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NEET • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Easy

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Showing 1-30 of 88 questions
1 Easy
1 of 88
Analyzing +4 | -1
Which possesses least stable covalent P-H bond?
View answer and explanation
Correct option: D
PH6+PH_6^ +
Option D (PH6+PH_6^ +) is correct because the PH6+PH_6^+ ion is highly unstable due to the expansion of the octet and high positive charge density on the phosphorus atom, making the P-H bonds very weak.
2 Easy
2 of 88
Understanding +4 | -1
Which of the following is not an acidic oxide?
View answer and explanation
Correct option: A
NO
Option A (NO) is correct because nitric oxide (NO) is a neutral oxide, while the other options are acidic oxides that react with water to form acids.
3 Easy
3 of 88
Remembering +4 | -1
Fluorine is usually obtained from:
View answer and explanation
Correct option: A
Fluorspar
Option A is correct. Fluorspar (CaF2) is the primary source from which fluorine is usually obtained.
4 Easy
4 of 88
Understanding +4 | -1
The basic character of hydrides of V group is
View answer and explanation
Correct option: A
NH3>PH3>ASH3>SbH3N{H_3} > P{H_3} > AS{H_3} > Sb{H_3}
Option A (NH3>PH3>ASH3>SbH3N{H_3} > P{H_3} > AS{H_3} > Sb{H_3}) is correct because basicity decreases down the group due to the decrease in electronegativity and increase in bond length.
5 Easy
5 of 88
Analyzing +4 | -1
Which is planar molecule?
View answer and explanation
Correct option: B
XeF4Xe{F_4}
Option B (XeF4Xe{F_4}) is correct because it has a square planar geometry, which is planar.
6 Easy
6 of 88
Analyzing +4 | -1
Mark the wrong statement. Halogens are all coloured.
View answer and explanation
Correct option: D
The excitation energy required by the small fluorine atoms is smaller than required by the large iodine atom
Option D (The excitation energy required by the small fluorine atoms is smaller than required by the large iodine atom) is the wrong statement because smaller atoms require higher excitation energy.
7 Easy
7 of 88
Understanding +4 | -1
Oxygen is paramagnetic. The unpaired electrons are present in :
View answer and explanation
Correct option: A
Antibonding orbitals
Option A (Antibonding orbitals) is correct. Oxygen's paramagnetism arises from the presence of unpaired electrons in its antibonding molecular orbitals.
8 Easy
8 of 88
Remembering +4 | -1
A clathrate is defined as a:
View answer and explanation
Correct option: A
Cage compound
Option A (Cage compound) is correct because a clathrate is a chemical substance consisting of a lattice that traps or contains molecules.
9 Easy
9 of 88
Analyzing +4 | -1
A gas does not turn lime water milky, supports the combustion of burning magnesium. It has no smell and is colourless. It extinguishes a glowing splint but under some circumstances reacts with oxygen and hydrogen. It is not poisonous. The gas is likely to be :
View answer and explanation
Correct option: B
Nitrogen
Option B (Nitrogen) is correct because nitrogen does not turn lime water milky, supports combustion of burning magnesium, is odorless and colorless, extinguishes a glowing splint, and is not poisonous.
10 Easy
10 of 88
Understanding +4 | -1
Which factor is most responsible for the increase in boiling points of noble gases from He  to  XeHe\,\,\mathrm{to}\,\,Xe
View answer and explanation
Correct option: D
Increase in Polarisibility
Option D (Increase in Polarisibility) is correct because as the atomic size and number of electrons increase down the group, the polarizability of the noble gas atoms increases, leading to stronger London dispersion forces and higher boiling points.
11 Easy
11 of 88
Analyzing +4 | -1
In which reaction does SO2S{O_2} act as oxidizing agent?
View answer and explanation
Correct option: D
H2S{H_2}S
Option D (H2S{H_2}S) is correct because in the reaction with H2S\mathrm{H_2S}, SO2\mathrm{SO_2} oxidizes H2S\mathrm{H_2S} to sulfur, thus acting as an oxidizing agent.
