to an overestimation of the mass of the anhydrous salt and an underestimation of the water lost, thus a lower degree of hydration.
36 Easy
36 of 95
Understanding +4 | -1
Phosphorous can be estimated as
View answer and explanation
Correct option: A
Mg2P2O7M{g_2}{P_2}{O_7}
Option A (Mg2P2O7M{g_2}{P_2}{O_7}) is correct because phosphorus is quantitatively converted to magnesium ammonium phosphate, which is then ignited to magnesium pyrophosphate for gravimetric estimation.
37 Medium
37 of 95
Remembering +4 | -1
Which of the following can be used to precipitate lead salt.
View answer and explanation
Correct option: D
All
Option D (All) is correct because K2CrO4\mathrm{K}_2\mathrm{CrO}_4, KI\text{KI}, and dil. H2SO4\mathrm{H}_2\mathrm{SO}_4 can all form insoluble precipitates with lead ions.
38 Easy
38 of 95
Remembering +4 | -1
Which of the following cations is detected by the flame test?
View answer and explanation
Correct option: B
K+\mathrm{K}^{+}
Option B (K+\mathrm{K}^{+}) is correct because potassium ions impart a characteristic lilac or violet color to the flame.
39 Hard
39 of 95
Application +4 | -1
Moles of KHC2O4\mathrm{KHC}_2 \mathrm{O}_4 required to reduced 100 ml of 0.02 Molar KMnO4\mathrm{KMnO}_4 in acidic medium to Mn+2\mathrm{Mn}^{+2} is
View answer and explanation
Correct option: B
0.0050.005
Option B (0.005) is correct because the balanced equation shows that 2 moles of KMnO4 react with 5 moles of KHC2O4 in acidic medium.
40 Medium
40 of 95
Application +4 | -1
If H+(aq)+OH−(aq)→H2O(l);\mathrm{H}^{+}(a q)+\mathrm{OH}^{-}(a q) \rightarrow \mathrm{H}_2 \mathrm{O}({l}) ; ΔH=−X kJ,\Delta H=-X \mathrm{~kJ}, then heat liberated for complete neutralisation of 1 gm1 \mathrm{~gm} molecule of H2SO4\mathrm{H}_2 \mathrm{SO}_4 in aqueous solution wil be
View answer and explanation
Correct option: B
−2X kJ-2 X \mathrm{~kJ}
Option B (−2X kJ-2X \text{{ kJ}}) is correct because the neutralization of 1 mole of H2_2SO4_4 involves 2 moles of H+^+ ions reacting with 2 moles of OH−^- ions, thus releasing twice the given heat.
41 Easy
41 of 95
Remembering +4 | -1
In detection of NN and SS both in the compound by Lassaigne’s fusion test, blood red colour is due to formation of
View answer and explanation
Correct option: D
[Fe(CNS)2]2+{\left[ {Fe{{(CNS)}_2}} \right]^{2 + }}
The correct answer is D ([Fe(CNS)2]2+{\left[ {Fe{{(CNS)}_2}} \right]^{2 + }}) because the blood red color in Lassaigne's test indicates the formation of iron(III) thiocyanate complex, specifically [Fe(CNS)2]2+{\left[ {Fe{{(CNS)}_2}} \right]^{2 + }}.
42 Medium
42 of 95
Understanding +4 | -1
During the preparation of Mohr's salt solution (Ferrous ammonium sulphate), which of the following acid is added to prevent hydrolysis of Fe2+\mathrm{Fe}^{2+} ion?
View answer and explanation
Correct option: C
Dilute sulphuric acid
Option C (Dilute sulphuric acid) is correct because it prevents the hydrolysis of Fe2+\mathrm{Fe}^{2+} ions by providing H+\mathrm{H}^+ ions, shifting the equilibrium away from hydroxide formation.
43 Medium
43 of 95
Understanding +4 | -1
The best indicator for the detection of the end point in the titration of a weak acid and a strong base is
View answer and explanation
Correct option: D
Phenolphthalein (pH range 8 to 10)
Option D (Phenolphthalein (pH range 8 to 10)) is correct because the titration of a weak acid with a strong base has an equivalence point in the basic range (pH > 7), and phenolphthalein's color change occurs within this range.
44 Hard
44 of 95
Analyzing +4 | -1
The molar mass of an unknown organic liquid (M∼100)(M \sim 100) is determined by placing 5 mL5 \mathrm{~mL} of the liquid in a weighed 125−mL125-\mathrm{mL} conical flask fitted with a piece of Al{Al} foil with a pin hole in it. The flask is heated in a boiling water bath until the liquid evaporates to expel the air and fill the flask with the unknown vapor at atmospheric pressure. After cooling to room temperature the flask and its contents are reweighed. The uncertainty in which piece of apparatus causes the largest percentage error in the molar mass?
