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NEET • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Hard

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Showing 61-67 of 67 questions

61 Hard

61 of 67

Remembering +4 | -1

The word neon signifies:

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Correct option: A

New

Option A (New) is correct because the word \"neon\" is derived from the Greek word \"neos,\" meaning \"new.\"

62 Hard

62 of 67

Analyzing +4 | -1

A dark brown solid (X) reacts with

N{H_3}

to form a mild explosive which decomposes to give a violet coloured gas. (X) also reacts with

{H_2}

to give an acid (Y).(Y) can also be prepared by heating its salt with

{H_3}P{O_4}

X and Y are

View answer and explanation

Correct option: D

{I_2},HI

Option D is correct because iodine reacts with ammonia to form

NI_3.NH_3

which is explosive and decomposes to give violet iodine vapor, and iodine reacts with hydrogen to form HI.

63 Hard

63 of 67

Analyzing +4 | -1

Which reaction represents the oxidizing behaviour of

{H_2}S{O_4}

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Correct option: D

2HI + {H_2}S{O_4} \to {I_2} + S{O_2} + 2{H_2}O

Option D (

2HI + {H_2}S{O_4} \to {I_2} + S{O_2} + 2{H_2}O

) is correct because

H_2SO_4

oxidizes

HI

I_2

, demonstrating its oxidizing behavior.

64 Hard

64 of 67

Remembering +4 | -1

A cold, green flame can be made by passing

C{O_2}

over warm:

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Correct option: B

White P

Option B (White P) is correct because white phosphorus reacts with carbon dioxide to produce a cold, green flame due to chemiluminescence.

65 Hard

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Understanding +4 | -1

{\mathrm{F}_2}

is formed by the reaction of

{\mathrm{K}_2}\mathrm{Mn}{\mathrm{F}_6}

with:

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Correct option: A

\mathrm{Sb}{\mathrm{F}_5}

Option A (

\mathrm{Sb}{\mathrm{F}_5}

) is correct because it acts as a fluoride ion acceptor, leading to the formation of

F_2

66 Hard

66 of 67

Understanding +4 | -1

Sulphur trioxide can be obtained by which of the following reaction:

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Correct option: D

F{e_2}{\left( {S{O_4}} \right)_3}\xrightarrow[{}]{\Delta }

Option D (

F{e_2}{\left( {S{O_4}} \right)_3}\xrightarrow[{}]{\Delta }

) is correct because the thermal decomposition of

F{e_2}{\left( {S{O_4}} \right)_3}

produces

Fe_2O_3

and

SO_3

67 Hard

67 of 67

Analyzing +4 | -1

Assertion : When a metal is treated with conc.

{HNO}_3

it generally yields a nitrate,

{NO}_2

and

{H}_2 {O}

.

Reason : Conc.

{HNO}_3

reacts with metal and first produces a metal nitrate and nascent hydrogen. The nascent hydrogen then further reduces

{HNO}_3

{NO}_2

View answer and explanation

Correct option: A

Assertion is correct, reason is correct; reason is a correct explanation for assertion.

Option A is correct because both the assertion and the reason are correct, and the reason correctly explains the assertion. Concentrated

{HNO}_3

reacts with metals to form metal nitrates,

{NO}_2

, and

{H}_2{O}

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