12 Easy
12 of 88
Application +4 | -1
Mg on heating to redness in an atmosphere of N2{N_2} and then on treating with H2O{H_2}O gives:
View answer and explanation
Correct option: A
NH3N{H_3}
Option A (NH3N{H_3}) is correct because magnesium reacts with nitrogen at high temperatures to form magnesium nitride, which then hydrolyzes to ammonia.
13 Easy
13 of 88
Application +4 | -1
In which of the following compound central atom has +4+4 oxidation state?
View answer and explanation
Correct option: B
H2SO3\mathrm{H}_2 \mathrm{SO}_3
Option B (H2SO3\mathrm{H}_2 \mathrm{SO}_3) is correct because, in this compound, the oxidation state of sulfur is +4, calculated by considering the oxidation states of hydrogen (+1) and oxygen (-2).
14 Easy
14 of 88
Application +4 | -1
Which Cl2\mathrm{Cl}_2 gas reacts with cold and dilute sodium hydroxide solution, the oxidation number of chlorine changes from:
View answer and explanation
Correct option: D
Zero to -1 and zero to +1
Option D (Zero to -1 and zero to +1) is correct because chlorine undergoes disproportionation in cold and dilute NaOH, changing from 0 to -1 and +1.
15 Easy
15 of 88
Understanding +4 | -1
Which of the following halogen acids is least basic?
View answer and explanation
Correct option: D
HI
Option D (HI) is correct because HI is the strongest acid among the halogen acids due to the large size of the iodide ion and weak H-I bond, making it the least basic.

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16 Easy
16 of 88
Remembering +4 | -1
Major credit for the discovery of noble gases is given to:
View answer and explanation
Correct option: B
Ramsay
Option B (Ramsay) is correct because Sir William Ramsay is credited with the discovery of noble gases.
17 Easy
17 of 88
Understanding +4 | -1
Which of the following is a nitric acid anhydride
View answer and explanation
Correct option: C
N2O5{N_2}{O_5}
Option C (N2O5{N_2}{O_5}) is correct because dinitrogen pentoxide reacts with water to form nitric acid, making it the anhydride of nitric acid.
18 Easy
18 of 88
Understanding +4 | -1
PCl5\mathrm{PC}{\mathrm{l}_5} exists but NCl5\mathrm{NC}{\mathrm{l}_5} does not because:
View answer and explanation
Correct option: A
Nitrogen has no vacant 2d-orbitals
Option A (Nitrogen has no vacant 2d-orbitals) is correct because nitrogen, being a second-period element, does not have available 2d orbitals to expand its valence shell and form five bonds, unlike phosphorus.
19 Easy
19 of 88
Analyzing +4 | -1
Assertion (A) : The atomic radii of the elements of the oxygen family are smaller than the atomic radii of the corresponding elements of the nitrogen family.

Reason (R): The members of the oxygen family are more electronegative and thus have lower values of nuclear charge than those of the nitrogen family.
View answer and explanation
Correct option: C
A\mathbf{A} is true but R\mathbf{R} is false.
Option C (A\mathbf{A} is true but R\mathbf{R} is false) is correct because the atomic radii decrease across a period due to increasing effective nuclear charge, not due to lower nuclear charge.
20 Easy
20 of 88
Understanding +4 | -1
General decreasing order of stability of oxides is
View answer and explanation
Correct option: B
I >Cl> Br
Option B (I >Cl> Br) is correct because the stability of oxides generally decreases as you move up the halogen group due to decreasing bond strength.
21 Easy
21 of 88
Analyzing +4 | -1
Nitrogen dioxide and sulphur dioxide have some properties in common. Which property is shown by one of these compounds, but not by other
View answer and explanation
Correct option: B
Used as a food preservative
Option B (Used as a food preservative) is correct because only SO2SO_2 is used as a food preservative, while NO2NO_2 is not.
22 Easy
22 of 88
Application +4 | -1
Structure of XeF5+XeF_5^ + ion is
View answer and explanation
Correct option: B
Square pyramidal
Option B (Square pyramidal) is correct because XeF5+XeF_5^+ has five bonding pairs and one lone pair, resulting in a square pyramidal geometry.