View answer and explanation
Correct option: A
Balance (±0.01 g)( \pm 0.01 \mathrm{~g})
Option A is correct because the balance has the smallest absolute uncertainty but affects the molar mass calculation directly, leading to the largest percentage error.
45 Medium
45 of 95
Understanding +4 | -1
Appearance of blood red colour, on treatment of the sodium fusion extract of an organic compound with FeSO4{FeSO}_4 in presence of concentrated H2SO4{H}_2 {SO}_4 indicates the presence of element/s
View answer and explanation
Correct option: A
N{N} and S{S}
The correct answer is A (N{N} and S{S}) because the appearance of a blood red color indicates the formation of iron thiocyanate, which requires both nitrogen and sulfur to be present in the organic compound.
46 Medium
46 of 95
Application +4 | -1
Fe(OH)3+HCl→A→K4[Fe(CN)6]C;\mathrm{Fe}(\mathrm{OH})_3+\mathrm{HCl} \rightarrow \mathrm{A} \xrightarrow{\mathrm{K}_4\left[\mathrm{Fe} (\mathrm{CN})_6\right]} \mathrm{C}; What is (C)?
View answer and explanation
Correct option: C
Fe4[Fe(CN)6]3\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3
Option C is correct because the reaction of FeCl3 with K4[Fe(CN)6] produces ferric ferrocyanide, which has the formula Fe4[Fe(CN)6]3.
47 Medium
47 of 95
Understanding +4 | -1
When water is added to a salt solution containing chloroform, chloroform layer turns violet. Salt contains
View answer and explanation
Correct option: B
I−I^-
Option B (I−I^-) is correct because iodine dissolves in chloroform to give a violet color.
48 Hard
48 of 95
Remembering +4 | -1
As2S3\mathrm{As}_2 \mathrm{S}_3 is soluble in (NH4)2S2\left(\mathrm{NH}_4\right)_2 \mathrm{S}_2 forming:
View answer and explanation
Correct option: A
(NH4)3AsS4\left(\mathrm{NH}_4\right)_3 \mathrm{AsS}_4
Option A ((NH4)3AsS4\left(\mathrm{NH}_4\right)_3 \mathrm{AsS}_4) is correct because arsenic sulfide reacts with ammonium sulfide to form ammonium thioarsenate.
49 Medium
49 of 95
Application +4 | -1
When MnO2\mathrm{MnO}_2 and H2SO4\mathrm{H}_2 \mathrm{SO}_4 is added to a salt (A)(\mathrm{A}), the greenish yellow gas liberated as salt (A)(\mathrm{A}) is:
View answer and explanation
Correct option: D
NH4Cl\mathrm{NH}_4 \mathrm{Cl}
The question is flawed. The correct answer should be a chloride salt such as NaCl or KCl. When MnO2\mathrm{MnO}_2 and H2SO4\mathrm{H}_2\mathrm{SO}_4 are added to a chloride salt, chlorine gas is liberated.
50 Medium
50 of 95
Application +4 | -1
Fe(OH)3{Fe}({OH})_3 can be separated from Al(OH)3{Al}({OH})_3 by addition of
View answer and explanation
Correct option: C
NaOH{NaOH} solution
Option C (NaOH{NaOH} solution) is correct because Al(OH)3Al(OH)_3 is amphoteric and dissolves in NaOH, while Fe(OH)3Fe(OH)_3 is not.
51 Easy
51 of 95
Remembering +4 | -1
Mercurous ion is represented as:
View answer and explanation
Correct option: A
Hg22+\mathrm{Hg}_2^{2+}
Option A (Hg22+\mathrm{Hg}_2^{2+}) is correct because mercurous ion exists as a diatomic species with a +2 charge overall.
52 Hard
52 of 95
Application +4 | -1
100 ml100 \mathrm{~ml} of 1 M KMnO41 \mathrm{~M} \mathrm{~KMnO}_4 oxidized 100 ml100 \mathrm{~ml} of H2O2\mathrm{H}_2 \mathrm{O}_2 in acidic medium. Volume of same KMnO4\mathrm{KMnO}_4 required to oxidise 100 ml H2O2100 \mathrm{~ml} \, \mathrm{H}_2 \mathrm{O}_2 in basic medium will be
View answer and explanation
Correct option: B
5003ml\frac{500}{3} \mathrm{ml}
Option B (5003ml\frac{500}{3} \mathrm{ml}) is correct because the number of electrons transferred by KMnO4 changes depending on whether the medium is acidic or basic.
53 Medium
53 of 95
Remembering +4 | -1
On passing a gas, 'XX', through Nessler's regent, a brown precipitate is obtained. The gas 'XX' is
View answer and explanation
Correct option: B
NH3{NH}_3
Option B (NH3\mathrm{NH}_3) is correct because ammonia gas reacts with Nessler's reagent to form a brown precipitate.
54 Medium
54 of 95
Understanding +4 | -1
Which of the following statements are correct?

A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.

B. Aniline can be purified by steam distillation as aniline is miscible in water.

C. Ethanol can be separated from ethanol water mixture by azeotropic distillation because it forms azeotrope.

D. An organic compound is pure, if mixed M.P. is remained same.

Choose the most appropriate answer from the options given below :
View answer and explanation
Correct option: B
A, C, D only
The correct answer is B (A, C, D only) because glycerol is purified by vacuum distillation, ethanol can be separated by azeotropic distillation, a pure organic compound has the same mixed melting point, but aniline is miscible with water and cannot be purified by steam distillation.
55 Medium
55 of 95
Remembering +4 | -1
A mixture, on heating with conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4 and MnO2\mathrm{MnO}_2, librates brown vapour of
View answer and explanation
Correct option: A
Br2\mathrm{Br}_2
Option A (Br2\mathrm{Br}_2) is correct because the reaction of a mixture with conc. H2SO4 and MnO2 liberates brown vapors of bromine.
56 Medium
56 of 95
Application +4 | -1
The pH range where the indicator shows change in colour are given as

(i) 4−9.74-9.7 \quad (ii) 7.46−10.07.46-10.0 \quad (iii) 6.5−46.5-4

Which of the above pH range represents titration of

I. Strong acid/strong base (SA/SB)\left(S_A / S_B\right)

II. Weak acid/strong base (WA/SB)\left(W_A / S_B\right)

III. Weak base/strong acid (WB/SA)\left(W_B / S_A\right)
View answer and explanation
Correct option: A
(i) →\rightarrow I, (ii) →\rightarrow II, (iii) →\rightarrow III
Option A is correct because it correctly matches the pH ranges with the respective titrations based on the strength of the acid and base involved.
57 Medium
57 of 95
Remembering +4 | -1
In qualitative test for identification of presence of phosphorous, the compound is heated with an oxidising agent. Which is further treated with nitric acid and ammonium molybdate respectively. The yellow coloured precipitate obtained is:
View answer and explanation
Correct option: C
(NH4)3PO4⋅12MoO3\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3
Option C is correct because the yellow precipitate formed in the test for phosphorus is ammonium phosphomolybdate, which has the formula (NH₄)₃PO₄ ⋅ 12MoO₃.
58 Hard
58 of 95
Analyzing +4 | -1
0.5 g0.5 \mathrm{~g} mixture of oxalic acid (H2C2O4)\left(\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4\right) and some sodium oxalate (Na2C2O4)\left(\mathrm{Na}_2 \mathrm{C}_2 \mathrm{O}_4\right) with some impurities requires 40 ml40 \mathrm{~ml} of 0.1 M NaOH0.1 \mathrm{~M} \mathrm{~NaOH} for complete neutralization and 6 ml6 \mathrm{~ml} of 0.2 M KMnO40.2 \mathrm{~M} \, \mathrm{KMnO}_4 for complete oxidation. Calculate the %\% of Na2C2O4\mathrm{Na}_2 \mathrm{C}_2 \mathrm{O}_4 in the mixture.
View answer and explanation
Correct option: B
26.8%26.8 \%
Option B (26.8 %) is correct because it involves calculating the amount of oxalic acid and sodium oxalate in the mixture using the given neutralization and oxidation data, then finding the percentage of sodium oxalate.
59 Hard
59 of 95
Application +4 | -1
One mole of anhydrous AB\mathrm{AB} dissolves in water and liberates 21.0 J mol−121.0 \mathrm{~J} \, {\mathrm{mol}^{-1}} of heat. The value of ΔH⊖(hydration)\Delta H^{\ominus}\text{(hydration)} of AB\mathrm{AB} is −29.4 J mol−1.-29.4 \mathrm{~J} \mathrm{~mol}^{-1}. The heat of dissolution of hydrated salt AB.2H2O(s)\mathrm{AB}.2 \mathrm{H}_2 \mathrm{O}(\mathrm{s}) is
View answer and explanation
Correct option: B
8.4 J mol−18.4 \mathrm{~J} \mathrm{~mol}^{-1}
Option B is correct because the heat of dissolution of the hydrated salt is calculated by subtracting the heat of hydration from the heat of dissolution of the anhydrous salt.
60 Medium
60 of 95
Remembering +4 | -1
K4[Fe(CN)6]\text{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] is not used for the detection of
View answer and explanation
Correct option: A
Fe2+\mathrm{Fe}^{2+} ions
Option A (Fe2+\mathrm{Fe}^{2+} ions) is correct because K4[Fe(CN)6]\text{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] reacts with Fe3+\mathrm{Fe}^{3+} to form Prussian blue, with Zn2+\mathrm{Zn}^{2+} to form a white precipitate, and with Cu2+\mathrm{Cu}^{2+} to form a chocolate-brown precipitate, but it does not form a distinctive precipitate with Fe2+\mathrm{Fe}^{2+}.
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