23 Easy
23 of 88
Understanding +4 | -1
Which is the correct thermal stability order
View answer and explanation
Correct option: D
H2PO<H2Te<H2Se<H2S<H2O{H_2}PO < {H_2}Te < {H_2}Se < {H_2}S < {H_2}O
Option D (H2PO<H2Te<H2Se<H2S<H2O{H_2}PO < {H_2}Te < {H_2}Se < {H_2}S < {H_2}O) is correct because thermal stability decreases down the group due to decreasing bond dissociation energy, with water being an exception due to strong hydrogen bonding.
24 Easy
24 of 88
Application +4 | -1
How many lone pairs are associated with xenon atom in XeF2,  SeF4    and    XeF6\mathrm{Xe}{\mathrm{F}_2},\mathrm{\;Se}{\mathrm{F}_4}\mathrm{\;}\,\,\mathrm{and\;}\,\,\mathrm{Xe}{\mathrm{F}_6} respectively?
View answer and explanation
Correct option: C
3, 2 and 1
Option C (3, 2 and 1) is correct because XeF2XeF_2 has 3 lone pairs, SeF4SeF_4 has 1 lone pair, and XeF6XeF_6 has 1 lone pair.
25 Easy
25 of 88
Remembering +4 | -1
Uranium isotopes are usually separated by using compounds of the halogen:
View answer and explanation
Correct option: A
F2{\mathrm{F}_2}
Option A is correct. Uranium isotopes are usually separated by using compounds of Fluorine (F2) due to the volatility of UF6.
26 Easy
26 of 88
Analyzing +4 | -1
Assertion (A) : SO2\mathrm{SO}_2 from oxidation of sulphur or H2 S\mathrm{H}_2 \mathrm{~S} contains sulphur and oxygen in the mass ratio of 1:21: 2.

Reason (R) : Different samples of a pure chemical substance always contain the same proportions of elements by mass.
View answer and explanation
Correct option: D
A\mathbf{A} is false but R\mathbf{R} is true.
Option D (A\mathbf{A} is false but R\mathbf{R} is true.) is correct because the mass ratio of S:O in SO2 is not 1:2, but the law of definite proportions (Reason R) is always true.
27 Easy
27 of 88
Understanding +4 | -1
Which of the following oxides is most acidic
View answer and explanation
Correct option: C
N2O5{N_2}{O_5}
Option C (N2O5{N_2}{O_5}) is correct because, in general, for oxides of elements in the same group, acidity increases with increasing oxidation state and electronegativity. Nitrogen is more electronegative than As, P, and Sb, and N2O5N_2O_5 has a high oxidation state for N.
28 Easy
28 of 88
Application +4 | -1
Oxidation state of phosphorous in hypophosphorous acid is
View answer and explanation
Correct option: B
+1+1
Option B (+1) is correct because the oxidation state of phosphorus in hypophosphorous acid (H3PO2H_3PO_2) is +1.
29 Easy
29 of 88
Remembering +4 | -1
In fisher-Ringe’s method of separation of noble gas mixture from air, ………. Is used.
View answer and explanation
Correct option: A
90%CaC2+10% CaCl290\% \mathrm{ Ca}{\mathrm{C}_\mathrm{2}} + 10\% \,\mathrm{CaC}{\mathrm{l}_\mathrm{2}}
Option A (90%CaC2+10% CaCl290\% \mathrm{ Ca}{\mathrm{C}_{\mathrm{2}}} + 10\% \,\mathrm{CaC}{\mathrm{l}_{\mathrm{2}}}) is correct because this mixture is used in the Fisher-Ringe method to absorb nitrogen from air, allowing noble gases to be separated.
30 Easy
30 of 88
Remembering +4 | -1
The product obtained as a result of a reaction of nitrogen with CaC2 Ca{C_2}\, is:
View answer and explanation
Correct option: A
Ca(CN)2\mathrm{Ca(CN}{\mathrm{)}_\mathrm{2}}
Option A is correct. The reaction of nitrogen with calcium carbide (CaC2) produces calcium cyanamide, which has the formula Ca(CN)2.
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